Figure 22-22 shows three arrangements of electric held lines. In each arrangement, a proton is released from rest at point A and is then accelerated through point B by the electric field. Points A and B have equal separations in the three arrangements. Rank the arrangements according to the linear momentum of the proton at point B , greatest first. Figure 22-22 Qustion 1.

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Answer 1

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Chapter 22, Problem 1Q

Figure 22-22 shows three arrangements of electric held lines. In each arrangement, a proton is released from rest at point A and is then accelerated through point B by the electric field. Points A and B have equal separations in the three arrangements. Rank the arrangements according to the linear momentum of the proton at point B, greatest first.

Chapter 22, Problem 1Q, Figure 22-22 shows three arrangements of electric held lines. In each arrangement, a proton is

Figure 22-22 Qustion 1.

Expert Solution & Answer

To determine

To rank:

The given situations according to the linear momentum of a proton released from rest in an electric field at point A.

Answer to Problem 1Q

Solution:

(a)> (b)> (c).

Explanation of Solution

1) Concept:

Electric field strength is directly proportional to the density of field lines. Hence, the field is stronger when the lines are closely located and weaker when the lines are farther away. According to Newton’s second law, the rate of change of linear momentum of a body depends on the force acting on the body. Hence, the stronger the electric field, greater the force will be and also greater the linear momentum will be.

2) Formulae:

Electric field strength, E∞1r2.

3) Given:

A proton is released from rest at point A and is then accelerated through point B.

4) Calculations:

Let us look at the given situations.

Fundamentals of Physics, Volume 1, Chapter 1-20, Chapter 22, Problem 1Q

In case a, the field lines are closely located than in case b and c. Therefore the linear momentum of proton at B is greatest in case a.

In case b, the field lines are diverging from A towards B. In C the distance between field lines are farther than in case b and c. Therefore the electric field is greater in case b than in case c. Thus momentum of proton is greater in case b than case c.

Conclusion:

Using the relationship between linear momentum and force of a particle we can compare the momentum in the given scenarios.

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· A proton with mass m = 1.67x10-27 kg and an initial velocity i, of magnitude 2x104 m/s in the positive x direction enters the region between two charged parallel plates through a small hole as seen in the figure. The magnitude of the electric fiend E between the plates is 5x104 N/C and in the negative x direction. A second hole is placed on the second plate opposite to the first one. (a) What should the maximum separation L between the plates be to allow the proton leave the plates from the second hole? (b)How long will it take the proton to do this? (c) If the separation were not L found in (a) but L/2 for the same proton speed, what would be the final velocity of the proton as it leaves the plates? (Ignore the gravity, assume that the holes do not alter the electric field. e = 1.6x10-19 C.) m Plate

58 G0 Proton in a well Figure 24-59 shows electric poten- tial V along an x axis. The scale of the ver- tical axis is set by V, = 10.0 V. A pro- x (cm) 0 1 2 3 4 5 6 7 %3D ton is to be released Figure 24-59 Problem 58. at x= 3.5 cm with initial kinetic energy 4.00 eV. (a) If it is initially moving in the neg- ative direction of the axis, does it reach a turning point (if so, what is the x coordinate of that point) or does it escape from the plotted region (if so, what is its speed at x = 0)? (b) If it is initially moving in the positive direction of the axis, does it reach a turning point (if so, what is the x coordinate of that point) or does it escape from the plotted region (if so, what is its speed at x = 6.0 cm)? What are the (c) magnitude Fand (d) direction (positive or negative direction of the x axis) of the electric force on the proton if the proton moves just to the left of x = 3.0 cm? What are (e) Fand (f) the direction if the proton moves just to the right of x = 5.0 cm?…

The figure shows three arrangements of electric field lines. In each arrangement, a proton is released from rest at point A and is then accelerated through point B by the electric field. Points A and B have equal separations in the three arrangements. Rank the arrangements according to the linear momentum of the proton at point B. a: Third Greatest b: Second Greatest c: Greatest a: Greatest b: Second Greatest c: Third Greatest a: Second Greatest b: Greatest c: Third Greatest a = b = c

Answer 2

Textbook Question

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Chapter 22, Problem 1Q

Figure 22-22 shows three arrangements of electric held lines. In each arrangement, a proton is released from rest at point A and is then accelerated through point B by the electric field. Points A and B have equal separations in the three arrangements. Rank the arrangements according to the linear momentum of the proton at point B, greatest first.

Chapter 22, Problem 1Q, Figure 22-22 shows three arrangements of electric held lines. In each arrangement, a proton is

Figure 22-22 Qustion 1.

Expert Solution & Answer

To determine

To rank:

The given situations according to the linear momentum of a proton released from rest in an electric field at point A.

Answer to Problem 1Q

Solution:

(a)> (b)> (c).

Explanation of Solution

1) Concept:

Electric field strength is directly proportional to the density of field lines. Hence, the field is stronger when the lines are closely located and weaker when the lines are farther away. According to Newton’s second law, the rate of change of linear momentum of a body depends on the force acting on the body. Hence, the stronger the electric field, greater the force will be and also greater the linear momentum will be.

2) Formulae:

Electric field strength, E∞1r2.

3) Given:

A proton is released from rest at point A and is then accelerated through point B.

4) Calculations:

Let us look at the given situations.

Fundamentals of Physics, Volume 1, Chapter 1-20, Chapter 22, Problem 1Q

In case a, the field lines are closely located than in case b and c. Therefore the linear momentum of proton at B is greatest in case a.

In case b, the field lines are diverging from A towards B. In C the distance between field lines are farther than in case b and c. Therefore the electric field is greater in case b than in case c. Thus momentum of proton is greater in case b than case c.

Conclusion:

Using the relationship between linear momentum and force of a particle we can compare the momentum in the given scenarios.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Textbook Question

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Chapter 22, Problem 1Q

Figure 22-22 shows three arrangements of electric held lines. In each arrangement, a proton is released from rest at point A and is then accelerated through point B by the electric field. Points A and B have equal separations in the three arrangements. Rank the arrangements according to the linear momentum of the proton at point B, greatest first.

Chapter 22, Problem 1Q, Figure 22-22 shows three arrangements of electric held lines. In each arrangement, a proton is

Figure 22-22 Qustion 1.

Expert Solution & Answer

To determine

To rank:

The given situations according to the linear momentum of a proton released from rest in an electric field at point A.

Answer to Problem 1Q

Solution:

(a)> (b)> (c).

Explanation of Solution

1) Concept:

Electric field strength is directly proportional to the density of field lines. Hence, the field is stronger when the lines are closely located and weaker when the lines are farther away. According to Newton’s second law, the rate of change of linear momentum of a body depends on the force acting on the body. Hence, the stronger the electric field, greater the force will be and also greater the linear momentum will be.

2) Formulae:

Electric field strength, E∞1r2.

3) Given:

A proton is released from rest at point A and is then accelerated through point B.

4) Calculations:

Let us look at the given situations.

Fundamentals of Physics, Volume 1, Chapter 1-20, Chapter 22, Problem 1Q

In case a, the field lines are closely located than in case b and c. Therefore the linear momentum of proton at B is greatest in case a.

In case b, the field lines are diverging from A towards B. In C the distance between field lines are farther than in case b and c. Therefore the electric field is greater in case b than in case c. Thus momentum of proton is greater in case b than case c.

Conclusion:

Using the relationship between linear momentum and force of a particle we can compare the momentum in the given scenarios.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Textbook Question

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Chapter 22, Problem 1Q

Figure 22-22 shows three arrangements of electric held lines. In each arrangement, a proton is released from rest at point A and is then accelerated through point B by the electric field. Points A and B have equal separations in the three arrangements. Rank the arrangements according to the linear momentum of the proton at point B, greatest first.

Chapter 22, Problem 1Q, Figure 22-22 shows three arrangements of electric held lines. In each arrangement, a proton is

Figure 22-22 Qustion 1.

Expert Solution & Answer

To determine

To rank:

The given situations according to the linear momentum of a proton released from rest in an electric field at point A.

Answer to Problem 1Q

Solution:

(a)> (b)> (c).

Explanation of Solution

1) Concept:

Electric field strength is directly proportional to the density of field lines. Hence, the field is stronger when the lines are closely located and weaker when the lines are farther away. According to Newton’s second law, the rate of change of linear momentum of a body depends on the force acting on the body. Hence, the stronger the electric field, greater the force will be and also greater the linear momentum will be.

2) Formulae:

Electric field strength, E∞1r2.

3) Given:

A proton is released from rest at point A and is then accelerated through point B.

4) Calculations:

Let us look at the given situations.

Fundamentals of Physics, Volume 1, Chapter 1-20, Chapter 22, Problem 1Q

In case a, the field lines are closely located than in case b and c. Therefore the linear momentum of proton at B is greatest in case a.

In case b, the field lines are diverging from A towards B. In C the distance between field lines are farther than in case b and c. Therefore the electric field is greater in case b than in case c. Thus momentum of proton is greater in case b than case c.

Conclusion:

Using the relationship between linear momentum and force of a particle we can compare the momentum in the given scenarios.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Textbook Question

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Answer 6

Textbook Question

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Answer 7

Expert Solution & Answer

To determine

To rank:

The given situations according to the linear momentum of a proton released from rest in an electric field at point A.

Answer to Problem 1Q

Solution:

(a)> (b)> (c).

Explanation of Solution

1) Concept:

Electric field strength is directly proportional to the density of field lines. Hence, the field is stronger when the lines are closely located and weaker when the lines are farther away. According to Newton’s second law, the rate of change of linear momentum of a body depends on the force acting on the body. Hence, the stronger the electric field, greater the force will be and also greater the linear momentum will be.

2) Formulae:

Electric field strength, E∞1r2.

3) Given:

A proton is released from rest at point A and is then accelerated through point B.

4) Calculations:

Let us look at the given situations.

Fundamentals of Physics, Volume 1, Chapter 1-20, Chapter 22, Problem 1Q

In case a, the field lines are closely located than in case b and c. Therefore the linear momentum of proton at B is greatest in case a.

In case b, the field lines are diverging from A towards B. In C the distance between field lines are farther than in case b and c. Therefore the electric field is greater in case b than in case c. Thus momentum of proton is greater in case b than case c.

Conclusion:

Using the relationship between linear momentum and force of a particle we can compare the momentum in the given scenarios.

Answer 8

Expert Solution & Answer

To determine

To rank:

The given situations according to the linear momentum of a proton released from rest in an electric field at point A.

Answer to Problem 1Q

Solution:

(a)> (b)> (c).

Explanation of Solution

1) Concept:

Electric field strength is directly proportional to the density of field lines. Hence, the field is stronger when the lines are closely located and weaker when the lines are farther away. According to Newton’s second law, the rate of change of linear momentum of a body depends on the force acting on the body. Hence, the stronger the electric field, greater the force will be and also greater the linear momentum will be.

2) Formulae:

Electric field strength, E∞1r2.

3) Given:

A proton is released from rest at point A and is then accelerated through point B.

4) Calculations:

Let us look at the given situations.

Fundamentals of Physics, Volume 1, Chapter 1-20, Chapter 22, Problem 1Q

In case a, the field lines are closely located than in case b and c. Therefore the linear momentum of proton at B is greatest in case a.

In case b, the field lines are diverging from A towards B. In C the distance between field lines are farther than in case b and c. Therefore the electric field is greater in case b than in case c. Thus momentum of proton is greater in case b than case c.

Conclusion:

Using the relationship between linear momentum and force of a particle we can compare the momentum in the given scenarios.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

To determine

To rank:

The given situations according to the linear momentum of a proton released from rest in an electric field at point A.

Answer 12

Answer to Problem 1Q

Solution:

(a)> (b)> (c).

Answer 13

Explanation of Solution

1) Concept:

Electric field strength is directly proportional to the density of field lines. Hence, the field is stronger when the lines are closely located and weaker when the lines are farther away. According to Newton’s second law, the rate of change of linear momentum of a body depends on the force acting on the body. Hence, the stronger the electric field, greater the force will be and also greater the linear momentum will be.

2) Formulae:

Electric field strength, E∞1r2.

3) Given:

A proton is released from rest at point A and is then accelerated through point B.

4) Calculations:

Let us look at the given situations.

Fundamentals of Physics, Volume 1, Chapter 1-20, Chapter 22, Problem 1Q

In case a, the field lines are closely located than in case b and c. Therefore the linear momentum of proton at B is greatest in case a.

In case b, the field lines are diverging from A towards B. In C the distance between field lines are farther than in case b and c. Therefore the electric field is greater in case b than in case c. Thus momentum of proton is greater in case b than case c.

Conclusion:

Using the relationship between linear momentum and force of a particle we can compare the momentum in the given scenarios.