Explanation It is given that the number of moles of CO 2 is 2 .0 mol . The constant pressure is 1.2 5 atm . The temperature increases from 250 K to 277 K . The molar heat capacity ( C p ) of CO 2 is 37 .11 J K − 1 mol − 1 . The heat is given at constant pressure. Therefore, q p = Δ H (1) At constant pressure, the change in enthalpy is given by expression, Δ H = n × C p × Δ T (2) Substitute the values of number of moles, molar heat capacity and change in temperature in the above formula to calculate the change in enthalpy. Δ H = 2. 0 mol × 37.11 J K − 1 mol − 1 × ( 277 K − 250 K ) Δ H = 74.22 J K − 1 × 27 K Δ H = 2 0 0 3 . 9 4 J _ Hence, values of q and Δ H are 2 0 0 3 . 9 4 J _ and 2 0 0 3

11th Edition

ISBN: 9780198814740

Author: ATKINS, P. W. (peter William), 1940- (author.)

Publisher: Oxford University Press,

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Chapter 2, Problem 2B.4BE

Interpretation Introduction

Interpretation: The values of q, ΔU and ΔH have to be calculated when the temperature is increases from 250 K to 277 K.

Concept introduction: The system is said to have gone through a process when the initial state is changed to the final state. The properties of the system such as temperature, pressure, enthalpy, entropy are changes in thermodynamic process.

Thermodynamics address temperature and heat and their relationship to work, energy and matter. Work is defined as the form of mechanical energy that is transferred from system to another.

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Chapter 2 Solutions

Atkins' Physical chemistry

Ch. 2 - Prob. 2A.1ST Ch. 2 - Prob. 2B.1ST Ch. 2 - Prob. 2B.2ST Ch. 2 - Prob. 2C.1ST Ch. 2 - Prob. 2C.2ST Ch. 2 - Prob. 2D.1ST Ch. 2 - Prob. 2D.2ST Ch. 2 - Prob. 2A.1DQ Ch. 2 - Prob. 2A.2DQ Ch. 2 - Prob. 2A.3DQ

Ch. 2 - Prob. 2A.4DQ Ch. 2 - Prob. 2A.5DQ Ch. 2 - Prob. 2A.1AE Ch. 2 - Prob. 2A.1BE Ch. 2 - Prob. 2A.2AE Ch. 2 - Prob. 2A.2BE Ch. 2 - Prob. 2A.3AE Ch. 2 - Prob. 2A.3BE Ch. 2 - Prob. 2A.4AE Ch. 2 - Prob. 2A.4BE Ch. 2 - Prob. 2A.5AE Ch. 2 - Prob. 2A.5BE Ch. 2 - Prob. 2A.6AE Ch. 2 - Prob. 2A.6BE Ch. 2 - Prob. 2A.1P Ch. 2 - Prob. 2A.2P Ch. 2 - Prob. 2A.3P Ch. 2 - Prob. 2A.4P Ch. 2 - Prob. 2A.5P Ch. 2 - Prob. 2A.6P Ch. 2 - Prob. 2A.7P Ch. 2 - Prob. 2A.8P Ch. 2 - Prob. 2A.9P Ch. 2 - Prob. 2A.10P Ch. 2 - Prob. 2B.1DQ Ch. 2 - Prob. 2B.2DQ Ch. 2 - Prob. 2B.1AE Ch. 2 - Prob. 2B.1BE Ch. 2 - Prob. 2B.2AE Ch. 2 - Prob. 2B.2BE Ch. 2 - Prob. 2B.3AE Ch. 2 - Prob. 2B.3BE Ch. 2 - Prob. 2B.4AE Ch. 2 - Prob. 2B.4BE Ch. 2 - Prob. 2B.1P Ch. 2 - Prob. 2B.2P Ch. 2 - Prob. 2B.3P Ch. 2 - Prob. 2B.4P Ch. 2 - Prob. 2B.5P Ch. 2 - Prob. 2C.1DQ Ch. 2 - Prob. 2C.2DQ Ch. 2 - Prob. 2C.3DQ Ch. 2 - Prob. 2C.4DQ Ch. 2 - Prob. 2C.1AE Ch. 2 - Prob. 2C.1BE Ch. 2 - Prob. 2C.2AE Ch. 2 - Prob. 2C.2BE Ch. 2 - Prob. 2C.3AE Ch. 2 - Prob. 2C.3BE Ch. 2 - Prob. 2C.4AE Ch. 2 - Prob. 2C.4BE Ch. 2 - Prob. 2C.5AE Ch. 2 - Prob. 2C.5BE Ch. 2 - Prob. 2C.6AE Ch. 2 - Prob. 2C.6BE Ch. 2 - Prob. 2C.7AE Ch. 2 - Prob. 2C.7BE Ch. 2 - Prob. 2C.8AE Ch. 2 - Prob. 2C.8BE Ch. 2 - Prob. 2C.1P Ch. 2 - Prob. 2C.2P Ch. 2 - Prob. 2C.3P Ch. 2 - Prob. 2C.4P Ch. 2 - Prob. 2C.5P Ch. 2 - Prob. 2C.6P Ch. 2 - Prob. 2C.7P Ch. 2 - Prob. 2C.8P Ch. 2 - Prob. 2C.9P Ch. 2 - Prob. 2C.10P Ch. 2 - Prob. 2C.11P Ch. 2 - Prob. 2D.1DQ Ch. 2 - Prob. 2D.2DQ Ch. 2 - Prob. 2D.1AE Ch. 2 - Prob. 2D.1BE Ch. 2 - Prob. 2D.2AE Ch. 2 - Prob. 2D.2BE Ch. 2 - Prob. 2D.3AE Ch. 2 - Prob. 2D.3BE Ch. 2 - Prob. 2D.4AE Ch. 2 - Prob. 2D.4BE Ch. 2 - Prob. 2D.5AE Ch. 2 - Prob. 2D.5BE Ch. 2 - Prob. 2D.1P Ch. 2 - Prob. 2D.2P Ch. 2 - Prob. 2D.3P Ch. 2 - Prob. 2D.4P Ch. 2 - Prob. 2D.5P Ch. 2 - Prob. 2D.6P Ch. 2 - Prob. 2D.7P Ch. 2 - Prob. 2D.8P Ch. 2 - Prob. 2D.9P Ch. 2 - Prob. 2E.1DQ Ch. 2 - Prob. 2E.2DQ Ch. 2 - Prob. 2E.1AE Ch. 2 - Prob. 2E.1BE Ch. 2 - Prob. 2E.2AE Ch. 2 - Prob. 2E.2BE Ch. 2 - Prob. 2E.3AE Ch. 2 - Prob. 2E.3BE Ch. 2 - Prob. 2E.4AE Ch. 2 - Prob. 2E.4BE Ch. 2 - Prob. 2E.5AE Ch. 2 - Prob. 2E.5BE Ch. 2 - Prob. 2E.1P Ch. 2 - Prob. 2E.2P Ch. 2 - Prob. 2.1IA Ch. 2 - Prob. 2.3IA Ch. 2 - Prob. 2.4IA Ch. 2 - Prob. 2.5IA Ch. 2 - Prob. 2.6IA Ch. 2 - Prob. 2.7IA

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