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(II) Two large, flat metal plates are separated by a distance that is very small compared to their height and width. The conductors are given equal but opposite uniform surface charge densities ± σ. Ignore edge effects and use Gauss’s law to show (a) that for points far from the edges, the electric field between the plates is
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- (a) Determine the electric field intensity E caused by a spherical cloud of electrons in free space with a volume charge density p=-P for 0≤R≤a (both P, and a are positive) and p=0 for R> a. (8%)arrow_forward(II) The 1/r² form of Coulomb's law implies the following: (i) The electric field is zero at all points inside a uniformly charged shell. (ii) The electric field outside a uniformly charged sphere can be found by treating the charge as being concentrated at the center. Use these facts to show that within a uniformly charged sphere of radius R having a volume charge density p C/m³, the field strength increases linearly with the distance r from the center. That is, Ex r for r < R.arrow_forward(c) The interface between two different dielectric media has a surface charge density of 3.54 x 10-11 C/m2. Find the electric field in the first medium (€1 = E2 = 3â – 2ý + 22 V/m. Assume that the interface is perpendicular to the y-axis. Also find the angle which E makes with the y-axis. 2c0), if the electric field in second medium (c2 18co) is given as %3Darrow_forward
- (a) Sketch the electric field lines around an isolated point charge q > 0. (b) Sketch the electric field pattern around an isolated negative point charge of magnitude -2q.arrow_forwardA spherical metal shellA of radius R, and a solid metal sphere B ofradius RB (arrow_forward(c) As shown in Figure 3, there are 2 non-conducting rings each with uniform charge q1 and q2. Both rings have the same radius R. The separation distance between the rings is d = 4.0 R. Given q1 = 10.0 nC, q2 = -20.0 nC, R= 0.50 m, d= 1.50 m. Calculate the net electric field at point P. Ring 1 Ring 2 12 P R R -R→| d Figure 3arrow_forward(10% ) Problem 7: An infinite conducting cylindrical shell of outer radius ri-0.10 m and inner radius r2 0.08 m initially carries a surface charge density 0.15 μC/m2 A thin wire with linear charge density 1.3 μC m s nserted along the shells' axis. The shell and the wire do not touch and these is no charge exchanged between them Banchi, Stephen - banchis3@students.rowan.edu @ theexpertta.com - tracking id: 2N74-2F-82-4A-BAAB-13083. In accordance with Expert TA's Terms of Service. copying this information to any solutions sharing website is strictly forbidden. Doing so may result in termination of your Expert TA Account. -a33% Part (a) What is the new surface charge density, in microcoulombs per square meter, on the inner surface of the cylindrical shell? -là 33% Part (b) What is the new surface charge density, in microcoulombs per square meter, on the outer surface of the cylindrical shell? 33% Part (c) Enter an expression for the magnitude of the electric field outside the cylinder (r…arrow_forward(c) Calculate the magnitude of the force on the charge q, given that the square is 10.0 cm on a side and q=2 μC. Fr net = 0 Case II. 9a = b = +8 μC and qc = qd = -8 μC. N (e) Due to symmetry the direction of the net force is D. In the -y direction Fnet (d) In your notebook, draw the forces on q due to qa, qb, qc, and qd. Or use the result of of Homework: Charges on a Square Free Body Diagram. = 83.91 qc Hint: For each force draw the x and y components. Some will add and some will cancel. (f) Calculate the magnitude of the force on the charge q, given that the square is 10.0 cm on a side and q=2 μC. X N No, that's only partially correct. O qd Xarrow_forward(Figure 1)A slab of insulating material of uniform thickness d, lying between -d/2 to +d/2 along the x axis, extends infinitely in the y and z directions, as shown in the figure. The slab has a uniform charge density p. The electric field is zero in the middle of the slab, at z = 0. Figure x=+d/2 x=0 x= -d/2 1 of 2 0 -1.57 rad Submit ✓ Correct Part C What is Eout, the magnitude of the electric field outside the slab? As implied by the fact that Eout is not given as a function of, this magnitude is constant everywhere outside the slab, not just at the surface. Express your answer in terms of d, p, and . ► View Available Hint(s) pd Eout = 2€0 Previous Answers Submit Previous Answers ✓ Correct Part D What is Ein (2), the magnitude of the electric field inside the slab as a function of z? ▸ View Available Hint(s) Ein (2) = Submit |VL]ΑΣΦ ?arrow_forward(a) Two insulated charged copper spheres A and B have their centres separated by a distance of 50 cm. What is the mutual force of electrostatic repulsion if the charge on each is 6.5 x 10-7 C? The radii of A and B are negligible compared to the distance of separation.arrow_forward7-) A conducting sphere, with an outer radius of 25 cm and an inner radius of 20 cm, has a surface charge density of 6.37 µC / m * 2. A charge of -0.50 µC is introduced into the internal cavity of the sphere. What is the new charge density just outside the sphere? One of these answers: -5.5 µC -4.5 µC 5.5 µC 4.5 µCarrow_forward(c) d) 2R R. R. R. Two uniform line charges of = 4n C/m each are parallel to the z-axis at (0, 4)m and (0, -4)m. Magnitude of electric field at points (+4, 0, 0) is (a) 9 V/m (b) 18 V/m C4.5 V/m (d) 9/2 V/marrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_ios
- Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning