Essential University Physics (3rd Edition)
Essential University Physics (3rd Edition)
3rd Edition
ISBN: 9780134202709
Author: Richard Wolfson
Publisher: PEARSON
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Chapter 25, Problem 78P

A parallel-plate capacitor has plates of area 10cm2 separated by a 0.10-nun layer of glass insulation with resistivity ρ = 1.2 × 1013 Ω·m and dielectric constant κ = 5.6. Because of the finite resistivity, charge leaks through the insulation, (a) How can such a leaky capacitor be represented in a circuit diagram? (b) Find the time constant for this capacitor to discharge through its insulation, and show that it depends only on the properties of the insulating material and not on its dimensions.

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A parallel-plate capacitor of plate area 6.7 cm2 and plate separation 4.7 cm has a dielectric constant of 2.5. The capacitor is put in series with a 9.5 k2 resistor and a battery of EMF 6 V, and allowed to fully charge. a) Determine the time constant of the circuit. b) Show that the SI base unit of the time constant of the circuit is seconds. Ensure you include any relevant equations and/or definitions in your working. (c) What is the initial current in the circuit, in mA, when charging begins? d) What is the final charge on the capacitor once it is fully energised? (e) The potential difference, V, across the capacitor, at a time t after charging begins is given ay V = VMAX[1 – e where VMAX is the final potential difference across the capacitor once charging is complete and T is the time constant of the circuit. Show that the potential difference across the capacitor is equal to 50% of its maximum, 2.08 ns after charging begins.
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Chapter 25 Solutions

Essential University Physics (3rd Edition)

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