Physics for Scientists and Engineers
6th Edition
ISBN: 9781429281843
Author: Tipler
Publisher: MAC HIGHER
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Question
Chapter 2, Problem 91P
To determine
To find: Change in height of an object during successive time intervals falling from rest follows Galileo’s rule of odd numbers.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
A prankster flips a coin off of the Empire Building at a height of 1054 feet above the ground. The initial vertical velocity of the coin is 1.20m/s. In real life, air resistance would limit the maximum speed the coin can attain during its fall, but if air resistance were not a factor and assuming it has practically no horizontal motion, answer the following questions. (1 foot = 0.3048m)
a. What would the coin's velocity be when it hits the ground?
b. How long would it take to hit?
c. How high would the coin be halfway through the total falling time, and how fast would it be falling then?
In an experiment, a shearwater (a seabird) was taken from its nest, flown a distance 5040 km away, and released. It found its way back to its nest a time 12.4 days after release. If we place the origin in the nest and extend the +x-axis to the release point, what was the bird's average velocity for the return flight?
At the equator, the radius of the Earth is approximately 6370 km. A plane flies at a very low altitude at a constant speed of v = 278 m/s. Upon landing, the plane can produce an average deceleration of a = 21 m/s2.
What is the numeric value for the minimum landing distance, d (in meters), this plane needs to come to rest? Assume that when the plane touches the ground it is moving at the same speed as it was when it was flying.
Chapter 2 Solutions
Physics for Scientists and Engineers
Ch. 2 - Prob. 1PCh. 2 - Prob. 2PCh. 2 - Prob. 3PCh. 2 - Prob. 4PCh. 2 - Prob. 5PCh. 2 - Prob. 6PCh. 2 - Prob. 7PCh. 2 - Prob. 8PCh. 2 - Prob. 9PCh. 2 - Prob. 10P
Ch. 2 - Prob. 11PCh. 2 - Prob. 12PCh. 2 - Prob. 13PCh. 2 - Prob. 14PCh. 2 - Prob. 15PCh. 2 - Prob. 16PCh. 2 - Prob. 17PCh. 2 - Prob. 18PCh. 2 - Prob. 19PCh. 2 - Prob. 20PCh. 2 - Prob. 21PCh. 2 - Prob. 22PCh. 2 - Prob. 23PCh. 2 - Prob. 24PCh. 2 - Prob. 25PCh. 2 - Prob. 26PCh. 2 - Prob. 27PCh. 2 - Prob. 28PCh. 2 - Prob. 29PCh. 2 - Prob. 30PCh. 2 - Prob. 31PCh. 2 - Prob. 32PCh. 2 - Prob. 33PCh. 2 - Prob. 34PCh. 2 - Prob. 35PCh. 2 - Prob. 36PCh. 2 - Prob. 37PCh. 2 - Prob. 38PCh. 2 - Prob. 39PCh. 2 - Prob. 40PCh. 2 - Prob. 41PCh. 2 - Prob. 42PCh. 2 - Prob. 43PCh. 2 - Prob. 44PCh. 2 - Prob. 45PCh. 2 - Prob. 46PCh. 2 - Prob. 47PCh. 2 - Prob. 48PCh. 2 - Prob. 49PCh. 2 - Prob. 50PCh. 2 - Prob. 51PCh. 2 - Prob. 52PCh. 2 - Prob. 53PCh. 2 - Prob. 54PCh. 2 - Prob. 55PCh. 2 - Prob. 56PCh. 2 - Prob. 57PCh. 2 - Prob. 58PCh. 2 - Prob. 59PCh. 2 - Prob. 60PCh. 2 - Prob. 61PCh. 2 - Prob. 62PCh. 2 - Prob. 63PCh. 2 - Prob. 64PCh. 2 - Prob. 65PCh. 2 - Prob. 66PCh. 2 - Prob. 67PCh. 2 - Prob. 68PCh. 2 - Prob. 69PCh. 2 - Prob. 70PCh. 2 - Prob. 71PCh. 2 - Prob. 72PCh. 2 - Prob. 73PCh. 2 - Prob. 74PCh. 2 - Prob. 75PCh. 2 - Prob. 76PCh. 2 - Prob. 77PCh. 2 - Prob. 78PCh. 2 - Prob. 79PCh. 2 - Prob. 80PCh. 2 - Prob. 81PCh. 2 - Prob. 82PCh. 2 - Prob. 83PCh. 2 - Prob. 84PCh. 2 - Prob. 85PCh. 2 - Prob. 86PCh. 2 - Prob. 87PCh. 2 - Prob. 88PCh. 2 - Prob. 89PCh. 2 - Prob. 90PCh. 2 - Prob. 91PCh. 2 - Prob. 92PCh. 2 - Prob. 93PCh. 2 - Prob. 94PCh. 2 - Prob. 95PCh. 2 - Prob. 96PCh. 2 - Prob. 97PCh. 2 - Prob. 98PCh. 2 - Prob. 99PCh. 2 - Prob. 100PCh. 2 - Prob. 101PCh. 2 - Prob. 102PCh. 2 - Prob. 103PCh. 2 - Prob. 104PCh. 2 - Prob. 105PCh. 2 - Prob. 106PCh. 2 - Prob. 107PCh. 2 - Prob. 108PCh. 2 - Prob. 109PCh. 2 - Prob. 110PCh. 2 - Prob. 111PCh. 2 - Prob. 112PCh. 2 - Prob. 113PCh. 2 - Prob. 114PCh. 2 - Prob. 115PCh. 2 - Prob. 116PCh. 2 - Prob. 117PCh. 2 - Prob. 118PCh. 2 - Prob. 119PCh. 2 - Prob. 120PCh. 2 - Prob. 121PCh. 2 - Prob. 122P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- The position of a particle is given by r →(t) = A (cos ωti ^ + sin ωtj ^), where ω is a constant. (a) Show that the particle moves in a circle of radius A. (b) Calculate d r → /dt and then show that the speed of the particle is a constant Aω. (c) Determine d2 r → /dt2 and show that a is given by ac = rω2. (d) Calculate the centripetal force on the particle. [Hint: For (b) and (c), you will need to use (d/dt)(cos ωt) = −ω sin ωt and (d/dt)(sin ωt) = ω cos ωt.arrow_forwardSuppose we are told that the acceleration a of a particle moving with uniform speed ν in a circle of radius r is proportional to some power of r, say rn, and some power of ν, say νm. Determine the values of n and m and write the simplest form of an equation for the acceleration.arrow_forwardA falling stone takes Δt = 0.38 s to travel past a window 2.2 m tall (see the (Figure 1)). From what height above the top of the window did the stone fall? Express your answer to two significant figures and include the appropriate units.arrow_forward
- A ball is thrown into the air by a baby alien on a planet in the system of Alpha Centauri with a velocity of 44 ft/s. Its height in feet after t seconds is given by y = 44t - 23t². A. Find the average velocity for the time period beginning when t = 2 and lasting .01 s: .005 s: .002 s: .001 s: NOTE: For the above answers, you may have to enter 6 or 7 significant digits if you are using a calculator. B. Estimate the instantaneous velocity when t = 2. Answer:arrow_forwardIt has been pointed out that if tunnels could be drilled straight through the earth between points on the surface, trains could travel between those points using gravitational force for acceleration and deceleration. (The effects of friction and aerodynamic drag could be minimized by evacuating the tunnels andusing magnetically levitated trains.) Suppose that such a train travels from the North Pole to a point on the equator. Determine the magnitude of the velocity of the train (a) when it arrives at the equator and (b) when it is halfway from the North Pole to the equator. The radius of the earth is Re = 3960 mi.arrow_forwardThe position of a particle in the xy-plane at time t is r(t) = (e¹) 1 + (40 e²¹) ₁. particle. Then find the particle's velocity and acceleration vectors at t = In 7. The equation for the path of the particle is y= j. Find an equation in x and y whose graph is the path of thearrow_forward
- When we estimate distances from velocity data, it is sometimes necessary to use times t0, t1, t2, t3, . . . that are not equally spaced. We can still estimate distances using the time periods Δti = ti − ti − 1. For example, a space shuttle was launched on a mission, the purpose of which was to install a new motor in a satellite. The table provided gives the velocity data for the shuttle between liftoff and the jettisoning of the solid rocket boosters. Use these data to estimate the height, h, above Earth's surface of the space shuttle, 62 seconds after liftoff. (Give the upper approximation available from the data.)h = ft Event Time (s) Velocity (ft/s) Launch 0 0 Begin roll maneuver 10 180 End roll maneuver 15 319 Throttle to 89% 20 442 Throttle to 67% 32 742 Throttle to 104% 59 1217 Maximum dynamic pressure 62 1430 Solid rocket booster separation 125 4052arrow_forwardExternal stimuli are communicated to the brain by means of electrical signals propagating along with nerve cells at a speed of approximately 30 m/s. Similarly, electrical messages are sent at the same speed from the brain along with nerve cells to the muscles. Reflex actions are controlled by a relatively simple nerve circuit from a muscle to the spine and back to the muscle. Estimate the reflex time for a stimulus at the knee. (Assume that the signal resulting from the stimulus must travel a distance Δs = 1 m.)arrow_forwardHigh-speed motion pictures (3500 frames/second) of a jumping 230 μg flea yielded the data to plot the flea's acceleration as a function of time as shown in the figure ( Figure 1). (See "The Flying Leap of the Flea," by M. Rothschild et al. in the November 1973 Scientific American.) This flea was about 2 mm long and jumped at a nearly vertical takeoff angle. Use the measurements shown on the graph to answer the questions. Figure alg 150 100 50 0 0 0.5 1.0 1.5 Part E Use the graph to find the flea's maximum speed. Express your answer in meters per second to two significant figures. IVE] ΑΣΦ 3 v=1.6 Submit Previous Answers Request Answer ? X Incorrect; Try Again; 2 attempts remaining m/sarrow_forward
- A falling object experiment is performed to determine the acceleration due to gravity on an unknown planet (not the Earth) from photographic data of the falling object.At time = 0 seconds, the object's displacement is 0 m.At time = 0.4 seconds, the object's displacement is 1.9 m.From the above information, calculate the value of the acceleration due to gravity on the unknown planet.arrow_forwardA proton in a synchrotron is moving in a circle of radius 1 km and increasing its speed by v(t) = c1 + c2 t2, where c1 = 2.0 × 105 m/s, c2 = 105 m/s3. (a) What is the proton’s total acceleration at t = 5.0 s? (b) At what time does the expression for the velocity become unphysical?arrow_forwardA magnetic field forces an electron to move in a circle with radial acceleration 3.0 * 1014 m/s2. (a) What is the speed of the electron if the radius of its circular path is 15 cm? (b)What is the period of the motion?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Relative Velocity - Basic Introduction; Author: The Organic Chemistry Tutor;https://www.youtube.com/watch?v=_39hCnqbNXM;License: Standard YouTube License, CC-BY