Chapter 20, Problem 20.51P

Interpretation Introduction

(a)

Interpretation:

How to carry out the given transformation is to be shown.

Concept introduction:

Lithium aluminum hydride ${\text{(LiAlH}}_{\text{4}})$ is a more powerful reducing agent than ${\text{NaBH}}_{\text{4}}$ and can thus reduce acid chlorides, acid anhydrides, and esters to primary alcohols, too. ${\text{LiAlH}}_{\text{4}}$ reduces carboxylic acids $\left({\text{RCO}}_{\text{2}}\text{H}\right)$ to primary alcohols and reduces amides $\left({\text{RCONR}}_{\text{2}}\right)$ to amines $\left({\text{RCH}}_{\text{2}}{\text{NR}}_{\text{2}}\right)$.

Interpretation Introduction

(b)

Interpretation:

How to carry out the given transformation is to be shown.

Concept introduction:

Lithium aluminum hydride ${\text{(LiAlH}}_{\text{4}})$ is a more powerful reducing agent than ${\text{NaBH}}_{\text{4}}$ and can thus reduce acid chlorides, acid anhydrides, and esters to primary alcohols, too. ${\text{LiAlH}}_{\text{4}}$ reduces carboxylic acids $\left({\text{RCO}}_{\text{2}}\text{H}\right)$ to primary alcohols and reduces amides.

Acid work up with ${\text{LiAlH}}_{\text{4}}$ prevents the reduction of C=C.