Chapter 2, Problem 102P

2-66. Determine the magnitude and coordinate direction angles of the resultant force, and sketch this vector on the coordinate system. ス F, = 125 N 5. 3. 4 -y 20 60° 45° 60° F = 400 N %3D Prob. 2-66

Express the force in Cartesian vector form. F = 1500 lb 17 t 12 ft

Since F1 = 200 N Theta = 15 °, determine the magnitude of the resultant force acting on the bracket and its direction measured counterclockwise from the positive x 'axis.

Determine the magnitude of the resultant force and its direction, measured counterclockwise from the positive x axis. F3 = 750 N 45° 30° F; = 850 N F2 = 625 N

Determine the magnitude of the resultant force FR = F₁ + F₂ and its direction, measured counterclockwise from the positive x axis. 2-6. Determine the magnitude of the resultant force FR = F₁+F₂ and its direction, measured clockwise from the positive u axis. 75° -30° 30° F₁ = 250 lb F₂=375 lb 30° F₂ = 6 kN F₁ = 4 kN

Find the magnitude and direction of the resultant force if F1 = 60 N at 45 deg N of W and F2 = 50 N at 60 deg S of E.

Determine the x- and y-coordinates of a point through which the resultant of the parallel forces passes. y 20 lb 90 lb 85 lb 30 Ib 16" 7" 13" 13" 25 lb v Part 1 The problem asks us to replace these five forces with a single equivalent force. The new system is shown below. y Find the force R. Answer: R = Ib

Q6- The force F acts on radius bone. If the magnitude of the x and z components of F are F=150 and F=400, and B=130°, determine the magnitude of F and its y component. Also, find the coordinate direction angles a and y. y

Three forces act at the same point as shown. Determine the magnitude (N) of the resultant. Consider the following: F1 = 192 N F2 = 62 N F3 = 53 N θ1 = 14°  θ2 = 37° x = 2 y = 7