(a)
Interpretation:
The equation for radioactive decay of
Concept Introduction:
Electron capture involves the absorption of electrons by the proton rich nucleus from the inner shells. During this process, the proton changes to neutron releasing an electron and
(a)
Answer to Problem 7E
The radioactive decay of
Explanation of Solution
The radioactive decay of
(As Ga has atomic number as 31)
While computing the mass numbers and
Mass Number: 68 + 0 =?
x = 68
Atomic number: 31 + (-1) =?
y= 30
Hence unknown element is
The radioactive decay of
(b)
Interpretation:
The equation for radioactive decay of
Concept Introduction:
Beta decay takes place when there is excess of protons or neutrons which gets transformed to other. In beta plus decay, proton gets converted to neutron releasing positron and neutrino. The emission of positron will decrease the atomic number by 1 with no changes in mass number.
(b)
Answer to Problem 7E
The radioactive decay of
Explanation of Solution
The radioactive decay of
While computing the mass numbers and atomic mass for unknown element, it is found that
Mass number: 62 = 0 +?
x = 62
Atomic Number: 29 =? + (1)
y= 28
Hence unknown element is
Hence, the overall equation for the radioactive decay of
(c)
Interpretation:
The equation for radioactive decay of
Concept Introduction:
Radioactive decay takes place when an atomic nucleus is unstable such that it gets converted to smaller stable nuclei emitting radiations like alpha, beta, and gamma. Release of alpha particle causes a decrease in mass number by 4 units and atomic number by 2 units.
(c)
Answer to Problem 7E
The radioactive decay of
Explanation of Solution
The radioactive decay of
While computing the mass numbers and atomic mass for unknown element, it is found that
Mass number: 212 = ?+4
x = 208
Atomic number: 87=? + 2
y= 85
Hence unknown element is
The radioactive decay of
Hence, the overall equation for the radioactive decay of
(d)
Interpretation:
The equation for radioactive decay of
Concept Introduction:
Radioactive decay releases radiations like alpha, beta and gamma, when unstable nuclei get converted to smaller stable fragments. The emission of β particle will increase the atomic number by 1 with no changes in mass number.
(d)
Answer to Problem 7E
The radioactive decay of
Explanation of Solution
The radioactive decay of
While computing the mass numbers and atomic mass for unknown element, it is found that
Mass number: 129 = x+ 0
x = 129
Atomic number: 51 = x + (- 1)
x= 52
Hence unknown element is
Hence, the overall equation for the radioactive decay of
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Chapter 20 Solutions
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