Computer Science Illuminated
7th Edition
ISBN: 9781284155617
Author: Nell Dale, John Lewis
Publisher: Jones & Bartlett Learning
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Question
Chapter 2, Problem 32E
Program Plan Intro
a.
Decimal numbers:
- A decimal number is a number in which the whole number part and the fractional part is separated by a decimal point.
- The dot is known as a decimal point of a decimal number.
- Hence decimal numeral system is a method for representing both integer and non-integer numbers.
Octal numbers:
- Octal number system is also known as base 8 number system and uses the digits 0 to 7.
- These are made from binary numerals by grouping consecutive binary digits into three groups starting from the right.
- Octal numbers also make it easy to write large binary numbers into smaller groups.
Explanation of Solution
b.
Conversion of decimal number 321 into octal value:
- Since it is octal, divide the number 321 by 8 repeatedly. It returns 40 as quotient and 1 as remainder.
- Now divide 40 by 8 and it returns 5 as quotient and 0 as remainder.
- Now divide 5 by 8 and it is not possible as 5 is less than 8...
Explanation of Solution
c.
Conversion of decimal number 1492 into octal number:
- Since it is octal, divide the number 1492 by 8 repeatedly. It returns 186 as quotient and 4 as remainder.
- Now divide 186 by 8 and it returns 23 as quotient and 2 as remainder.
- Now divide 23 by 8 and it returns 2 as quotient and 7 as remainder...
Explanation of Solution
d.
Conversion of decimal number 1066 into octal number:
- Since it is octal, divide the number 1066 by 8 repeatedly. It returns 133 as quotient and 2 as remainder.
- Now divide 133 by 8 and it returns 16 as quotient and 5 as remainder.
- Now divide 16 by 8 and it returns 2 as quotient and 0 as remainder...
Explanation of Solution
e.
Conversion of decimal number 2001 into octal number:
- Since it is octal, divide the number 2001 by 8 repeatedly. It returns 250 as quotient and 1 as remainder.
- Now divide 250 by 8 and it returns 31 as quotient and 2 as remainder.
- Now divide 31 by 8 and it returns 3 as quotient and 7 as remainder...
Expert Solution & Answer
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Chapter 2 Solutions
Computer Science Illuminated
Ch. 2 - Prob. 1ECh. 2 - Prob. 2ECh. 2 - Prob. 3ECh. 2 - Prob. 4ECh. 2 - Prob. 5ECh. 2 - Prob. 6ECh. 2 - Prob. 7ECh. 2 - Prob. 8ECh. 2 - Prob. 9ECh. 2 - Prob. 10E
Ch. 2 - Prob. 11ECh. 2 - Prob. 12ECh. 2 - Prob. 13ECh. 2 - Prob. 14ECh. 2 - Prob. 15ECh. 2 - Prob. 16ECh. 2 - Prob. 17ECh. 2 - Prob. 18ECh. 2 - Prob. 19ECh. 2 - Prob. 20ECh. 2 - Prob. 21ECh. 2 - Prob. 22ECh. 2 - Prob. 23ECh. 2 - Prob. 24ECh. 2 - Prob. 25ECh. 2 - Prob. 26ECh. 2 - Prob. 27ECh. 2 - Prob. 28ECh. 2 - Prob. 29ECh. 2 - Prob. 30ECh. 2 - Prob. 31ECh. 2 - Prob. 32ECh. 2 - Prob. 33ECh. 2 - Prob. 34ECh. 2 - Prob. 35ECh. 2 - Prob. 36ECh. 2 - Prob. 38ECh. 2 - Prob. 39ECh. 2 - Prob. 40ECh. 2 - Prob. 41ECh. 2 - Prob. 42ECh. 2 - Prob. 43ECh. 2 - Prob. 44ECh. 2 - Prob. 45ECh. 2 - Prob. 46ECh. 2 - Prob. 47ECh. 2 - Prob. 1TQCh. 2 - Prob. 2TQCh. 2 - Prob. 3TQCh. 2 - Prob. 4TQ
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