Prescott's Microbiology
Prescott's Microbiology
10th Edition
ISBN: 9781259281594
Author: Joanne Willey, Linda Sherwood Adjunt Professor Lecturer, Christopher J. Woolverton Professor
Publisher: McGraw-Hill Education
Question
Book Icon
Chapter 23, Problem 1CHI
Summary Introduction

A diverse group of bacteria is present in the class of Clostridia. Clostridium is a Gram-positive, fermentative, and obligate anaerobic bacterium. Members belong to this genus have a great useful effect because they form endospores that are resistant to heat. They are responsible for spoilage of food in many cases, even foods that canned. Clostridium contains around a hundred (100) species that include essential pathogen and free-living bacteria.

Expert Solution & Answer
Check Mark

Explanation of Solution

Some species of Clostridia are valuable in the industry. Example, Clostridium acetobutylicum because it manufactures butanol. The well-known toxin is also generated by this pathogenic species. Tetanus is caused by Clostridium tetani by the release of toxin (tetanospasmin).

Depends on the strain, Clostridium perfringens secretes a protein toxin. It causes the poisoning of food and gas gangrene. However, it lacks a tricarboxylic acid cycle (TCA). They generate ATP by fermentation. When this species present inside the human host, it has a doubling time of about 8 to 10 minutes. Apparently, this is due to the assimilation and readiness to supply macromolecules in the host.

A number of amino acids are also fermented by Clostridium tetani to butyrate, H2, and lactate. Both amino acids and carbohydrates are catabolized by Clostridium perfringens and Clostridium acetobutylicum. In contrast, Clostridium tetani lack the genes that catabolize molecule of sugars.

A simple experiment that demonstrates the pattern of the rapid growth rate of bacteria in the host that uses different types of growth media in vitro.

Experiment that would explore doubling time phenomenon are given below:

Two test tubes are taken, one tube is poured by a rich medium of amino acid and nitrate. Another tube is poured with medium only contains a minimum essential medium. An equal volume of Clostridium perfringens culture is inoculated with two test tubes. These tubes are tightly capped without leaving headspace. Then, inoculate the culture in an anaerobic environment.

It is clearly observed after 24 to 48 hours of incubation, Clostridium perfringens culture in amino acid and nitrate-rich medium shows high turbidity and it indicates the growth of cells. Due to the lowest growth of a cell, other tube shows less turbidity.

In this experiment, it is clearly shown that growth of the cell is differs, because Clostridium perfringens lacks tricarboxylic acid cycle (TCA). It mainly relies on organic compound fermentation for its growth. The energy is produced by using nitrate as the terminal electron acceptor. Thus, the body of humans provides a sufficient amount of amino acids and nitrates to the Clostridium perfringens growth. Therefore, Clostridium grows faster inside the host than in vitro.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
In protozoan parasites, what are the main molecular pathways of medication resistance? Talk about it in depth.
In Spirogyra, some cells in one of the two filaments become empty after conjugation. Give reason.
In 1971, Dr. Akira Endo, working at the Sankyo company in Tokyo speculated that fungi not only contained antibiotics but also inhibitors of other processes such as cholesterol metabolism. Over a period of several years, he screened more than 6,000 fungal cultures until a positive result emerged. This compound, which was named compactin, came from the blue-green mold Penicillium citrinum Pen-5 that was isolated from a rice sample collected at a grain shop in Kyoto. Based on biochemical assays, compactin is the first known statin. 1. The original kinetics data for compactin inhibition of HMG-CoA reductase enzyme that was published by Dr. Endo in 1976 is shown on the right. a) Determine the Km and Vmax values for enzymatic activity. Do NOT forget the units. Answers can be expressed either as a fraction or in decimals. With No inhibitor: ; Vmax= -60 1/V, (nanomoles/min)-1 0.4 0.35+ 0.3 0.25 0.2 0.15 0.1 0.05 -40 -20 0 + 24 nM compactin + 70 nM compactin None T 20 40 60 1/[HMG-CoA], (mM)-1…
Knowledge Booster
Background pattern image
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Curren'S Math For Meds: Dosages & Sol
Nursing
ISBN:9781305143531
Author:CURREN
Publisher:Cengage
Text book image
Basic Clinical Laboratory Techniques 6E
Biology
ISBN:9781133893943
Author:ESTRIDGE
Publisher:Cengage
Text book image
Principles Of Radiographic Imaging: An Art And A ...
Health & Nutrition
ISBN:9781337711067
Author:Richard R. Carlton, Arlene M. Adler, Vesna Balac
Publisher:Cengage Learning