Physics for Scientists and Engineers
10th Edition
ISBN: 9781337553278
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 26, Problem 15P
To determine
The electrical conductivity of the earth’s atmosphere.
Expert Solution & Answer
Trending nowThis is a popular solution!
Students have asked these similar questions
A current density of 6.00 x 10-13 A/m2 exists in the atmosphere at a location where the electric field is 100 V/m. Calculate the electrical conductivity of the Earth’s atmosphere in this region.
A current density of 6.00 A/m2 exists in the atmosphere at a location where the electric field is 100 V/m.Calculate the electrical conductivity of the Earth’s atmospherein this region.
Earth's lower atmosphere contains negative and positive ions that are produced by radioactive elements in the soil and cosmic rays
from space. In a certain region, the atmospheric electric field strength is 174 V/m and the field is directed vertically down. This field
causes singly charged positive ions, at a density of 868 cm³, to drift downward and singly charged negative ions, at a density of 624
cm3, to drift upward (see the figure). The measured conductivity of the air in that region is 3.45 x 10-14 (0-m)-¹. Calculate (a) the
magnitude of the current density and (b) the ion drift speed, assumed to be the same for positive and negative ions.
(a) Number i
(b) Number
Units
Units
Chapter 26 Solutions
Physics for Scientists and Engineers
Ch. 26.1 - Consider positive and negative charges of equal...Ch. 26.2 - Prob. 26.2QQCh. 26.2 - Prob. 26.3QQCh. 26.4 - When does an incandescent lightbulb carry more...Ch. 26 - Prob. 1PCh. 26 - A small sphere that carries a charge q is whirled...Ch. 26 - In the Bohr model of the hydrogen atom (which will...Ch. 26 - Prob. 4PCh. 26 - Prob. 5PCh. 26 - Figure P26.6 represents a section of a conductor...
Ch. 26 - The quantity of charge q (in coulombs) that has...Ch. 26 - A Van de Graaff generator (see Problem 24)...Ch. 26 - An electric current in a conductor varies with...Ch. 26 - Prob. 10PCh. 26 - An electric heater carries a current of 13.5 A...Ch. 26 - You are working at a company that manufactures...Ch. 26 - Prob. 13PCh. 26 - Prob. 14PCh. 26 - Prob. 15PCh. 26 - Prob. 16PCh. 26 - Prob. 17PCh. 26 - Prob. 18PCh. 26 - An aluminum wire with a diameter of 0.100 mm has a...Ch. 26 - Plethysmographs are devices used for measuring...Ch. 26 - At what temperature will aluminum have a...Ch. 26 - You are working in a laboratory that studies the...Ch. 26 - Assume that global lightning on the Earth...Ch. 26 - The Van de Graaff generator, diagrammed in Figure...Ch. 26 - A 100-W lightbulb connected to a 120-V source...Ch. 26 - The potential difference across a resting neuron...Ch. 26 - The cost of energy delivered to residences by...Ch. 26 - Residential building codes typically require the...Ch. 26 - Assuming the cost of energy from the electric...Ch. 26 - An 11.0-W energy-efficient fluorescent lightbulb...Ch. 26 - A 500-W heating coil designed to operate from 110...Ch. 26 - Why is the following situation impossible? A...Ch. 26 - Make an order-of-magnitude estimate of the cost of...Ch. 26 - Lightbulb A is marked 25 W 120 V, and lightbulb B...Ch. 26 - One wire in a high-voltage transmission line...Ch. 26 - You are working with an oceanographer who is...Ch. 26 - A charge Q is placed on a capacitor of capacitance...Ch. 26 - An experiment is conducted to measure the...Ch. 26 - Prob. 39APCh. 26 - Prob. 40APCh. 26 - Review. An office worker uses an immersion heater...Ch. 26 - The strain in a wire can be monitored and computed...Ch. 26 - A close analogy exists between the flow of energy...Ch. 26 - The dielectric material between the plates of a...Ch. 26 - Review. A parallel-plate capacitor consists of...Ch. 26 - Prob. 46APCh. 26 - Why is the following situation impossible? An...Ch. 26 - Prob. 48CPCh. 26 - A spherical shell with inner radius ra and outer...Ch. 26 - Material with uniform resistivity is formed into...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- An aluminum wire 1.628 mm in diameter (14-gauge) carries a current of 3.00 amps, (a) What is the absolute value of the charge density in the wire? (b) What is the drift velocity of the electrons? (c) What would be the drift velocity if the same gauge copper were used instead of aluminum? The density of copper is 8.96 g/cm3 and thedensity of aluminum is 2.70 g/cm3. The molar mass ofaluminum is 26.98 g/mol and the molar mass of copper is 63.5 g/mol. Assume each atom of metal contributes one free electron.arrow_forwardTaking R = 1.00 k and = 250 V in Figure P21.49, determine the direction and magnitude of the current in the horizontal wire between a and e. Figure P21.49arrow_forwardEarth’s lower atmosphere contains negative and positive ions that are produced by radioactive elements in the soil and cosmic rays from space. In a certain region, the atmospheric electric field strength is 120 V/m and the field is directed vertically down.This field causes singly charged positive ions, at a density of 620 cm3, to drift downward and singly charged negative ions, at a density of 550 cm3, to drift upward. The measured conductivity of the air in that region is 2.70 * 10-14 (ohmm)-1. Calculate (a) the magnitude of the current density and (b) the ion drift speed, assumed to be the same for positive and negative ions.arrow_forward
- The earth’s surface has a negative surface charge density of 10-9 C m-2. The potential difference of 400 kV between the top of the atmosphere and the surface results (due to the low conductivity of the lower atmosphere) in a current of only 1800 A over the entire globe. If there were no mechanism of sustaining atmospheric electric field, how much time (roughly) would be required to neutralise the earth’s surface? (This never happens in practice because there is a mechanism to replenish electric charges, namely the continual thunderstorms and lightning in different parts of the globe). (Radius of earth = 6.37 × 106 m.)arrow_forwardSilver wire has a cross-sectional area A = 2.0 mm2. A total of 9.4 x 10 electrons pass through the wire in 3.0 s. The conduction electron density in silver is 5.8 x 1028 electrons/m. What is the drift velocity of these electrons?arrow_forwardSuppose that there is a wire. It is made out of material that has a the following information: temperature coefficient = 0.005/°C cross sectional area = 4.51x10-6 m² length: 1.00 m free electron density = 8.49 x 1028 electrons/m³ The wire is at temperature 20°C and it carries a current of 5 A when connected to a 35 V battery. Find the (1) drift speed of the electrons and (2) resistivity at 50°C.arrow_forward
- Gr 11 level No calculusarrow_forwardSuppose that there is a wire. It is made out of material that has a the following information: temperature coefficient=0.005/°C cross sectional area: 4.51x10-6 m² length: 1.00 m fee electron density of 8.49 x 1028 electrons/m³ The wire is at temperature 20°C and it carries a current of 5 A when connected to a 35 V battery. Find the (1) drift speed of the electrons and (2) resistivity at 50°C.arrow_forwardA conductor has a cross-sectional area of 2.3x106 m² and the number of free electrons per unit volume is 8.5 X1028 electron/m³. When the current is 7.1 A, find the drift speed (in mm/s) of the electrons. Use the charge of the electron to be 1.6×1019 c.arrow_forward
- An aluminum "12 gauge" wire has a diameter d of 0.205 centimeters. The resistivity ρ of aluminum is 2.75×10−8 ohm-meters. The electric field in the wire changes with time as E(t)=0.0004t2−0.0001t+0.0004 newtons per coulomb, where time is measured in seconds. Find the charge Q passing through a cross-section of the conductor between time 0 seconds and time 5 seconds. Express your answer in coulombs to two significant figures.arrow_forwardA typical lightning bolt may last for 0.197s and transfer 1.19 ✕ 1020 electrons. Calculate the average current (in A) in the lightning bolt.arrow_forwardA voltage ΔV is applied across the ends of a Nichrome heater wire having a cross-sectional area A and length L. The same voltage is applied across the ends of a second Nichrome heater wire having a cross-sectional area A and length 2L. Which wire gets hotter?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage Learning
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Physics for Scientists and Engineers: Foundations...
Physics
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Cengage Learning