Concept explainers
(a)
Interpretation:
Given reaction has to be completed representing the mass number and
Concept Introduction: In this radioactive decay process the unstable isotopes loses their energy by emitting radiation. It is converted to stable isotopes. The emitting radiations are positron emission, gamma emission, beta emission and electron capture.
Mass number is the sum of neutron and protons.
Atomic number is the number of protons.
In alpha decay, there will be lose of
In beta decay, there will be a lose of electron from nucleus (neutron turns into proton): there will be no change in mass number and atomic number increases by one.
(a)
Answer to Problem 21PS
Explanation of Solution
The radioactive isotope of iron-54 when irradiated with alpha particle forms
(b)
Interpretation:
Given reaction has to be completed representing the mass number and atomic number.
Introduction: In this radioactive decay process the unstable isotopes loses their energy by emitting radiation. It is converted to stable isotopes. The emitting radiations are positron emission, gamma emission, beta emission and electron capture.
Mass number is the sum of neutron and protons.
Atomic number is the number of protons.
In alpha decay, there will be lose of
In beta decay, there will be a lose of electron from nucleus (neutron turns into proton): there will be no change in mass number and atomic number increases by one.
(b)
Answer to Problem 21PS
Explanation of Solution
The radioactive isotope of Aluminium-27 when irradiated with alpha particle forms
(c)
Interpretation:
Given reaction has to be completed representing the mass number and atomic number.
Introduction: In this radioactive decay process the unstable isotopes loses their energy by emitting radiation. It is converted to stable isotopes. The emitting radiations are positron emission, gamma emission, beta emission and electron capture.
Mass number is the sum of neutron and protons.
Atomic number is the number of protons.
In alpha decay, there will be lose of
In beta decay, there will be a lose of electron from nucleus (neutron turns into proton): there will be no change in mass number and atomic number increases by one.
(c)
Answer to Problem 21PS
Explanation of Solution
The radioactive isotope of Sulphur-32 is irradiated with neutron forms
(d)
Interpretation:
Given reaction has to be completed representing the mass number and atomic number.
Introduction: In this radioactive decay process the unstable isotopes loses their energy by emitting radiation. It is converted to stable isotopes. The emitting radiations are positron emission, gamma emission, beta emission and electron capture.
Mass number is the sum of neutron and protons.
Atomic number is the number of protons.
In alpha decay, there will be lose of
In beta decay, there will be a lose of electron from nucleus (neutron turns into proton): there will be no change in mass number and atomic number increases by one.
(d)
Answer to Problem 21PS
Explanation of Solution
The radioactive isotope of
(e)
Interpretation:
Given reaction has to be completed representing the mass number and atomic number.
Introduction: In this radioactive decay process the unstable isotopes loses their energy by emitting radiation. It is converted to stable isotopes. The emitting radiations are positron emission, gamma emission, beta emission and electron capture.
Mass number is the sum of neutron and protons.
Atomic number is the number of protons.
In alpha decay, there will be lose of
In beta decay, there will be a lose of electron from nucleus (neutron turns into proton): there will be no change in mass number and atomic number increases by one.
(e)
Answer to Problem 21PS
Explanation of Solution
The radioactive isotope of
(f)
Interpretation:
Given reaction has to be completed representing the mass number and atomic number.
Introduction: In this radioactive decay process the unstable isotopes loses their energy by emitting radiation. It is converted to stable isotopes. The emitting radiations are positron emission, gamma emission, beta emission and electron capture.
Mass number is the sum of neutron and protons.
Atomic number is the number of protons.
In alpha decay, there will be lose of
In beta decay, there will be a lose of electron from nucleus (neutron turns into proton): there will be no change in mass number and atomic number increases by one.
(f)
Answer to Problem 21PS
Explanation of Solution
The radioactive isotope of
Want to see more full solutions like this?
Chapter 25 Solutions
Chemistry & Chemical Reactivity
- Chemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningChemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningWorld of Chemistry, 3rd editionChemistryISBN:9781133109655Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCostePublisher:Brooks / Cole / Cengage Learning
- Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningChemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage LearningIntroductory Chemistry: A FoundationChemistryISBN:9781337399425Author:Steven S. Zumdahl, Donald J. DeCostePublisher:Cengage Learning