Electrical Transformers and Rotating Machines
4th Edition
ISBN: 9781305494817
Author: Stephen L. Herman
Publisher: Cengage Learning
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Textbook Question
Chapter 21, Problem 11RQ
The short-circuit protective device supplying the motors in question #10 is an inverse-time circuit breaker. What size circuit breaker should be used?
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Question 5
The blower requires 20 kW to run at 350 rpm. The power is
transmitted by a v-belt shown in Figure 4 from an electric motor. The
diameter of the machine pulley is 650 mm and that of the motor
pulley is 330 mm. The centre distance between the pulleys is 1.2 m.
The contact angle of the belt is 150°. The safe pull in each belt is
900 N and the mass of the belt is 0.46 kg per meter length. The
coefficient of friction between the belt and the pulley is 0.25. The
belt should not exceed the speed of 1 800 m/min.
X1 = 16 mm
H= 6 mm
B
X2 = 7 mm
Figure 4: Cross sectional view of the v-belt
5.1. Calculate the velocity of the belt in m/s.
Determine the length of the belt.
Calculate the belt tensions.
5.2.
5.3.
Chapter 21 Solutions
Electrical Transformers and Rotating Machines
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- An open winding in an electric motor means that A. the winding is making contact with the motor frame. B. one winding is making contact with another winding. C. a wire in one winding is broken. D. the centrifugal switch to the start winding is open.arrow_forwardWhat are the three types of armature windings?arrow_forwardIs the resistance in the start winding greater or less than the resistance in the run winding?arrow_forward
- What type of field winding is made with many turns of small wire?arrow_forwardA 10 kVA transformer has a primary voltage of 208 volts and a secondary voltage of 120 volts. What size circuit breaker should be used to protect the primary winding?arrow_forwardThe secondary of the transformer in question #3 has a rated voltage of 2400 volts. What size fuse should be used to provide branch circuit protection?arrow_forward
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