Explanation Figure 1 represent the incidence of unpolarised light incident on the left disk with an intensity of I max and leaving the plate with an intensity of I . Write the intensity of transmitted light from the first plate. I = 1 2 I max (I) Here, I is the intensity of the light transmitted light from the first plate, and I max is the intensity of light incident on the first plate. Write the intensity of transmitted light from the second plate. I = 1 2 I max cos 2 θ (II) Here, I is the intensity of the light transmitted light from the second plate, and I max is the intensity of light incident on the first plate. Write the intensity of transmitted light from the third plate. I = 1 2 I max cos 2 θ cos 2 ( 90 ° − θ ) (III) Here, I is the intensity of the light transmitted light from the third plate, and I max is the intensity of light incident on the first plate. From trigonometric identities cos 2 θ is expressed as 1 2 ( 1 + cos2 θ ) , and cos 2 ( 90 ° − θ ) is equivalent to sin 2 θ which is expressed as 1 2 ( 1 − cos 2 θ )

Principles of Physics: A Calculus-Based Text

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ISBN: 9781133104261

Author: Raymond A. Serway, John W. Jewett

Publisher: Cengage Learning

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Chapter 24, Problem 46P

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To show that the intensity of light emerging from the right disk is I=116Imax(1−cos4ωt).

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Chapter 24, Problem 45P

Chapter 24, Problem 47P

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Principles of Physics: A Calculus-Based Text

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To show that the intensity of light emerging from the right disk is I = 1 16 I max ( 1 − cos 4 ω t ) .

Solution Summary: The author shows the intensity of light emerging from the right disk as I=116I_max(1-mathrmcos4omega

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To show that the intensity of light emerging from the right disk is I=116Imax(1−cos4ωt).

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Chapter 24 Solutions