EBK ORGANIC CHEMISTRY
EBK ORGANIC CHEMISTRY
10th Edition
ISBN: 9781259636875
Author: Carey
Publisher: MCGRAW HILL BOOK COMPANY
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Chapter 23, Problem 12P

The IUPAC rules permit the use of common names for a number of familiar phenols and aryl ethers. These common names are listed here along with their systematic names. Write the structure of each compound.

(a) V a n i l l i n   ( 4-hydroxy-3-methoxybenzaldehyde ) : a component of vanilla bean oil, which contributes to its characteristic flavor

(b) T h y m o l   ( 2-isopropyl-5-methylphenol ) : obtained from oil of thyme

(c) C a r v a c r o l   ( 5-isopropyl-2-methylphenol ) : present in oil of thyme and marjoram

(d) E u g e n o l   ( 4-allyl-2-methoxyphenol ) : obtained from oil of cloves

(e) G a l l i c   a c i d   ( 3,4,5-trihydroxybenzoic acid ) : prepared by hydrolysis of tannins derived from plants

(f) S a l i c y l   a l c o h o l   ( o -hydroxybenzyl alcohol ) : obtained from bark of poplar and willow trees

Expert Solution & Answer
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Interpretation Introduction

Interpretation:

The structures of the given compounds are to be drawn.

Concept introduction:

The systematic naming of organic compound is done by using IUPAC nomenclature. The naming of an organic compound is done in such a way that the structure of the organic compound is correctly interpreted from its name.

In order to determine the structure of an organic compound from its name, first the root word in the name is identified. The suffixes like -ane, -ene, -yne, -ol, -al in the name represent that the parent compound is an alkane, alkene, alkyne, alcohol and aldehyde respectively.

In the next step of structure identification of the organic compound from its name, the position, location and number of the substituents bonded to the carbon chain are determined.

Answer to Problem 12P

Solution:

a) The structure of vanillin can be shown as follows.

EBK ORGANIC CHEMISTRY, Chapter 23, Problem 12P , additional homework tip  1

b) The structure of thymol can be shown as follows.

EBK ORGANIC CHEMISTRY, Chapter 23, Problem 12P , additional homework tip  2

c) The structure of carvacrol can be shown as follows.

EBK ORGANIC CHEMISTRY, Chapter 23, Problem 12P , additional homework tip  3

d) The structure of eugenol can be written as follows.

EBK ORGANIC CHEMISTRY, Chapter 23, Problem 12P , additional homework tip  4

e) The structure of gallic acid is shown as follows.

EBK ORGANIC CHEMISTRY, Chapter 23, Problem 12P , additional homework tip  5

f) The structure of salicyl alcohol is shown as follows.

EBK ORGANIC CHEMISTRY, Chapter 23, Problem 12P , additional homework tip  6

Explanation of Solution

a) The structure of vanillin (4-hydroxy-3-methoxybenzaldehyde)

The given compound is vanillin. Its IUPAC name is 4-hydroxy-3-methoxybenzaldehyde. The root word in the name is benzaldehyde which indicates that the structure contains a benzene ring with an aldehyde functional group at first carbon atom. The functional groups that are attached to the longest chain are called substituents and they are written as prefixes in alphabetical order. The substituent present at the third carbon atom is methoxy group and that present at the fourth carbon atom is hydroxyl group. Therefore, the structural formula for the given aldehyde can be written as follows.

EBK ORGANIC CHEMISTRY, Chapter 23, Problem 12P , additional homework tip  7

b) The structure of thymol (2-isopropyl-5-methylphenol)

The given compound is thymol. Its IUPAC name is 2-isopropyl-5-methylphenol. The root word in the name of the compound is phenol. It indicates that the structure consists of a benzene ring with hydroxyl functional group at the first carbon atom. The substituent present at the second carbon atom is isopropyl group and that present at the fifth carbon atom is methyl group. Therefore, the structural formula for the given compound can be shown as follows.

EBK ORGANIC CHEMISTRY, Chapter 23, Problem 12P , additional homework tip  8

c) The structure of carvacrol (5-isopropyl-2-methylphenol)

The given compound is carvacrol. Its IUPAC name is 5-isopropyl-2-methylphenol. The root word ‘phenol’ in the name indicates that the structure contains a benzene ring with a hydroxyl functional group at first carbon atom. The isopropyl group is attached to the fifth carbon atom and methyl group is attached to the second carbon atom. Therefore, the structural formula for the given compound can be shown as follows.

EBK ORGANIC CHEMISTRY, Chapter 23, Problem 12P , additional homework tip  9

d) The structure of eugenol (4-allyl-2-methoxyphenol)

The given compound is eugenol. Its IUPAC name is 4-allyl-2-methoxyphenol. The root word is phenol, which indicates that the structure contains a benzene ring with a hydroxyl functional group at the first carbon atom. The substituent present at the second carbon atom is methoxy group and that present at the fourth carbon atom is allyl group. Therefore, the structural formula for the given compound can be written as follows.

EBK ORGANIC CHEMISTRY, Chapter 23, Problem 12P , additional homework tip  10

e) The structure of gallic acid (3,4,5-trihydroxybenzoic acid)

The given compound is gallic acid. Its IUPAC name is 3,4,5-trihydroxybenzoic acid. The root word in the name is benzoic acid which indicates that the structure contains a benzene ring with a carboxylic acid functional group at the first carbon atom. The three hydroxy groups are attached to the third, fourth and fifth carbon atom respectively. Therefore, the structural formula for the given compound can be shown as follows.

EBK ORGANIC CHEMISTRY, Chapter 23, Problem 12P , additional homework tip  11

f) The structure of is salicyl alcohol (o-hydroxybenzyl alcohol)

The given compound is salicyl alcohol. Its IUPAC name is o-hydroxybenzyl alcohol. The name of the compound suggests that the compound is a benzyl alcohol with hydroxyl functional group at ortho position. Therefore, the structural formula for the given compound can be written as follows.

EBK ORGANIC CHEMISTRY, Chapter 23, Problem 12P , additional homework tip  12

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Ethyl butyrate, CH3CH2CH2CO2CH2CH3, is an artificial fruit flavor commonly used in the food industry for such flavors as orange and pineapple. Its fragrance and taste are often associated with fresh orange juice, and thus it is most commonly used as orange flavoring.It can be produced by the reaction of butanoic acid with ethanol in the presence of an acid catalyst (H+): CH3CH2CH2CO2H(l)+CH2CH3OH(l)H+⟶CH3CH2CH2CO2CH2CH3(l)+H2O(l) a) Given 7.70 g of butanoic acid and excess ethanol, how many grams of ethyl butyrate would be synthesized, assuming a complete 100% yield? b) A chemist ran the reaction and obtained 5.25 g of ethyl butyrate. What was the percent yield? c) The chemist discovers a more efficient catalyst that can produce ethyl butyrate with a 78.0% yield. How many grams would be produced from 7.70 g of butanoic acid and excess ethanol?
Ethyl butyrate, CH3CH2CH2CO2CH2CH3, is an artificial fruit flavor commonly used in the food industry for such flavors as orange and pineapple. Its fragrance and taste are often associated with fresh orange juice, and thus it is most commonly used as orange flavoring.It can be produced by the reaction of butanoic acid with ethanol in the presence of an acid catalyst (H+): CH3CH2CH2CO2H(l)+CH2CH3OH(l)H+⟶CH3CH2CH2CO2CH2CH3(l)+H2O(l). The chemist discovers a more efficient catalyst that can produce ethyl butyrate with a 78.0% yield. How many grams would be produced from 8.50 gof butanoic acid and excess ethanol? Express your answer in grams to three significant figures.
Ethyl butyrate, CH3CH2CH2CO2CH2CH3, is an artificial fruit flavor commonly used in the food industry for such flavors as orange and pineapple. Its fragrance and taste are often associated with fresh orange juice, and thus it is most commonly used as orange flavoring.It can be produced by the reaction of butanoic acid with ethanol in the presence of an acid catalyst (H+): CH3CH2CH2CO2H(l)+CH2CH3OH(l)H+⟶CH3CH2CH2CO2CH2CH3(l)+H2O(l) Given 8.50 g of butanoic acid and excess ethanol, how many grams of ethyl butyrate would be synthesized, assuming a complete 100%yield? Express your answer in grams to three significant figures.
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