Essential University Physics
4th Edition
ISBN: 9780134988566
Author: Wolfson, Richard
Publisher: Pearson Education,
expand_more
expand_more
format_list_bulleted
Concept explainers
Textbook Question
Chapter 21, Problem 67P
The volume charge density inside a solid sphere of radius a is ρ = ρ0r/a where ρ0 is a constant. Find (a) the total charge and (b) the electric field strength within the sphere, as a function of distance r from the center.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
A cylinder of length L=5m has a radius R=2 cm and linear charge density 2=300 µC/m. Although the
linear charge density is a constant through the cylinder, the charge density within the cylinder changes
with r. Within the cylinder, the charge density of the cylinder varies with radius as a function p( r) =p.r/R.
Here R is the radius of the cylinder and R=2 cm and p, is just a constant that you need to determine.
b. Find the constant po in terms of R and 2. Then plug in values of R and 1. to find the value for
the constant p.
c. Assuming that L>>R, use Gauss's law to find out the electric field E inside the cylinder (rR) in terms of 1. and R.
d. Based on your result from problem c, find the electric field E at r=1cm and r=4cm.
Positive charge is distributed in a sphere of radius R that is centered at the origin. Inside the sphere, the electric
field is Ē(r) = kr-1/4 f, where k is a positive constant. There is no charge outside the sphere.
a) How is the charge distributed inside the sphere? In particular, find an equation for the charge density, p.
b) Determine the electric field, E(r), for r > R (outside the sphere).
c) What is the potential difference between the center of the sphere (r = 0) and the surface of the sphere
(r = R)?
d) What is the energy stored in this electric charge configuration?
Charge is distributed throughout a spherical shell of inner radius r1 and outer radius r2 with a volume density given by ρ = ρ0 r1/r, where ρ0 is a constant. Determine the electric field due to this charge as a function of r, the distance from the center of the shell.
Chapter 21 Solutions
Essential University Physics
Ch. 21.1 - Which figure represents the electric field of a...Ch. 21.2 - The figure shows a cube of side s in a uniform...Ch. 21.3 - A spherical surface surrounds an isolated positive...Ch. 21.4 - A spherical shell carries charge Q distributed...Ch. 21.5 - (1) If you're close to a finite line of charge...Ch. 21.6 - (1) If you're close to a finite line of charge...Ch. 21 - Can electric field lines ever cross? Why or why...Ch. 21 - The electric flux through a closed surface is...Ch. 21 - Under what conditions can the electric flux...Ch. 21 - Right field lines emerge from a closed surface...
Ch. 21 - In Gausss law, EdA=q0does the field E necessarily...Ch. 21 - The field of an infinite charged line decreases as...Ch. 21 - Why cant you use Gausss law to determine the field...Ch. 21 - Youre sitting inside an uncharged, hollow...Ch. 21 - Does Gausss law apply to a spherical Gaussian...Ch. 21 - The electric field of a flat sheet of charge is...Ch. 21 - In Fig. 21.32, the magnitude of the middle charge...Ch. 21 - Charges +2q and q are near each other. Sketch some...Ch. 21 - The net charge shown in Fig. 21.33 is +Q. Identify...Ch. 21 - A flat surface with area 2.0 m2 is in a uniform...Ch. 21 - The electric field on the surface of a...Ch. 21 - In the figure with GOT IT? 21.2, take E = 1.75...Ch. 21 - In Fig. 21.8, take the half-cylinders radius and...Ch. 21 - A sock comes out of the dryer with a trillion...Ch. 21 - Whats the electric flux through the closed...Ch. 21 - Interpret This problem involves applying Gauss's...Ch. 21 - A 2.6-C charge is at the center of a cube 7.5 cm...Ch. 21 - The electric field at the surface of a...Ch. 21 - A solid sphere 25 cm in radius carries 14C,...Ch. 21 - A 15-nC point charge is at the center of a thin...Ch. 21 - The electric field strength outside a charge...Ch. 21 - An electron close to a large, Hat sheet of charge...Ch. 21 - Find the field produced by a uniformly charged...Ch. 21 - What surface charge density on an infinite sheet...Ch. 21 - A rod 50 cm long and 1.0 cm in radius carries a...Ch. 21 - Whats the approximate field strength 1 cm above a...Ch. 21 - The disk in Fig. 21.22 has area 0.14 m2 and is...Ch. 21 - What is the electric field strength just outside...Ch. 21 - A net charge of 5.0 C is applied on one side of a...Ch. 21 - A positive point charge q lies at the center of a...Ch. 21 - A total charge of 18 C is applied to a thin,...Ch. 21 - Example 21.2: A positive point charge +q is at the...Ch. 21 - Example 21.2: A point charge q is at the center of...Ch. 21 - Example 21.2: A long, thin wire carrying uniform...Ch. 21 - Example 21.2: A long, thin wire canning uniform...Ch. 21 - Example 21.4: A long, straight wire carries a...Ch. 21 - Example 21.4: A long, thin rod carries charge...Ch. 21 - Example 21.4: An infinitely long rod carries a...Ch. 21 - Example 21.4: A 75.0-cm-long rod of diameter 2.54...Ch. 21 - Whats the flux through the hemispherical open...Ch. 21 - An electric field is given byE=E0(y/a)k, where E0...Ch. 21 - The electric field in a certain region is given by...Ch. 21 - A study shows that mammalian red blood cells...Ch. 21 - Positive charge is spread uniformly over the...Ch. 21 - A solid sphere 2.0 cm in radius carries a uniform...Ch. 21 - A point charge of 2Q is at the center of a...Ch. 21 - Prob. 51PCh. 21 - A spherical shell of radius R and negligible...Ch. 21 - A spherical shell 30 cm in diameter carries 85 C...Ch. 21 - A thick, spherical shell of inner radius a and...Ch. 21 - A long, thin wire carrying 5.6 nC/m runs down the...Ch. 21 - A long, solid rod of radius R carries a uniform...Ch. 21 - A solid rod 2.54 cm in diameter and 1.50 m long...Ch. 21 - If you painted positive charge on the floor, what...Ch. 21 - A charged slab extends infinitely in two...Ch. 21 - A solid sphere 10 cm in radius carries a 40-C...Ch. 21 - A nonconducting square plate 75 cm on a side...Ch. 21 - A 250-nC point charge is placed at the center of...Ch. 21 - An irregular conductor containing an irregular,...Ch. 21 - You measure the electric field strength at points...Ch. 21 - A point charge q is at the center of a spherical...Ch. 21 - A point charge q is at the center of a spherical...Ch. 21 - The volume charge density inside a solid sphere of...Ch. 21 - Figure 21.37 shows a rectangular box with sides 2a...Ch. 21 - The charge density within a charged sphere of...Ch. 21 - Calculate the electric fields in Example 21.2...Ch. 21 - A solid sphere of radius R carries a nonuniform...Ch. 21 - Problem 76 of Chapter 13 explored what happened to...Ch. 21 - An infinitely long solid cylinder of radius R...Ch. 21 - A solid sphere of radius R carries a uniform...Ch. 21 - Repeal Problem 59 for the case where the charge...Ch. 21 - Coaxial cables are widely used with audio-visual...Ch. 21 - A coaxial cable carries equal but opposite charges...Ch. 21 - How does the electric field between the conductors...Ch. 21 - Coaxial cables are widely used with audio-visual...
Additional Science Textbook Solutions
Find more solutions based on key concepts
(II) Two capacitors, C1 = 3200 pF and C2 = 1800 pF, are connected in series to a 12.0-V battery. The capacitors...
Physics for Scientists and Engineers with Modern Physics
11. The electric potential at a point that is halfway between two identical charged particles is 300 V. What is...
College Physics: A Strategic Approach (4th Edition)
30.36 A Radio Tuning Circuit. The minimum capacitance of a variable capacitor in a radio is 4.18 pF. (a) What i...
University Physics (14th Edition)
What do you think explains the placebo effect?
Conceptual Integrated Science
How might a star’s habitable zone be wider than we assume based on planets like Earth? What are orphan planets,...
Life in the Universe (4th Edition)
47(II) What gauge pressure in the water pipes is necessary if a fire hose is to spray water to a height of 16 m...
Physics: Principles with Applications
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- The volume charge density ρ for a spherical charge distribution of radius R= 6.00 mm is not uniform. (Figure 1) shows ρ as a function of the distance r from the center of the distribution. a)Calculate the electric field at r = 1.00 mm. b)Calculate the electric field at r = 1.00 mm.arrow_forwardThe charge density of a non-uniformly charged sphere of radius 1.0 m is given as: For rs 1.0 m; p(r)= Po(1-4r/3) For r> 1.0 m; p(r)= 0, where r is in meters. What is the value of r in meters for which the electric field is maximum?arrow_forwardThe bulk density of charge on a sphere of radius a is given by ρ = ρ0(1 + r/a), where ρ0 is a constant, and r is the radial distance measured from the center of the sphere. (a) Determine the total charge present on the sphere.(b) Calculate the electric field for points inside the sphere.arrow_forward
- A sphere of radius R carries a volume charge density given by ρ(r)=αr where r is the distance to the center of the sphere and α a positive constant. Determine the total charge carried by the sphere.arrow_forwardA circular metal plate of radius 17.2 cm carries a total charge of 1.01 μC and the charge is distributed uniformly over the surface of the plate. Determine the surface charge density on the plate and report your answer in µC/m².arrow_forwardThe volumetric charge density of a cylinder of radius R is proportional to the distance to the center of the cylinder, that is, ρ = Ar when r≤R, with A being a constant. (a) Sketch the charge density for the region - 3R < r < 3R. What is the dimension of A?b) Calculate the electric field for a point outside the cylinder, r > Rc) Calculate the electric field for a point inside the cylinder, r<R.d) Sketch Exrarrow_forward
- The volume charge density ρ for a spherical charge distribution of radius R = 6.00 mm is not uniform. The figure shows ρ as a function of the distance r from the center of the distribution. a) Calculate the electric field at r = 5.00 mm .Express your answer with the appropriate units. b) Calculate the electric field at r = 7.00 mm .Express your answer with the appropriate unitsarrow_forwardYou are working as an intern for a meteorological laboratory. You are out in the field taking measurements with a device that measures electric fields. You measure the electric field in the air immediately above the Earth's surface to be 139 N/C directed downward. (Assume the radius of the Earth is 6.37 x 106 m.) (a) Determine the surface charge density (in C/m²) on the ground. C/m? (b) Imagine the surface charge density is uniform over the planet. Determine the charge (in C) of the whole surface of the Earth. (e) Determine the Earth's electric potential (in V) due to the charge found in (b). V (d) Determine the difference in potential (in V) between the head and the feet of a person 1.50 m tall. (Ignore any charges in the atmosphere.) Varrow_forwardA solid nonconducting sphere of radius R = 6.7 cm has a nonuniform charge distribution of volume charge density ρ = (16.7 pC/m3)r/R, where r is radial distance from the sphere's center. (a) What is the sphere's total charge? What is the magnitude E of the electric field at (b) r = 0, (c) r = R/2.0, and (d) r = R? *I don't need answer a. * hint: Did you construct a Gaussian sphere through any given radial point, concentric with the actual sphere? What is the charge enclosed by the Gaussian sphere? (Do you see that with a variable density, integration is required?) Did you then apply Gauss' law to get the field?arrow_forward
- A solid nonconducting sphere of radius R = 6.7 cm has a nonuniform charge distribution of volume charge density ρ = (16.7 pC/m3)r/R, where r is radial distance from the sphere's center. (a) What is the sphere's total charge? What is the magnitude E of the electric field at (b) r = 0, (c) r = R/2.0, and (d) r = R?arrow_forwardCharge Q is distributed uniformly throughout the volume of an insulating sphere of radius R = 4.00 cm. At a distance of r = 8.00 cm from the center of the sphere, the electric field due to the charge distribution has magnitude E = 940 N/C. What are (a) the volume charge density for the sphere and (b) the electric field at a distance of 2.00 cm from the sphere’s center?arrow_forwardThe volume charge density of a sphere of Radius R is directly related to the radius of the sphere as given by the equation p(r) = br where b is a positive integer. What would be expression for the electric field at r = 1/2 R from the center of the sphere?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage Learning
Physics for Scientists and Engineers: Foundations...
Physics
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Cengage Learning
Electric Fields: Crash Course Physics #26; Author: CrashCourse;https://www.youtube.com/watch?v=mdulzEfQXDE;License: Standard YouTube License, CC-BY