Materials for Civil and Construction Engineers (4th Edition)
4th Edition
ISBN: 9780134320533
Author: Michael S. Mamlouk, John P. Zaniewski
Publisher: PEARSON
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Chapter 2, Problem 2.18QP
Determine the density of a hypothetical BCC metal with an atomic mass of 63.5 g/mole and atomic radius of 0.128 nm.
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Two hypothetical metals are created with different elements that have the same atomic mass (g/mole) and the same atomic radius. Metal A has a density of 9.50 g/cm3 and metal B has a density of 8.73 g/cm3. If one of these metals has a BCC lattice structure and the other has an FCC lattice structure, identify the structure that corresponds to each of one of them. Justify your answer.
Two hypothetical metals are created with different elements that have thesame atomic mass (g/mole) and the same atomic radius. Metal A has a density of 9.50 g/cm3 and metal B has a density of 8.73 g/cm3 . If one of these metals has a BCC lattice structure and the other has an FCC lattice structure, identify the structure that corresponds to each of one of them. Justify your answer.
Chapter 2 Solutions
Materials for Civil and Construction Engineers (4th Edition)
Ch. 2 - Define elastic and plastic behaviors at the micro...Ch. 2 - Prob. 2.2QPCh. 2 - Prob. 2.3QPCh. 2 - Describe the order in which electrons fill the...Ch. 2 - Prob. 2.5QPCh. 2 - Why do atoms maintain specific separations?Ch. 2 - Prob. 2.7QPCh. 2 - Prob. 2.8QPCh. 2 - Prob. 2.9QPCh. 2 - Two hypothetical metals are created with different...
Ch. 2 - Prob. 2.11QPCh. 2 - Prob. 2.12QPCh. 2 - Prob. 2.13QPCh. 2 - Prob. 2.14QPCh. 2 - Prob. 2.15QPCh. 2 - Prob. 2.16QPCh. 2 - Prob. 2.17QPCh. 2 - Determine the density of a hypothetical BCC metal...Ch. 2 - Determine the density of a hypothetical FCC metal...Ch. 2 - Prob. 2.20QPCh. 2 - Prob. 2.21QPCh. 2 - Prob. 2.22QPCh. 2 - Prob. 2.23QPCh. 2 - Prob. 2.24QPCh. 2 - Prob. 2.25QPCh. 2 - Prob. 2.26QPCh. 2 - Prob. 2.27QPCh. 2 - Prob. 2.28QPCh. 2 - Prob. 2.29QPCh. 2 - Prob. 2.30QPCh. 2 - Prob. 2.31QPCh. 2 - Prob. 2.32QPCh. 2 - Prob. 2.33QPCh. 2 - Prob. 2.34QPCh. 2 - Prob. 2.35QPCh. 2 - Prob. 2.36QP
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- Two hypothetical metals are created with different elements that have the same atomic mass (g/mole) and the same atomic radius. Metal A has a densityof 9.50 g/cm3 and metal B has a density of 8.73 g/cm3. If one of these metals has a BCC lattice structure and the other has an FCC lattice structure, identify the structure that corresponds to each of one of them. Justify your answer.arrow_forwardA pure titanium cube has an edge length of 2.74 inin . How many titanium atoms does it contain? Titanium has a density of 4.50g/cm34.50g/cm3. Express your answer in atoms to three significant figures.arrow_forwardUsing the information available in Table 2.3, calculate the density of molyb-denum given that it has an atomic mass of 95.94 g/mole.arrow_forward
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- Calcium forms a face centered cubic cell with a density of 1.54 g/ml, what would its radius be?arrow_forwardDraw a bar diagram on your sketch paper based on the table below and determine the non-carbon hardness (permanent hardness) in mg/L of CaCO3. Atomic weight Equivalent weight or molecular Concentration (mg/L) meq/L concentration (mg/meq) weight (g/mol) 100 Ca2+ 40 150 mg/L as CaCO3 150/50=3 (g/mol)/2(eq/mol)=50 Mg2+ 24 100 mg/L as CACO3 100/50=2 Na+ 23 46 mg/L K+ 39 39 mg/L HCO3 61 225 mg/L as CaCO3 225/50=4.5 SO42- 96 72 mg/L CI 35.5 71 mg/L O 25 mg/L of CaCO3 O 50 mg/L of CaCO3 O 100 mg/L of CaCO3 O 150 mg/L of CaCO3arrow_forwardThe reciprocal of density isarrow_forward
- Copper has an atomic radius of 0.128 nm (1.28A°), an FCC crystal structure, and an atomic weight of 63.5 g/mol. Compute its theoretical density?arrow_forwardReferring to the BCC lattice structure shown in Figure P2.12 a. Determine the number of equivalent whole atoms in the unit cell. b. Calculate the relation between a and r. c. Calculate the atomic packing factor of the BCC lattice structure.arrow_forwardCalculate the radius of a palladium atom in nm, given that Pd has a FCC crystal structure, a density of 12.0 g/cm^3 and an atomic weight of 106.4 g/mol. a) 1.38X10^-8b) 0.138c) 138d) 1.38arrow_forward
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