Organic Chemistry
Organic Chemistry
12th Edition
ISBN: 9781118875766
Author: T. W. Graham Solomons, Craig B. Fryhle, Scott A. Snyder
Publisher: WILEY
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Chapter 25, Problem 8PP
Interpretation Introduction

Interpretation:

The intermediate formed during the conversion of adenine to hypoxanthine, hydrogen bonds of hypoxanthine-cytosine base pair and the consequences it would have through two rounds of DNA (deoxyribonucleic acid) replication is to be shown.

Concept Introduction:

▸ Normally, in DNA, adenine pairs with thymine by forming two hydrogen bonds. On treatment with nitrous acid, amino group of adenine undergoes changes to form diazonium and finally gets removed.

▸ Hypoxanthine forms two hydrogen bonds with cytosine instead of thymine. This mispairing then passes on to the daughter DNA formed during replication and further brings about permanent changes (mutations).

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Students have asked these similar questions
1. How does real-time polymerase chain reaction work? 2. What does the melting point represent?
Which statement best explains the chemical differencesbetween DNA and RNA? (a) DNA has two different sugarsin its sugar–phosphate backbone, but RNA only has one.(b) Thymine is one of the DNA bases, whereas RNA’s correspondingbase is thymine minus a methyl group. (c) TheRNA sugar–phosphate backbone contains fewer oxygenatoms than DNA’s backbone. (d) DNA forms double helicesbut RNA cannot.
During base excision repair, DNA glycosylase cleaves theN-glycosidic link between the altered base and the deoxyribose component of the nucleotide. Draw a typical nucleotideand indicate which bond is cleaved.
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