PRINT COMPANION ENGINEER THERMO
9th Edition
ISBN: 9781119778011
Author: MORAN
Publisher: WILEY
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Question
thumb_up100%
Chapter 2, Problem 2.38P
i.
To determine
Calculate the rate of conduction.
ii.
To determine
Calculate the rate of convection.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
A 3,500-seat auditorium is to be air-conditioned using window
units
10 kW nominal value. Assume that a person at rest will
dissipate heat at a rate of approximately 360 kJ/h.
There are 200 lamps in the auditorium, each rated at 250 W.
The rate of heat transfer to the
auditorium through the walls and windows is estimated to be
equal to 150,000 kJ/h. If the auditorium air goes
to maintain at a constant temperature of 200°C, determine the
number of air conditioning units of
required window. Answer: 45 units.
In an experiment to measure the specific heat of material, a student
first measured the masses of the following samples as given in
Table 1.
Table 1: Measurement of Mass
Physical quantity
measured in (g)
Value
Mass of Styrofoam
2.4
cup
Mass of Styrofoam
62
cup + water
Mass of
Brass sample
15.3
Mass of Copper
sample
62.5
and then recorded the temperatures of the above two samples, in
Table 2.
Table 2: Measured values of Temperatures
Hot termperature ("C )
Sample
Equilibrium cold temperature ( C)
temperature ("C)
Brass
99.8
26.5
24.5
Сopper
99.8
32
26
Answer the following questions using the data given in Table 1 and
Table 2.
(Please enter the answers with two digits after decimal)
(a) Calculation of specific heat capacity of Brass:
Calculated
Quantities
Mass of the
water (in
Values
grams)
Change in
temperature
lof the hot
object (
ATobieca)
°C)
Change in
temperature
of water
(ATwaer)
(°C)
Calculated
specific
heat of the
object
in (cal/g'C)
(b) Calculation of the specific heat capacity…
The molar heat capacities of substances varies with temperature. The general function for determining the molar heat capacity is given below;
Cp m = (a + bT + cT 2 )R .
In case of a gas where a = 3.245, b = 7.108 x10^ -4 K ^-1 , and c = -4.06 x10 ^-8 K^ -2 for temperatures in the range of 800 Kelvins to 1,500 Kelvins. What is the change in the enthalpy (in KiloJoules per Kelvin per mole) for two moles of this gas at 1,500 kelvins?
NOTE: Express answer in THREE SIGNIFICANT FIGURES.
Chapter 2 Solutions
PRINT COMPANION ENGINEER THERMO
Ch. 2 - Prob. 2.1ECh. 2 - Prob. 2.2ECh. 2 - Prob. 2.3ECh. 2 - Prob. 2.4ECh. 2 - Prob. 2.5ECh. 2 - Prob. 2.6ECh. 2 - Prob. 2.7ECh. 2 - Prob. 2.8ECh. 2 - Prob. 2.9ECh. 2 - Prob. 2.10E
Ch. 2 - Prob. 2.11ECh. 2 - Prob. 2.12ECh. 2 - Prob. 2.13ECh. 2 - Prob. 2.14ECh. 2 - Prob. 2.15ECh. 2 - Prob. 2.16ECh. 2 - Prob. 2.17ECh. 2 - Prob. 2.1CUCh. 2 - Prob. 2.2CUCh. 2 - Prob. 2.3CUCh. 2 - Prob. 2.4CUCh. 2 - Prob. 2.5CUCh. 2 - Prob. 2.6CUCh. 2 - Prob. 2.7CUCh. 2 - Prob. 2.8CUCh. 2 - Prob. 2.9CUCh. 2 - Prob. 2.10CUCh. 2 - Prob. 2.11CUCh. 2 - Prob. 2.12CUCh. 2 - Prob. 2.13CUCh. 2 - Prob. 2.14CUCh. 2 - Prob. 2.15CUCh. 2 - Prob. 2.16CUCh. 2 - Prob. 2.17CUCh. 2 - Prob. 2.18CUCh. 2 - Prob. 2.19CUCh. 2 - Prob. 2.20CUCh. 2 - Prob. 2.21CUCh. 2 - Prob. 2.22CUCh. 2 - Prob. 2.23CUCh. 2 - Prob. 2.24CUCh. 2 - Prob. 2.25CUCh. 2 - Prob. 2.26CUCh. 2 - Prob. 2.27CUCh. 2 - Prob. 2.28CUCh. 2 - Prob. 2.29CUCh. 2 - Prob. 2.30CUCh. 2 - Prob. 2.31CUCh. 2 - Prob. 2.32CUCh. 2 - Prob. 2.33CUCh. 2 - Prob. 2.34CUCh. 2 - Prob. 2.35CUCh. 2 - Prob. 2.36CUCh. 2 - Prob. 2.37CUCh. 2 - Prob. 2.38CUCh. 2 - Prob. 2.39CUCh. 2 - Prob. 2.40CUCh. 2 - Prob. 2.41CUCh. 2 - Prob. 2.42CUCh. 2 - Prob. 2.43CUCh. 2 - Prob. 2.44CUCh. 2 - Prob. 2.45CUCh. 2 - Prob. 2.46CUCh. 2 - Prob. 2.47CUCh. 2 - Prob. 2.48CUCh. 2 - Prob. 2.49CUCh. 2 - Prob. 2.50CUCh. 2 - Prob. 2.51CUCh. 2 - Prob. 2.52CUCh. 2 - Prob. 2.53CUCh. 2 - Prob. 2.54CUCh. 2 - Prob. 2.1PCh. 2 - Prob. 2.2PCh. 2 - Prob. 2.3PCh. 2 - Prob. 2.4PCh. 2 - Prob. 2.5PCh. 2 - Prob. 2.6PCh. 2 - Prob. 2.7PCh. 2 - Prob. 2.8PCh. 2 - Prob. 2.9PCh. 2 - Prob. 2.10PCh. 2 - Prob. 2.11PCh. 2 - Prob. 2.12PCh. 2 - Prob. 2.13PCh. 2 - Prob. 2.14PCh. 2 - Prob. 2.15PCh. 2 - Prob. 2.16PCh. 2 - Prob. 2.17PCh. 2 - Prob. 2.18PCh. 2 - Prob. 2.19PCh. 2 - Prob. 2.20PCh. 2 - Prob. 2.21PCh. 2 - Prob. 2.22PCh. 2 - Prob. 2.23PCh. 2 - Prob. 2.24PCh. 2 - Prob. 2.25PCh. 2 - Prob. 2.26PCh. 2 - Prob. 2.27PCh. 2 - Prob. 2.28PCh. 2 - Prob. 2.29PCh. 2 - Prob. 2.30PCh. 2 - Prob. 2.31PCh. 2 - Prob. 2.32PCh. 2 - Prob. 2.33PCh. 2 - Prob. 2.34PCh. 2 - Prob. 2.35PCh. 2 - Prob. 2.36PCh. 2 - Prob. 2.37PCh. 2 - Prob. 2.38PCh. 2 - Prob. 2.39PCh. 2 - Prob. 2.40PCh. 2 - Prob. 2.41PCh. 2 - Prob. 2.42PCh. 2 - Prob. 2.43PCh. 2 - Prob. 2.44PCh. 2 - Prob. 2.45PCh. 2 - Prob. 2.46PCh. 2 - Prob. 2.47PCh. 2 - Prob. 2.48PCh. 2 - Prob. 2.49PCh. 2 - Prob. 2.50PCh. 2 - Prob. 2.51PCh. 2 - Prob. 2.52PCh. 2 - Prob. 2.53PCh. 2 - Prob. 2.54PCh. 2 - Prob. 2.55PCh. 2 - Prob. 2.56PCh. 2 - Prob. 2.57PCh. 2 - Prob. 2.58PCh. 2 - Prob. 2.59PCh. 2 - Prob. 2.60PCh. 2 - Prob. 2.62PCh. 2 - Prob. 2.63PCh. 2 - Prob. 2.64PCh. 2 - Prob. 2.65PCh. 2 - Prob. 2.66PCh. 2 - Prob. 2.67PCh. 2 - Prob. 2.68PCh. 2 - Prob. 2.69PCh. 2 - Prob. 2.70PCh. 2 - Prob. 2.71P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- A food product with 85% moisture content is being frozen. Estimate the specific heat of the product at -10°C when 80% of the water is in a frozen state. The specific heat of dry product solid is 2 kJ/(kg °C). Assume specific heat of water at -10°C is similar to specific heat of water at 0°C. And the heat of the types of ice follow the function of Cp ice = 0.0062 Tfrozen + 2.0649. Cp frozen product = ... kJ/kg °C.arrow_forwardA food product containing 80% moisture content is being frozen. Estimate the specific heat of the product at -6 ° C when 82% of the water is frozen. The specific heat of the dry product is 2.5 kJ / (kg ° C). it is assumed that the specific heat of water at -10 ° C is the same as the specific heat of water at 0 ° C, and the specific heat of ice follows the function Cp es = 0.0062 Tbeku + 2.0649. Cp frozen products = AnswerkJ / kg ° C.arrow_forwardA food product containing 85% moisture content is being frozen. Estimate the specific heat of the product at -4 ° C when 62% of the water is frozen. The specific heat of the dry product is 2.5 kJ / (kg ° C). it is assumed that the specific heat of water at -10 ° C is the same as the specific heat of water at 0 ° C, and the specific heat of ice follows the function Cp es = 0.0062 Tfrozen + 2.0649. Cp of frozen product = kJ / kg ° C.arrow_forward
- A food product containing 75% moisture content is being frozen. Estimate the specific heat of the product at -10 ° C when 85% of the water is frozen. The specific heat of the dry product is 2 kJ / (kg ° C). It is assumed that the specific heat of water at -10 ° C is the same as the specific heat of water at 0 ° C, and that the specific heat of ice follows the function Cp ice = 0.0062 T frozen + 2.0649. Cp frozen product = AnswerkJ / kg ° C.arrow_forwardA food product containing 85% moisture content is being frozen. Estimate the specific heat of the product at -10 ° C when 80% of the water is frozen. The specific heat of the dry product is 2 kJ / (kg ° C). It is assumed that the specific heat of water at -10 ° C is the same as the specific heat of water at 0 ° C, and that the specific heat of ice follows the function Cp es = 0.0062 Tbeku + 2.0649. Cp frozen product = Answerarrow_forwardA food product containing 80% moisture content is being frozen. Estimate the specific heat of the product at -6 ° C when 80% of the water is frozen. The specific heat of the dry product is 2 kJ / (kg ° C). It is assumed that the specific heat of water at -10 ° C is the same as the specific heat of water at 0 ° C, and that the specific heat of ice follows the function Cp es = 0.0062 Tbeku + 2.0649. Cp frozen product = Answer kJ / kg ° C.arrow_forward
- A food product containing 75% moisture content is being frozen. Estimate the specific heat of the product at -10 ° C when 85% of the water is frozen. The specific heat of the dry product is 2 kJ / (kg ° C). it is assumed that the specific heat of water at -10 ° C is the same as the specific heat of water at 0 ° C, and the specific heat of ice follows the function Cp es = 0.0062 Tbeku + 2.0649. Cp of frozen product = .... kJ / kg ° Carrow_forwardA food product containing 80% moisture content is being frozen. Estimate the specific heat of the product at -6 ° C when 80% of the water is frozen. The specific heat of the dry product is 2 kJ / (kg ° C). it is assumed that the specific heat of water at -10 ° C is the same as the specific heat of water at 0 ° C, and the specific heat of ice follows the function Cp ice = 0.0062 T frozen + 2.0649. Cp frozen products = Answer kJ / kg ° C.arrow_forward2) For a wall that has a thermal conductivity of 4.80 BTU/ft. hr. F°, the surface area is equal to 3 m^2. The temperature difference is equal to 26F°.The thickness of the wall is 400 mm. Determine the following: a. The total heat loss in 7 hours in BTU b. Assume that all the conditions were retained except that the area was reduced to 2 m^2, what is the percentage reduction in the rate of heat transfer through the wall. c. Explain the concepts/principles that were considered and the factors that affected the condition of the above mentioned items (a & b).arrow_forward
- A firearm can be modeled as a kind of heat engine, where the projectile acts as a piston that separates from the rest of the system during expansion. Consider a rifle with a 1.70 kg barrel made of iron [specific heat = 448 J/(kg °C)]. The rifle fires a 4.00 g bullet that exits the barrel with a speed of 350 m/s. When the propellant is ignited, 1.10% of the energy released goes into propelling the bullet (this is the thermal efficiency of the "engine"). The other 98.9% can be approximated as being entirely absorbed by the barrel, which increases in temperature uniformly for a short time before this energy is dissipated into the surroundings. What is this temperature increase (in °C)? (Round your answer to at least one decimal place.) °℃arrow_forwardHeat transfer principles of convectionarrow_forwardQ A horizontal piston-cylinder assembly contains 2.00 kg of a fluid. The assembly is fitted with both a heater and a paddle wheel. It is found that the fluid undergoes an expansion from state 1 to state 2. During the process, the paddle wheel transmits 16.4 kJ of mechanical energy (Wp.w.) to the fluid via mixing, and the heater supplies 83 kJ of thermal energy (Q) to the fluid. The specific internal energy changes from U1 = 2386.6 kJ/kg to U2 = 2409.1 kJ/kg during the process. Determine the work done by the steam on the piston during the process (Wpiston) (kJ). Your Answer: 45°F hp Insert * 24 % 8. 4 R H J K D F CV B N Marrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Principles of Heat Transfer (Activate Learning wi...Mechanical EngineeringISBN:9781305387102Author:Kreith, Frank; Manglik, Raj M.Publisher:Cengage Learning
Principles of Heat Transfer (Activate Learning wi...
Mechanical Engineering
ISBN:9781305387102
Author:Kreith, Frank; Manglik, Raj M.
Publisher:Cengage Learning
The Laws of Thermodynamics, Entropy, and Gibbs Free Energy; Author: Professor Dave Explains;https://www.youtube.com/watch?v=8N1BxHgsoOw;License: Standard YouTube License, CC-BY