Chemistry: Atoms First
Chemistry: Atoms First
3rd Edition
ISBN: 9781259638138
Author: Julia Burdge, Jason Overby Professor
Publisher: McGraw-Hill Education
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Chapter 21.2, Problem 21.2.2SR
Interpretation Introduction

Interpretation: The process of formation of aurora borealis and aurora Australis should be determined.

Concept Introduction:

Atmosphere: The atmosphere is defined as air that is layer of gases which surrounds the earth due to gravity of earth.

The earth atmosphere consists of layers such as thermosphere, mesosphere, stratosphere and troposphere depending on the temperature and its composition.

The different regions of atmosphere and their description are as follows:

Thermosphere:

It is the top most layers in atmosphere which has high temperature than all other layers present in atmosphere. The high temperature is due to the heat released by the reactions like continuous attack of O2, N2 and atomic particles by energetic species.

Mesosphere:

It is layer next to thermosphere that is the layer below the thermosphere. The increasing temperature for this layer with respect to decreasing height is due to the presence of less concentration of ozone and other gases in it.

Stratosphere:

It is found below the mesosphere layer in which the concentration of ozone and other gases are high. The increasing temperature for this layer with respect to increasing height is due to the presence of high concentration of ozone and other gases in it.

Troposphere:

The layer is below stratosphere layer and it is closest to the earth surface. It is the thinnest place which is responsible for all weather conditions since it contains almost all amounts of water vapor with it.

Aurora borealis: They are celestial lights found in northern hemisphere.

Aurora Australis: They are same as aurora borealis but found in southern hemisphere.

Visible Range: The electromagnetic radiation which range is about 390 nm to 700 nm is considered as visible since the human eye can able to detect this range.

UV Range: The electromagnetic radiation which range is about 100 nm to 400nm is regarded as ultraviolet region and they are shorter than the visible region.

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In regard to the greenhouse effect, which statement is not true? (a) Ultraviolet and visible radiation are converted to infrared radiation at the surface of Earth. (b) Approximately one-third of the radiation of the Sun does not enter the atmosphere of Earth. (c) Infrared radiation is absorbed by greenhouse gases. (d) Greenhouse gases were not historically present in the atmosphere. (e) Ultraviolet radiation is absorbed by ozone.
(b) The nitric oxide molecule undergoes photoionization in the upper atmosphere. (c) Nitric oxide undergoes oxidation by ozone in the stratosphere.  (d) Nitrogen dioxide dissolves in water to form nitric acid and nitric oxide.
The initial step in the formation of O3 from O2 in the stratosphere is the absorption of light by 02, which causes it to split into O atoms. The balanced chemical equation for this process is 02 (g) → 2 0 (g) If AHP for O (g) is +249.17 kJ/mole, what wavelength of light, in nm, must be absorbed by 02 to make this reaction occur? Enter only the numerical portion of your answer in the space provided, to the correct number of significant figures; do not enter the units.

Chapter 21 Solutions

Chemistry: Atoms First

Ch. 21.5 - Prob. 21.5.1SRCh. 21.5 - Prob. 21.5.2SRCh. 21.8 - Prob. 21.3WECh. 21.8 - Prob. 3PPACh. 21.8 - Prob. 3PPBCh. 21.8 - Prob. 3PPCCh. 21.8 - Prob. 21.8.1SRCh. 21 - Prob. 21.1QPCh. 21 - Prob. 21.2QPCh. 21 - Prob. 21.3QPCh. 21 - Prob. 21.4QPCh. 21 - Prob. 21.5QPCh. 21 - Prob. 21.6QPCh. 21 - Prob. 21.7QPCh. 21 - Prob. 21.8QPCh. 21 - Prob. 21.9QPCh. 21 - Prob. 21.10QPCh. 21 - Prob. 21.11QPCh. 21 - Prob. 21.12QPCh. 21 - Prob. 21.13QPCh. 21 - Prob. 21.14QPCh. 21 - Prob. 21.15QPCh. 21 - Prob. 21.16QPCh. 21 - Prob. 21.17QPCh. 21 - Prob. 21.18QPCh. 21 - Prob. 21.19QPCh. 21 - Prob. 21.20QPCh. 21 - Prob. 21.21QPCh. 21 - Prob. 21.22QPCh. 21 - Prob. 21.23QPCh. 21 - Prob. 21.24QPCh. 21 - Prob. 21.25QPCh. 21 - Prob. 21.26QPCh. 21 - Prob. 21.27QPCh. 21 - Prob. 21.28QPCh. 21 - Prob. 21.29QPCh. 21 - Prob. 21.30QPCh. 21 - Prob. 21.31QPCh. 21 - Prob. 21.32QPCh. 21 - Prob. 21.33QPCh. 21 - Prob. 21.34QPCh. 21 - Prob. 21.35QPCh. 21 - Prob. 21.36QPCh. 21 - Prob. 21.37QPCh. 21 - Prob. 21.38QPCh. 21 - Prob. 21.39QPCh. 21 - Calcium oxide or quicklime (CaO) is used in...Ch. 21 - Prob. 21.41QPCh. 21 - Prob. 21.42QPCh. 21 - Prob. 21.43QPCh. 21 - Prob. 21.44QPCh. 21 - Prob. 21.45QPCh. 21 - Prob. 21.46QPCh. 21 - Prob. 21.47QPCh. 21 - Prob. 21.48QPCh. 21 - Prob. 21.49QPCh. 21 - Prob. 21.50QPCh. 21 - In which region of the atmosphere is ozone...Ch. 21 - The gas-phase decomposition of peroxyacetyl...Ch. 21 - Prob. 21.53QPCh. 21 - Prob. 21.54QPCh. 21 - Prob. 21.55QPCh. 21 - Prob. 21.56QPCh. 21 - Prob. 21.57QPCh. 21 - Prob. 21.58QPCh. 21 - A concentration of 8.00 102 ppm by volume of CO...Ch. 21 - Prob. 21.60QPCh. 21 - Briefly describe the harmful effects of the...Ch. 21 - Prob. 21.62QPCh. 21 - Prob. 21.63QPCh. 21 - Prob. 21.64QPCh. 21 - Prob. 21.65QPCh. 21 - Prob. 21.66QPCh. 21 - Prob. 21.67QPCh. 21 - A glass of water initially at pH 7.0 is exposed to...Ch. 21 - Prob. 21.69QPCh. 21 - Prob. 21.70QPCh. 21 - Describe the removal of SO2 by CaO (to form CaSO3)...Ch. 21 - Which of the following settings is the most...Ch. 21 - Prob. 21.73QPCh. 21 - Peroxyacetyl nitrate (PAN) undergoes thermal...Ch. 21 - Prob. 21.75QPCh. 21 - Prob. 21.76QPCh. 21 - The carbon dioxide level in the atmosphere today...Ch. 21 - A 14-m by 10-m by 3.0-m basement had a high radon...Ch. 21 - Prob. 21.79QPCh. 21 - A person was found dead of carbon monoxide...Ch. 21 - Prob. 21.81QPCh. 21 - As stated in the chapter, carbon monoxide has a...Ch. 21 - Prob. 21.83QPCh. 21 - Prob. 21.84QPCh. 21 - Prob. 21.85QPCh. 21 - Prob. 21.86QP
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Solutions: Crash Course Chemistry #27; Author: Crash Course;https://www.youtube.com/watch?v=9h2f1Bjr0p4;License: Standard YouTube License, CC-BY