Engineering Economy (16th Edition) - Standalone book
Engineering Economy (16th Edition) - Standalone book
16th Edition
ISBN: 9780133439274
Author: William G. Sullivan, Elin M. Wicks, C. Patrick Koelling
Publisher: PEARSON
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Chapter 2, Problem 26P
To determine

The total cost of operating the ship and cost of perishable cargo.

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A large company in the communication and publishing industry has quantified the relationship between the price of one of its products and the demand for this product as Price=160−0.02×Demand for an annual printing of this particular product. The fixed costs per year​ (i.e., per ​printing)=​$47,000 and the variable cost per unit=​$40. What is the maximum profit that can be​ achieved? What is the unit price at this point of optimal​ demand? Demand is not expected to be more than 4,000 units per year. The maximum profit that can be achieved is ​$? ​(Round to the nearest​ dollar.) The unit price at the point of optimal demand is ​$? per unit. ​
A company produces and sells a consumer product and is able to control the demand by varying the selling price. The approximate relationship between price and demand is 2700 5000 p = 38 + (for D>1) D² The company is seeking to maximize its profit. The fixed cost is $1,000 and the variable cost is $ 40 per unit. What is the number of units and total amount that should be produced and sold each month to maximize profit?
It is known that a certain company sells each kg of the product it manufactures at $80, it is also known that the total manufacturing cost "CT" is given by the function CT=(1/1000)x2 +100 , where "x" are the kg of product produced. a) How many units of "x" must the company sell to break even? Value = 100 points.b) How many units of "x" is the optimal quantity that should be sold to optimize the producer's profit? Value = 100 points.c) How many monetary units does that optimal profit for producers amount to? (remember, you will have to prove it mathematically either by the method of the first or by the method of the second derivative). Value = 100 points.
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