EBK INTRODUCTORY CHEMISTRY: AN ACTIVE L
EBK INTRODUCTORY CHEMISTRY: AN ACTIVE L
6th Edition
ISBN: 8220100547508
Author: CRACOLICE
Publisher: Cengage Learning US
Question
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Chapter 21, Problem 94E
Interpretation Introduction

Interpretation:

The monomers from the following step-growth condensation polymer are to be identified.

EBK INTRODUCTORY CHEMISTRY: AN ACTIVE L, Chapter 21, Problem 94E , additional homework tip  1

Concept introduction:

Polymers are the macromolecules that are formed by the repeating monomeric units. Step-growth condensation polymers are synthesized by the stepwise reaction of monomers. The monomers contain bifunctional or multifunctional groups. In step-growth polymerization, small molecules such as water, ammonia are eliminated.

The condensation reaction of the dicarboxylic acid and diamine are employed for the synthesis of polyamide. Ammonia molecule is eliminated and amide linkage is formed. The general reaction for the synthesis of two repeating units of the polymer is,

EBK INTRODUCTORY CHEMISTRY: AN ACTIVE L, Chapter 21, Problem 94E , additional homework tip  2

Here, R is an alkyl group.

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Chapter 21 Solutions

EBK INTRODUCTORY CHEMISTRY: AN ACTIVE L

Ch. 21 - Prob. 11ECh. 21 - Prob. 12ECh. 21 - Prob. 13ECh. 21 - Prob. 14ECh. 21 - Prob. 15ECh. 21 - Prob. 16ECh. 21 - Prob. 17ECh. 21 - Prob. 18ECh. 21 - Prob. 19ECh. 21 - Prob. 20ECh. 21 - Prob. 21ECh. 21 - Prob. 22ECh. 21 - Is the general formula of a cycloalkanes the same...Ch. 21 - Prob. 24ECh. 21 - Draw the skeleton diagram of cyclopentane.Ch. 21 - Prob. 26ECh. 21 - Prob. 27ECh. 21 - Prob. 28ECh. 21 - Prob. 29ECh. 21 - Prob. 30ECh. 21 - Prob. 31ECh. 21 - Prob. 32ECh. 21 - Prob. 33ECh. 21 - Prob. 34ECh. 21 - Prob. 35ECh. 21 - Prob. 36ECh. 21 - What is the difference in bonding and in the...Ch. 21 - Prob. 38ECh. 21 - Draw the structural formula of trichloroethene, a...Ch. 21 - Prob. 40ECh. 21 - Prob. 41ECh. 21 - Prob. 42ECh. 21 - Prob. 43ECh. 21 - Prob. 44ECh. 21 - Give the IUPAC name of the following molecule:Ch. 21 - Give the IUPAC name of the following molecule:Ch. 21 - Prob. 47ECh. 21 - Prob. 48ECh. 21 - Prob. 49ECh. 21 - Prob. 50ECh. 21 - Prob. 51ECh. 21 - Prob. 52ECh. 21 - Prob. 53ECh. 21 - Prob. 54ECh. 21 - Write an equation for the hydrogenation of...Ch. 21 - Prob. 56ECh. 21 - Prob. 57ECh. 21 - Prob. 58ECh. 21 - Prob. 59ECh. 21 - Explain why the ether with formula C2H6O is very...Ch. 21 - Prob. 61ECh. 21 - Prob. 62ECh. 21 - Prob. 63ECh. 21 - Prob. 64ECh. 21 - Prob. 65ECh. 21 - Prob. 66ECh. 21 - Prob. 67ECh. 21 - Prob. 68ECh. 21 - Prob. 69ECh. 21 - Prob. 70ECh. 21 - Prob. 71ECh. 21 - Prob. 72ECh. 21 - Prob. 73ECh. 21 - Prob. 74ECh. 21 - Prob. 75ECh. 21 - Prob. 76ECh. 21 - Prob. 77ECh. 21 - Prob. 78ECh. 21 - Prob. 79ECh. 21 - Prob. 80ECh. 21 - Prob. 81ECh. 21 - Prob. 82ECh. 21 - Prob. 83ECh. 21 - Prob. 84ECh. 21 - Prob. 85ECh. 21 - Prob. 86ECh. 21 - Prob. 87ECh. 21 - Prob. 88ECh. 21 - Prob. 89ECh. 21 - Prob. 90ECh. 21 - Prob. 91ECh. 21 - Prob. 92ECh. 21 - Prob. 93ECh. 21 - Prob. 94ECh. 21 - Distinguish precisely, and in scientific terms,...Ch. 21 - Prob. 96ECh. 21 - What is the difference in bonding and in general...Ch. 21 - Draw all isomers of C4H8.Ch. 21 - Prob. 99ECh. 21 - Prob. 100ECh. 21 - Prob. 101ECh. 21 - Prob. 102ECh. 21 - Prob. 103ECh. 21 - Prob. 104ECh. 21 - Prob. 105ECh. 21 - Prob. 106ECh. 21 - Prob. 107ECh. 21 - Prob. 21.1TCCh. 21 - Prob. 21.2TCCh. 21 - Prob. 21.3TCCh. 21 - Prob. 21.4TCCh. 21 - Prob. 21.5TCCh. 21 - Prob. 21.6TCCh. 21 - Prob. 21.7TCCh. 21 - Prob. 21.8TCCh. 21 - Prob. 21.9TCCh. 21 - Prob. 21.10TCCh. 21 - Prob. 21.11TCCh. 21 - Prob. 21.12TCCh. 21 - Prob. 1CLECh. 21 - Prob. 2CLECh. 21 - Prob. 3CLECh. 21 - Prob. 4CLECh. 21 - Prob. 5CLECh. 21 - Prob. 6CLECh. 21 - Prob. 7CLECh. 21 - Prob. 8CLECh. 21 - Prob. 9CLECh. 21 - Prob. 10CLE
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