Concept explainers
Figure 24-56a shows an electron moving along an electric dipole axis toward the negative side of the dipole. The dipole is fixed in place. The electron was initially very far from the dipole, with kinetic energy 100 eV. Figure 24-56b gives the kinetic energy K of the electron versus its distance r from the dipole center. The scale of the horizontal axis is set by rs = 0.10 m. What is the magnitude of the dipole moment?
Figure 24-56 Problem 52.
Want to see the full answer?
Check out a sample textbook solutionChapter 24 Solutions
Fundamentals of Physics Extended
Additional Science Textbook Solutions
College Physics: A Strategic Approach (3rd Edition)
Biology: Life on Earth with Physiology (11th Edition)
General, Organic, and Biological Chemistry: Structures of Life (5th Edition)
Laboratory Experiments in Microbiology (12th Edition) (What's New in Microbiology)
Physics for Scientists and Engineers: A Strategic Approach, Vol. 1 (Chs 1-21) (4th Edition)
Fundamentals Of Thermodynamics
- A water molecule is made up of two hydrogen atoms and one oxygen atom, with a total of 10 electrons and 10 protons. The molecule is modeled as a dipole with an effective separation d = 3.9 1012 m between its positive and negative charges. What is the magnitude of the water molecules dipole moment?arrow_forwardA uniformly charged ring of radius R = 25.0 cm carrying a total charge of 15.0 C is placed at the origin and oriented in the yz plane (Fig. P24.54). A 2.00-g particle with charge q = 1.25 C, initially at the origin, is nudged a small distance x along the x axis and released from rest. The particle is confined to move only in the x direction. a. Show that the particle executes simple harmonic motion about the origin. b. What is the frequency of oscillation for the particle? Figure P24.54arrow_forwardFour charged particles are at rest at the corners of a square (Fig. P26.14). The net charges are q1 = q2 = +2.65 C and q3 = q4 = 5.15 C. The distance between particle 1 and particle 3 is r13 = 1.75 cm. a. What is the electric potential energy of the four-particle system? b. If the particles are released from rest, what will happen to the system? In particular, what will happen to the systems kinetic energy?arrow_forward
- A particle with charge q on the negative x axis and a second particle with charge 2q on the positive x axis are each a distance d from the origin. Where should a third particle with charge 3q be placed so that the magnitude of the electric field at the origin is zero?arrow_forwardFour charged particles are at rest at the corners of a square (Fig. P26.14). The net charges are q1 = q2 = 2.65 C and q3 = q4 = 5.15 C. The distance between particle 1 and particle 3 is r13 = 1.75 cm. a. What is the electric potential energy of the four-particle system? b. If the particles are released from rest, what will happen to the system? In particular, what will happen to the systems kinetic energy as their separations become infinite? FIGURE P26.14 Problems 14, 15, and 16.arrow_forwardFind an expression for the magnitude of the electric field at point A mid-way between the two rings of radius R shown in Figure P24.30. The ring on the left has a uniform charge q1 and the ring on the right has a uniform charge q2. The rings are separated by distance d. Assume the positive x axis points to the right, through the center of the rings. FIGURE P24.30 Problems 30 and 31.arrow_forward
- The dipole moment of the water molecule (H,O) is 6.17 x 10-30 C.m. Consider a water molecule located at the origin whose dipole moment p points in the positive x direction. A chlorine ion (CI x = 3.00 x 10-9 meters. Assume that this x value is much larger than the separation d between the charges in the dipole, so that the approximate expression for the electric field along the dipole axis can be used. Part A of charge -1.60 x 10-19 C, is located at Find the magnitude of the electric force, ignoring the sign, that the water molecule exerts on the chlorine ion. • View Available Hint(s) 6.57 • 1012 Narrow_forwardV+ 2d d P L' V. A particle of charge +q and mass m is ejected from the point P with the initial velocity i = 20î + 10f(), traveling in a parabolic orbit with a maximum height d = 2cm in the uniform electric field and hitting the point Q at a distance of L = 10cm. Since the distance between the plates is 2d and the potential difference is 1000V, find the ratio of the particle's charge to its mass (q/m). (Ignore the gravitational force). a) 16. 10-2 () kg b) 48. 10-2 (C kg c) 96. 10-2 (C kg d) 160. 10-2 ( kg e) 240. 10-2 kg.arrow_forwardAn electric dipole consists of two charges q=+2e and q--2e (e 1.6x10 C). separated by a distance d =10m. The electric charges are placed along the y-axis as shown in figure. (3i + 3f)N/C is applied. Suppose a constant external electric field Et (a) What is the magnitude and direction of the dipole moment? (b) What is the magnitude and direction of the torque on the dipole?arrow_forward
- An electron starts from rest 2.81 cm from the center of a uniformly charged sphere of radius 2.08 cm. If the sphere carries a total charge of 1.13×10-⁹ C, how fast will the electron be moving when it reaches the surface of the sphere? 300 m/s Submit Answer Incorrect.arrow_forwardV+ 1 2d d P + L' Q v. A particle of charge +q and mass m is ejected from the point P with the initial velocity i = 50i + 405(), traveling in a parabolic orbit with a maximum height 2cm in the uni form electric field and hitting the point Q at a distance of L = 10cm. Since the distance between the plates is 2d and the potential difference is 1000V, find the ratio of the particle's charge to its mass (q/m). (Ignore the gravitational force). d = a) 16. 10-2 kg b) 48. 10-2 kg c) 96. 10-2 ( kg d) 160. 10-2 C kg e) 240. 10-2 ()arrow_forwardIn the figure a uniform, upward electric field of magnitude 1.60 × 103 N/C has been set up between two horizontal plates by charging the lower plate positively and the upper plate negatively. The plates have length L = 17.0 cm and separation d = 1.70 cm. An electron is then shot between the plates from the left edge of the lower plate. The initial velocity of the electron makes an angle 0 = 45.0° with the lower plate and has a magnitude of 6.40 × 105 m/s. (a) Will the electron strike one of the plates? (b) If so, which plate, top or bottom? (c) How far horizontally from the left edge will the electron strike? ↑E 5%8 (a) (b) (c) Number Mr Units <arrow_forward
- Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage LearningPhysics for Scientists and Engineers with Modern ...PhysicsISBN:9781337553292Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPrinciples of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
- Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningCollege PhysicsPhysicsISBN:9781285737027Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning