Explanation Given: Radii of curvatures of each germanium (Say isotope 1 to isotope 5), r 1 = 21.0 cm r 2 = 21.6 cm r 3 = 21.9 cm r 4 = 22.2 cm r 5 = 22.8 cm Atomic mass of 5 th isotope, m 5 = 76u Formula used: Radius of path produced by magnetic field in mass spectrometer r = m v q B ……….. (eq.1) Where, m → Mass of particle q → Charge of particle v → velocity of particle B → Applied magnetic field Calculation: Assuming velocity of detecting particle is same, we can rearrange eqn.1 as Atomic mass, m = q B v ⋅ r = C ⋅ r ( where C= q B v ) ……….. (eq.2) Now for isotope5 eqn.2 can be written as, m 5 = C ⋅ r 5 ⇒ 76 u = C ⋅ 22 .8cm ∴ C =3 ...

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Chapter 20, Problem 56P

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Atomic masses of germanium isotopes in a mass spectrometer

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