Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN: 9780134580999
Author: Elaine N. Marieb, Katja N. Hoehn
Publisher: PEARSON
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- Classify each monosaccharide by using the type of carbonyl group and the number of carbons in the chain. Select the single best answer for each part. Part 1 of 3 Classify galactose. H. H- -OH HO- H HO -H H OH CH₂OH aldopentose Oketopentose O aldohexose O aldotetrose ketotetrose Oketohexose Part 2 of 3 Classify tagatose. CH₂OH HO H HO H H OH CH₂OH Oketotetrose aldopentose O aldotetrose Oketohexose O aldohexose Oketopentose Part 3 of 3 Classify altrose. H HO H H OH H- -OH H -OH снон O aldopentose Oketohexose Oketotetrose aldohexose Oketopentose aldotetrosearrow_forwardWhat products are formed by the enzymatic hydrolysis of starch? How can you tell the enzymatic hydrolysis of starch is complete?arrow_forwardPlease note the image question below. CH₂OH ç-o CH₂OPO Dihydroxyacetone phosphate triose phosphate isomerase O True O False H HCOH CH₂OPO Glyceraldehyde 3-phosphate This is a change in configuration because isomers can only be interconverted by temporarily breaking covalent bonds.arrow_forward
- Modify the mannose structures provided to show the structure of a disaccharide formed from two mannose units joined by a 1. →>> • 6-B-glycosidic linkage. Снон Н Он H Он H Н ОН Он ОН Он Он H Он H H H Н Нarrow_forwardYou find a novel monosaccharide that contains 4 carbons, with a carbonyl group present at carbon 1 (ie. the first carbon). How should you classify this monosaccharide? O ketopentose Oketotetrose O aldopentose Oaldotriose O ketotriose aldotetrosearrow_forwardExplain in detail the condensation reactions to form Maltose and Sucrose from their monosaccharides.arrow_forward
- Copper ions present in Benedict’s reagent react with the free end of any reducing sugars, such as glucose, when heated. Originally blue in color, these copper ions are reduced by the sugar and produce an orange-red colored precipitate. Alternatively, iodine-potassium iodide (IKI) may also be used when working with starch. IKI contains special tri-iodine ions which interact with the coiled structure of a starch polymer. Prior to a reaction, the IKI displays a yellow-brown color; however, after reacting with starch, a dark purple or black color is presented. The molecule pictured below produced a blue color when tested with Benedict’s reagent, a yellow color when tested with IKI, and a violet color when tested with Biuret reagent. Based on the structure shown below and these chemical results, what kind of biomolecule is this?arrow_forwardAlthough the first two carbons of fructose and glucose are identical in structure to DHAP and GADP (from glycolysis), DHAP and GADP equilibriate on their in solution to favor the ketone over the aldehyde, while fructose and glucose do not. Why? a)The larger size of the molecule sterically hinders the isomerization b)The larger sugars have more OH groups which hydrogen bond and disrupt isomerization c)The larger sugars cyclize, and there is no carbonyl to isomerize in the cyclic form d)The larger sugars cyclize, and in the cyclic form the hydrogen bonding is very strong e)The larger sugars are less soluble in water than the smaller sugarsarrow_forwardConsider the disaccharide maltose. сон H -= H OH OH Part 1 of 2 д- CH₂OH H H H он Н Н д- ОН Н Он Н Он Classify the glycosidic linkage as a or ẞ. Select the single best answer. α В Part: 1/2 Part 2 of 2 Modify the structure of maltose to show the monosaccharide products that form from hydrolysis. You may draw the structures in any arrangement th you like, so long as they aren't touching. Н он Снон Н -= Он Н снон Н H H Он Н д- Н он -= Н Он H Онarrow_forward
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