Introduction to Electrodynamics
Introduction to Electrodynamics
4th Edition
ISBN: 9781108420419
Author: David J. Griffiths
Publisher: Cambridge University Press
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Chapter 2.5, Problem 2.42P
To determine

To Find: The force of repulsion between the “northern” hemisphere and the “southern” hemisphere.

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It is 15 km from downtown bozeman, Montana, to the Ridge, atop the Bridger bowl Ski area. If 1 C positive charge is placed on the top the ridge and a 1C positive charge is place atop the Baxter hotel in downtown Bozeman, what will be the force of repulsion between the two charges?
You break a piece of Styrofoam packing material, and it releases lots of little spheres whose electric charge makes them stick an-noyingly to you. If two of the spheres carry equal charges and repel with a force of 21 mN when they’re 15 mm apart, what’s the magnitude of the charge on each?
Macmillan Learning Consider a parallel universe where the laws of nature are different, and aqueous solutions can have an excess charge. Two beakers are separated 6.90 m and each contains 0.350 L of an aqueous solution of 3.10 x 10-6 M excess charge. One beaker has a net positive charge, and one beaker has a net negative charge. Calculate the force between the beakers using the formula F= 1 9192 4xco ² where F is force, co is the permittivity constant and is equal to 8.85 x 10-12 C2/(N m²), q, is the charge contained in the first beaker, q2 is the charge contained in the second beaker, and r is the distance between the beakers. Note that I mole of charge is 96485 C. Because one of the beakers contains a net negative charge, one q will be negative, and F will be negative. A negative F corresponds to an attractive force. F= -1.63 x106 Incorrect N

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Introduction to Electrodynamics

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