Physics
Physics
3rd Edition
ISBN: 9780073512150
Author: Alan Giambattista, Betty Richardson, Robert C. Richardson Dr.
Publisher: McGraw-Hill Education
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Chapter 20, Problem 42P

(a)

To determine

Number of turns on the solenoid.

(a)

Expert Solution
Check Mark

Answer to Problem 42P

Number of turns on the solenoid is 1.8×104.

Explanation of Solution

Write an expression for the number of turns on the solenoid.

  N=BLμ0I                                                                                                             (I)

Here, N is the number of turns in the solenoid, B is the magnetic field, L is the length of the solenoid μ0 is the permeability of free space and I is the current.

Conclusion:

Substitute 1.5T for B, 1.8m for L, 4π×107Tm/A for μ0 and 120A for I  in equation (I) to find N.

  N=(1.5T)(1.8m)(4π×107Tm/A)(120A)=2.7Tm(4π×107Tm/A)(120A)=1.8×104

Thus, the number of turns on the solenoid is 1.8×104.

(b)

To determine

The energy stored in the magnetic field during normal operation.

(b)

Expert Solution
Check Mark

Answer to Problem 42P

The energy stored in the magnetic field during normal operation is 620kJ.

Explanation of Solution

Write an expression for energy stored in the magnetic field during normal operation.

  UB=B22μ0π(d2)2L                                                                                                 (II)

Here, UB is energy stored in the magnetic field during normal operation and d is the diameter.

Conclusion:

Substitute 1.5T for B, 1.8m for L, 4π×107Tm/A for μ0 and 75cm for d  in equation (II) to find UB.

  UB=(1.5T)22(4π×107Tm/A)π((75cm)(1m102cm)2)2(1.8m)=(1.5T)22(4π×107Tm/A)π(0.35m)2(1.8m)=(620×103J)(1kJ103J)=620kJ

Thus, the energy stored in the magnetic field during normal operation is 620kJ.

(c)

To determine

The energy stored.

(c)

Expert Solution
Check Mark

Answer to Problem 42P

The energy stored is 110kJ.

Explanation of Solution

The energy stored is proportional to the square of the magnitude of magnetic field. The magnitude of magnetic field is proportional to the current. Thus, the energy stored is proportional to the square of the current.

Write an expression for the energy stored.

  UB=UBI2I2                                                                                               (III)

Here, UB is the energy stored and I is the current.

Conclusion:

Substitute 620kJ for UB, 120A for I  and 50A  for I in equation (III) to find UB.

  UB=(620kJ)(50A)2(120A)2=(25144)(620kJ)=110kJ

Thus, the energy stored is 110kJ.

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Chapter 20 Solutions

Physics

Ch. 20.6 - Practice Problem 20.7 An Ideal Transformer An...Ch. 20.7 - Conceptual Practice Problem 20.8 Choosing a Core...Ch. 20.9 - CHECKPOINT 20.9 Five solenoids are wound with...Ch. 20.9 - Practice Problem 20.9 Power in an Inductor The...Ch. 20.10 - Prob. 20.10CPCh. 20.10 - Prob. 20.10PPCh. 20 - Prob. 1CQCh. 20 - Prob. 2CQCh. 20 - Prob. 3CQCh. 20 - Prob. 4CQCh. 20 - Prob. 5CQCh. 20 - Prob. 6CQCh. 20 - Prob. 7CQCh. 20 - Prob. 8CQCh. 20 - Prob. 9CQCh. 20 - Prob. 10CQCh. 20 - Prob. 11CQCh. 20 - Prob. 12CQCh. 20 - Prob. 13CQCh. 20 - Prob. 14CQCh. 20 - Prob. 15CQCh. 20 - Prob. 16CQCh. 20 - Prob. 17CQCh. 20 - Prob. 18CQCh. 20 - Prob. 19CQCh. 20 - Prob. 1MCQCh. 20 - Prob. 2MCQCh. 20 - Prob. 3MCQCh. 20 - Prob. 4MCQCh. 20 - Prob. 5MCQCh. 20 - Prob. 6MCQCh. 20 - Prob. 7MCQCh. 20 - Prob. 8MCQCh. 20 - Prob. 9MCQCh. 20 - Prob. 10MCQCh. 20 - Prob. 1PCh. 20 - Prob. 2PCh. 20 - Prob. 3PCh. 20 - 4. In Fig. 20.2, what would the magnitude (in...Ch. 20 - Prob. 5PCh. 20 - 6. The armature of an ac generator is a circular...Ch. 20 - Prob. 7PCh. 20 - 8. A solid copper disk of radius R rotates at...Ch. 20 - 9. A horizontal desk surface measures 1.3 m × 1.0...Ch. 20 - 10. A square loop of wire, 0.75 m on each side,...Ch. 20 - 11. A long straight wire carrying a steady current...Ch. 20 - 12. A long straight wire carrying a current I is...Ch. 20 - Prob. 13PCh. 20 - 14. While I1 is increasing, what is the direction...Ch. 20 - 15. While I1 is constant, does current flow in...Ch. 20 - 16. A circular conducting coil with radius 3.40 cm...Ch. 20 - Prob. 17PCh. 20 - Prob. 18PCh. 20 - 19. In the figure, switch s is initially open. It...Ch. 20 - 20. Crocodiles are thought to be able to detect...Ch. 20 - 21. A bar magnet approaches a coil as shown, (a)...Ch. 20 - 22. Another example of motional emf is a rod...Ch. 20 - 23. Two loops of wire are next to each other in...Ch. 20 - 24. A dc motor has coils with a resistance of 16 Ω...Ch. 20 - Prob. 25PCh. 20 - Prob. 26PCh. 20 - Prob. 27PCh. 20 - Prob. 28PCh. 20 - 29. A doorbell uses a transformer to deliver an...Ch. 20 - Prob. 30PCh. 20 - 31. When the emf for the primary of a transformer...Ch. 20 - 32. A transformer with a primary coil of 1000...Ch. 20 - Prob. 33PCh. 20 - Prob. 34PCh. 20 - 35. A 2 m long copper pipe is held vertically....Ch. 20 - Prob. 36PCh. 20 - Prob. 37PCh. 20 - Prob. 38PCh. 20 - 39. A solenoid of length 2.8 cm and diameter 0.75...Ch. 20 - Prob. 40PCh. 20 - Prob. 41PCh. 20 - Prob. 42PCh. 20 - Prob. 43PCh. 20 - 44. The current in a 0.080 H solenoid increases...Ch. 20 - Prob. 45PCh. 20 - Prob. 46PCh. 20 - Prob. 47PCh. 20 - Prob. 48PCh. 20 - Prob. 49PCh. 20 - Prob. 50PCh. 20 - Prob. 51PCh. 20 - Prob. 52PCh. 20 - Prob. 53PCh. 20 - Prob. 54PCh. 20 - Prob. 55PCh. 20 - Prob. 56PCh. 20 - Prob. 57PCh. 20 - Prob. 58PCh. 20 - Prob. 59PCh. 20 - Prob. 60PCh. 20 - Prob. 61PCh. 20 - Prob. 62PCh. 20 - Prob. 63PCh. 20 - Prob. 64PCh. 20 - Prob. 65PCh. 20 - Prob. 66PCh. 20 - 67. Switch S2 has been closed for a long time, (a)...Ch. 20 - Prob. 68PCh. 20 - Prob. 69PCh. 20 - Prob. 70PCh. 20 - Prob. 71PCh. 20 - 72. A uniform magnetic field of magnitude 0.29 T...Ch. 20 - Prob. 73PCh. 20 - Prob. 74PCh. 20 - Prob. 75PCh. 20 - Prob. 76PCh. 20 - Prob. 77PCh. 20 - Prob. 78PCh. 20 - Prob. 79PCh. 20 - Prob. 80PCh. 20 - Prob. 81PCh. 20 - Prob. 82PCh. 20 - Prob. 83PCh. 20 - Prob. 84PCh. 20 - Prob. 85PCh. 20 - Prob. 86PCh. 20 - Prob. 87PCh. 20 - Prob. 88PCh. 20 - Prob. 89PCh. 20 - Prob. 90P
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