Universe: Stars And Galaxies
6th Edition
ISBN: 9781319115098
Author: Roger Freedman, Robert Geller, William J. Kaufmann
Publisher: W. H. Freeman
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Chapter 2, Problem 57Q
To determine
The reason for the difference between the time given by a sundial and a wristwatch.
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The earth revolves around the sun in exactly 365 1/4 days which is equivalent to 1 year. To make up for the loss of 1/4 day, the calendar was adjusted so that we have a leap year for every 4 years. If the earth were to speed in its motion slightly so that a year would be completed in exactly 365 days and 6 hours, how often would we need to have a leap year?
What should be the duration of the year
if the distance between the earth and the sun
gets doubled?
2) Calculate the difference in the geostationary altitude ( in km ) by by using solar day (24 hrs) and sidereal day (23hrs 56mins and 41 secs)
129.768
64.884
32.442
1000
Chapter 2 Solutions
Universe: Stars And Galaxies
Ch. 2 - Prob. 1QCh. 2 - Prob. 2QCh. 2 - Prob. 3QCh. 2 - Prob. 4QCh. 2 - Prob. 5QCh. 2 - Prob. 6QCh. 2 - Prob. 7QCh. 2 - Prob. 8QCh. 2 - Prob. 9QCh. 2 - Prob. 10Q
Ch. 2 - Prob. 11QCh. 2 - Prob. 12QCh. 2 - Prob. 13QCh. 2 - Prob. 14QCh. 2 - Prob. 15QCh. 2 - Prob. 16QCh. 2 - Prob. 17QCh. 2 - Prob. 18QCh. 2 - Prob. 19QCh. 2 - Prob. 20QCh. 2 - Prob. 21QCh. 2 - Prob. 22QCh. 2 - Prob. 23QCh. 2 - Prob. 24QCh. 2 - Prob. 25QCh. 2 - Prob. 26QCh. 2 - Prob. 27QCh. 2 - Prob. 28QCh. 2 - Prob. 29QCh. 2 - Prob. 30QCh. 2 - Prob. 31QCh. 2 - Prob. 32QCh. 2 - Prob. 33QCh. 2 - Prob. 34QCh. 2 - Prob. 35QCh. 2 - Prob. 36QCh. 2 - Prob. 37QCh. 2 - Prob. 38QCh. 2 - Prob. 39QCh. 2 - Prob. 40QCh. 2 - Prob. 41QCh. 2 - Prob. 42QCh. 2 - Prob. 43QCh. 2 - Prob. 44QCh. 2 - Prob. 45QCh. 2 - Prob. 46QCh. 2 - Prob. 47QCh. 2 - Prob. 48QCh. 2 - Prob. 49QCh. 2 - Prob. 50QCh. 2 - Prob. 51QCh. 2 - Prob. 52QCh. 2 - Prob. 53QCh. 2 - Prob. 54QCh. 2 - Prob. 55QCh. 2 - Prob. 56QCh. 2 - Prob. 57QCh. 2 - Prob. 58QCh. 2 - Prob. 59QCh. 2 - Prob. 60QCh. 2 - Prob. 61Q
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- Consider a calendar based entirely on the day and the month (the Moon’s period from full phase to full phase). How many days are there in a month? Can you figure out a scheme analogous to leap year to make this calendar work?arrow_forwardIn a part of Earth’s orbit where Earth is moving faster than usual around the Sun, would the length of the sidereal day change? If so, how? Explain.arrow_forwardOn the day of the vernal equinox, the day length for all places on Earth is actually slightly longer than 12 hours. Explain why.arrow_forward
- What would be duration of year, if distance Between earth & the sun got doubled? 10 129 days w 365 days (01) 500 days (iv) 1032 daysarrow_forwardEx. 10 : What would have be the duration of the year if the distance between earth and sun were half the present distance ?arrow_forwardWhen it is 12 noon in London, what is the standard time in Honolulu, Hawaii? I’m confused on how I find this answer on my own without a formula?arrow_forward
- Tonight you see a waning crescent in the night sky. A few (n) days later, the night is once again clear and you see a waning crescent. How many degrees did the Moon advance in its orbit during this time frame?arrow_forwardWhat would be the duration of the year if the distance between the earth and the sun gets tripled.arrow_forwardThe Earth covers about 1° per day in its orbit about the Sun, and the solar day is slightly longer than the sidereal day. If Earth spun in a retrograde direction like Venus but it still had the same sidereal period (23 hr 56 min), how long would the solar day be? The solar day would be 72 hr and min.arrow_forward
- What is the difference between a sidereal month and a synodic month? Which is longer? Why?arrow_forwardConsider a planet of radius 10 x 106 m for which the length of a sidereal day is 5 x 104 s. Calculate the speed you would have with respect to the center of the planet, in m/s, if you were at a latitude of 5 degrees north. (Please answer to the fourth decimal place - i.e 14.3225)arrow_forwardRight Ascension and Declination is a coordinate system for objects in the sky, and is analogous to longitude and latitude coordinates, respectively, for objects on Earth. Right ascension (RA) coordinates are given in hours (h), minutes (m), and seconds (s). Declination (DEC) coordinates are given in degrees (°), arcminutes ('), and arcseconds ("). Sirius is the brightest star in the night sky. Its RA and DEC coordinates are 6h 45 m 7.96 s and -16° 44' 78.6". Using unit conversion, find the RA coordinate only in hours and round the coordinate to 5 significant figures.arrow_forward
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