Microbiology with Diseases by Taxonomy (5th Edition)
5th Edition
ISBN: 9780134019192
Author: Robert W. Bauman Ph.D.
Publisher: PEARSON
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Chapter 2, Problem 2CT
Summary Introduction
To explain:
The reason for the name given to the reaction “dehydrogenation” is an appropriate one.
Introduction:
A
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at room temperature, amino acids are solids with relatively high decomposition points. explain why
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O Erythrose is ketose while eythrulose is an aldose
Erythrose bears the ketone group while erythrulose bears the aldehyde group.
What is the name of the process of the interconversion of the aldose and ketose
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tautomerization
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Chapter 2 Solutions
Microbiology with Diseases by Taxonomy (5th Edition)
Ch. 2 - Electrons zip around the nucleus at about 5...Ch. 2 - Chlorine and potassium atoms form ionic bonds,...Ch. 2 - Why are decomposition reactions exothermic, that...Ch. 2 - Why does the neutralization of an acid by a base...Ch. 2 - Prob. 5TMWCh. 2 - Prob. 1MCCh. 2 - Prob. 2MCCh. 2 - Prob. 3MCCh. 2 - Prob. 4MCCh. 2 - Which of the following terms most correctly...
Ch. 2 - Prob. 6MCCh. 2 - Prob. 7MCCh. 2 - Prob. 8MCCh. 2 - Prob. 9MCCh. 2 - Prob. 10MCCh. 2 - Prob. 1FIBCh. 2 - Prob. 2FIBCh. 2 - Prob. 3FIBCh. 2 - Prob. 4FIBCh. 2 - Prob. 5FIBCh. 2 - Prob. 6FIBCh. 2 - Reactions that release energy are called...Ch. 2 - Prob. 8FIBCh. 2 - Prob. 9FIBCh. 2 - Prob. 10FIBCh. 2 - Prob. 1VICh. 2 - Prob. 2VICh. 2 - Prob. 1SACh. 2 - Prob. 2SACh. 2 - Prob. 3SACh. 2 - Prob. 4SACh. 2 - Prob. 5SACh. 2 - Prob. 1CTCh. 2 - Prob. 2CTCh. 2 - Prob. 3CTCh. 2 - Prob. 4CTCh. 2 - Prob. 5CTCh. 2 - Prob. 6CTCh. 2 - Prob. 7CTCh. 2 - Prob. 8CTCh. 2 - Prob. 9CTCh. 2 - Prob. 10CTCh. 2 - Prob. 11CTCh. 2 - Prob. 12CTCh. 2 - Prob. 13CTCh. 2 - Prob. 14CTCh. 2 - A textbook states that only five nucleotide bases...Ch. 2 - Using the following terms, fill in the following...Ch. 2 - Prob. 1CCS
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- An excess of ketone bodies in the blood causes ketoacidosis. Consider the chemical structure of the ketone bodies (only two out of the three ketone bodies cause this effect) and explain why they are acids.arrow_forwardClassify each of the following sugar pairs as enantiomers, diastereomers, epimers, or an aldose–ketose pair. a. D-erythrose and D-threose b. D-glucose and D-mannose c. D-ribose and L-ribose d. D-allose and D-galactose e. D-glyceraldehyde and dihydroxyacetonearrow_forwardChain Shortening of monosaccharides can be done in the laboratory thru Kiliani-Fischer reaction. True Falsearrow_forward
- Do you agree or disagree with the following statements? Explain your answer. Neutralizing the negative charge on the carbohydrate portions of a proteoglycan should cause the ECM that houses the proteoglycan to become more liquefied.arrow_forwardIdentify whether each monosaccharide is an aldose or a ketose. Н НО Н Н НО- CHO ОН H -ОН ОН CH2OH CH2OH H CH₂OH Н НО Н CHO ОН CHO H -ОН CH₂OH н-с ОН CH2OH Н Н Н Н· CH2OH C=0 ОН CH2OH ... CHO ОН ОН ОН CH2OH Но Н Н Н CH2OH c=0 -Н -ОН CH2OH CH2OH О ОН ОН CH2OHarrow_forwardMonosaccharides can be chemically modified by a variety of reactions. Aldoses can be by Tollen's reagent or Benedict's reagent. Monosaccarides can react with carboxylic acids, phosphoric acid, or sulfuric acid to form The hydroxyl group on carbon two can be replaced with a group to form sugars.arrow_forward
- Glucose and fructose are reducing sugars. Sucrose, or table sugar, is a disaccharide consisting of both fructose and glucose. Is sucrose a reducing sugar? Explain.arrow_forwardWhat role does glycoprotein play in the body? Briefly explain.arrow_forwardAn oligosaccharide is a repeating unit of a-D-galactopyranosyl-(a-1 >3)-allopyranoside. Each disaccharide unit is linked via B-1 --->4 glycosidic bond. The oligosaccharide has 10 monosaccharide residues. Required: Is this oligosaccharide a good substrate for glycolysis? Why or why not? Provide two reasons and discuss corn prehensively.arrow_forward
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