Chapter 2, Problem 42Q

To determine

The angle between the two stars, measured in degrees, if for one star $\text{R}\text{.A}\text{.}={\text{8}}^{\text{h}}{\text{0}}^{\text{m}}{\text{0}}^{\text{s}}$, $\text{Decl}\text{.}=\text{0}{°}^{}\text{0}{\prime }^{}\text{0}{″}^{}$ and for the other star $\text{R}\text{.A}\text{.}={11}^{\text{h}}{\text{20}}^{\text{m}}{\text{0}}^{\text{s}}$, $\text{Decl}\text{.}=\text{0}{°}^{}\text{0}{\prime }^{}\text{0}{″}^{}$. Given that 24 hours of right ascension is equal to $360°$ of the celestial equator.