(a)
Interpretation: The
Concept Introduction:The electrode potential of the cell is defined as the potential of cell consisting of two electrodes. Therefore at anode the oxidation occurs and at cathode reduction occurs.
(a)
Answer to Problem 24.1QAP
The thermodynamic potential of the cell is
Explanation of Solution
The solution is
The expression for electrode potential is:
Here, standard electrode potential is
The electrode potential of the cell is equal to the difference between electrode potential of cathode and electrode potential of anode.
Here, the electrode potential of cathode is
The overall reaction is:
Write the reaction at cathode.
The reaction at anode is:
The expression for the electrode potential of cathode is:
The expression for the electrode potential of anode is:
Substitute
Substitute
Substitute
Therefore, the thermodynamic potential of the cell is
(b)
Interpretation:The
Concept Introduction:The current is directly proportional to voltage.
(b)
Answer to Problem 24.1QAP
The
Explanation of Solution
The oxygen is evolved at pressure of
The expression for
Here, voltage of cell is
Substitute
Therefore, the
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Chapter 24 Solutions
Principles of Instrumental Analysis
- Halide ions can he deposited at a silver anode, the reaction being Ag(s) + X- AgX(s) +e- Suppose that a cell was formed by immersing a silver anode in an analyte solution that was 0.0250 M Cl-,Br-, and I -ions and connecting the half-cell to a saturated calomel cathode via a salt bridge. (a) Which halide would form first and at what potential? Is the cell galvanic or electrolytic? (b) Could I- and Br- be separated quantitatively? (Take 1.00 l0-5 M as the criterion for quantitative removal of an ion.) If a separation is feasible, what range of cell potential could he used? (c) Repeat part (b) for I- and Cl-. (d) Repeat part (b) for Br- and Cl-.arrow_forwardAn alloy made up of tin and copper is prepared by simultaneously electroplating the two metals from a solution containing Sn(NO3)2 and Cu(NO3)2.If 20.0% of the total current is used to plate tin, while 80.0% is used to plate copper, what is the percent composition of the alloy?arrow_forwardThe following cell was found to have a potential of —0.492 V: Ag|AgCl(sat’d)||HA(0.200 M),NaA(0.300 M)|H2(1.00 atm),Pt Calculate the dissociation constant of HA, neglecting the junction potential.arrow_forward
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