Biochemistry
9th Edition
ISBN: 9781319114671
Author: Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher: W. H. Freeman
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Question
Chapter 24, Problem 27P
Interpretation Introduction
Interpretation:
Feedback mechanism for the given pathways, such that, Y and Z production is the same.
Concept introduction:
A feedback inhibition is a process in which the product of any reaction acts as the regulator of the reaction itself. By this, the production of the product gets limited. In this mechanism, the product binds to the allosteric site of the enzyme, and changes the shape of the active enzyme, resulting in loss of activity of the enzyme.
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Hi, help please. Discuss each method of regulating phosphofructokinase below as indicated by the circle. Discuss 1.) The type of regulation occurring, 2.) What compound or condition performs the regulation, 3.) How/why it influences the enzyme activity.
1F. Please help me in detail. for molecular Mechanism of ATP versus GTP selectivity of adenylate kinase, Draw a reaction scheme that includes both the substrate and the inhibitor under study here. Be sure to label KI, Ks, kp
I. Active site analysis.
Below is a diagram of a putative active site for Monoamine oxidase. As we learned, the purpose of
tertiary structure is to form a scaffold so you can orient just a few amino acids in the right orientation
to promote binding and/or catalysis. The position where this occurs is the active site. The amino acid
architecture of an active site is designed to bind substrates. Amino acid side chains are capable of
hydrogen bonding, ionic and hydrophobic interactions. Fill in each amino acid that you think is
suitable for interacting with the part of the substrate it is closest to. Assume the pH will be at 7.0
a.a.#1
a.a.#2
a.a.#6
HO
Lond
NH₂
НО
a.a.#5
OH
a.a.#3
a.a.#4
Chapter 24 Solutions
Biochemistry
Ch. 24 - Prob. 1PCh. 24 - Prob. 2PCh. 24 - Prob. 3PCh. 24 - Prob. 4PCh. 24 - Prob. 5PCh. 24 - Prob. 6PCh. 24 - Prob. 7PCh. 24 - Prob. 8PCh. 24 - Prob. 9PCh. 24 - Prob. 10P
Ch. 24 - Prob. 11PCh. 24 - Prob. 12PCh. 24 - Prob. 13PCh. 24 - Prob. 14PCh. 24 - Prob. 15PCh. 24 - Prob. 16PCh. 24 - Prob. 17PCh. 24 - Prob. 18PCh. 24 - Prob. 19PCh. 24 - Prob. 20PCh. 24 - Prob. 21PCh. 24 - Prob. 22PCh. 24 - Prob. 23PCh. 24 - Prob. 24PCh. 24 - Prob. 25PCh. 24 - Prob. 26PCh. 24 - Prob. 27PCh. 24 - Prob. 28PCh. 24 - Prob. 29PCh. 24 - Prob. 30PCh. 24 - Prob. 31PCh. 24 - Prob. 32PCh. 24 - Prob. 33PCh. 24 - Prob. 34PCh. 24 - Prob. 35PCh. 24 - Prob. 36PCh. 24 - Prob. 37PCh. 24 - Prob. 38PCh. 24 - Prob. 39PCh. 24 - Prob. 40P
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- Show solutions. Thanks.arrow_forward1B. please help me in detail. Draw a graph of free energy G (y-axis) vs reaction progress (x-axis) that illustrates what the kinase is doing in terms of the free energy by showing (i) the substrate (also label what the substrate is [it’s name]), (ii) the products (also give the name of the products), (iii) draw and label the uncatalyzed and catalyzed reactions, and be sure that the parts of the graph are properly labeled..arrow_forwardSelect all that apply. What is true about the conformational aspects of coupling? O The proton gradient is involved in the release of bound ATP from the synthase as a result of conformational change. O The conformational states interconvert as a result of proton flux through the synthase. There are two sites for substrate on the synthase and two possible conformational states: open (0) and tight-binding (T). Dinitrophenol binds to and inhibits ATP synthase conformational changes, thus inhibiting ATP synthesis. The Fo portion of ATP synthase acts as a rotary motor.arrow_forward
- Draw TCA Cycle. Please make sure to state all the enzymes and co-factors for each step of the pathway.arrow_forwardPlesae ASAP. thanku Which of the following is not true about the glutamate family of ligand-gated ion channels? a. members are AMPA, kinase, and NMDA channels b. they are cation permable c. channels subunits have 3 full transmembrane doamins d. they require 5 subunits to amke a functional channelarrow_forwardInducers and Inhibitors of AEP. Short peptides such as legumain stabilization and activity modulation (LSAM) domain and αvβ3 integrin could enhance the activity of AEP. LSAM domain known as the prodomain of AEP blocks substrate binding before activation. This prodomain has a helical structure and two independent peptides. One is an activation peptide (AP, K287 to N323), and the other is a LSAM domain. LSAM domain remains even after AP is cleaved and released from protease at neutral pH via electrostatic interaction. AEP without LSAM domain has a lower melting temperature than AEP with LSAM domain [77, 117]. Another short peptide, αvβ3 integrin, can directly interact with AEP, and after forming a complex, the optimal pH for AEP activity is increased from 5.5 to 6.0. It indicates that αvβ3 binding could induce conformational stabilization of AEP accompanied by deprotonated C189. αvβ3 does not directly interact with the AEP active site; however, AEP docks to the αvβ3 RGD-binding site…arrow_forward
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