Concept explainers
(a)
Interpretation:
Out of the compounds
Concept Introduction:
Electronegativity is the inherent property of any element in a certain compound that allows it to attract the unshared electron pairs towards itself. In any polar covalent bond, the difference in electronegativities gives rise to partial positive and negative charges respectively on the cation and anions. The ionic character of a polar covalent bond is determined on the basis of difference in electronegativities. If the difference exceeds 2, the compound is regarded as predominantly ionic otherwise it is primarily covalent.
(b)
Interpretation:
Out of the compounds
Concept Introduction:
Refer to part (a).
(c)
Interpretation:
Out of the compounds
Concept Introduction:
Refer to part (a).
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CHEMICAL PRINCIPLES (LL) W/ACCESS
- Acetylene 1C2H22 and nitrogen 1N22 both contain a triplebond, but they differ greatly in their chemical properties.(a) Write the Lewis structures for the two substances. (b) Byreferring to Appendix C, look up the enthalpies of formationof acetylene and nitrogen. Which compound is more stable?(c) Write balanced chemical equations for the completeoxidation of N2 to form N2O51g2 and of acetylene to formCO21g2 and H2O1g2. (d) Calculate the enthalpy of oxidationper mole for N2 and for C2H2 (the enthalpy of formationof N2O51g2 is 11.30 kJ>mol). (e) Both N2 and C2H2 possesstriple bonds with quite high bond enthalpies (Table 8.3).Calculate the enthalpy of hydrogenation per mole for bothcompounds: acetylene plus H2 to make methane, CH4;nitrogen plus H2 to make ammonia, NH3.arrow_forwardFrom their Lewis structures, determine the number of sand p bonds in each of the following molecules or ions:(a) CO2; (b) cyanogen, 1CN22; (c) formaldehyde, H2CO;(d) formic acid, HCOOH, which has one H and two O atomsattached to C.arrow_forward(a) Triazine, C3 H3 N3, is like benzene except that in triazineevery other C¬H group is replaced by a nitrogen atom.Draw the Lewis structure(s) for the triazine molecule. (b) Estimatethe carbon–nitrogen bond distances in the ring.arrow_forward
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- Acetylene (C2H2) and nitrogen (N2) both contain a triplebond, but they differ greatly in their chemical properties.(a) Write the Lewis structures for the two substances. (b) By referring to Appendix C, look up the enthalpies of formationof acetylene and nitrogen. Which compound is more stable?(c) Write balanced chemical equations for the completeoxidation of N2 to form N2O5(g) and of acetylene to formCO2(g) and H2O(g). (d) Calculate the enthalpy of oxidationper mole for N2 and for C2H2 (the enthalpy of formationof N2O5(g) is 11.30 kJ/mol). (e) Both N2 and C2H2 possesstriple bonds with quite high bond enthalpies (Table 8.3).Calculate the enthalpy of hydrogenation per mole for bothcompounds: acetylene plus H2 to make methane, CH4;nitrogen plus H2 to make ammonia, NH3.arrow_forwardKeeping in mind that some elements violate the octet rule, draw a Lewis structure for each compound: (a) BeH 2; (b) PCl 5.arrow_forward(a) What are trihalomethanes (THMs)? (b) Draw the Lewisstructures of two example THMs.arrow_forward
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- Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning