The equilibrium constants for the following reactions at 298 K have to be determined and also determine the equilibrium is a reactant or product favoured at equilibrium. (a) 2Cl - (aq) + Br 2 (l) → Cl 2 (g) + 2Br - (aq) Concept introduction: According to the first law of thermodynamics , the change in internal energy of a system is equal ti the heat added to the sysytem minus the work done by the system. The equation is as follows. ΔU = Q - W ΔU = Change in internal energy Q = Heat added to the system W=Work done by the system In voltaic cell, the maximum cell potential is directly related to the free energy difference between the reactants and products in the cell. ΔG 0 = -nFE 0 n = Number of moles transferred per mole of reactant and products F = Faradayconstant=96485C/mol E 0 = Volts = Work(J)/Charge(C) The relation between standard cell potential and equilibrium constant is as follows. lnK = nE 0 0 .0257 at 298K
The equilibrium constants for the following reactions at 298 K have to be determined and also determine the equilibrium is a reactant or product favoured at equilibrium. (a) 2Cl - (aq) + Br 2 (l) → Cl 2 (g) + 2Br - (aq) Concept introduction: According to the first law of thermodynamics , the change in internal energy of a system is equal ti the heat added to the sysytem minus the work done by the system. The equation is as follows. ΔU = Q - W ΔU = Change in internal energy Q = Heat added to the system W=Work done by the system In voltaic cell, the maximum cell potential is directly related to the free energy difference between the reactants and products in the cell. ΔG 0 = -nFE 0 n = Number of moles transferred per mole of reactant and products F = Faradayconstant=96485C/mol E 0 = Volts = Work(J)/Charge(C) The relation between standard cell potential and equilibrium constant is as follows. lnK = nE 0 0 .0257 at 298K
Solution Summary: The author explains that the equilibrium is a reactant or product favoured at equilibrium, according to the first law of thermodynamics.
Definition Definition Transformation of a chemical species into another chemical species. A chemical reaction consists of breaking existing bonds and forming new ones by changing the position of electrons. These reactions are best explained using a chemical equation.
Chapter 19, Problem 89GQ
(a)
Interpretation Introduction
Interpretation:
The equilibrium constants for the following reactions at 298 K have to be determined and also determine the equilibrium is a reactant or product favoured at equilibrium.
(a) 2Cl-(aq) + Br2(l) →Cl2(g) + 2Br-(aq)
Concept introduction:
According to the first law of thermodynamics, the change in internal energy of a system is equal ti the heat added to the sysytem minus the work done by the system.
The equation is as follows.
ΔU = Q - WΔU = Change in internal energyQ = Heat added to the systemW=Work done by the system
In voltaic cell, the maximum cell potential is directly related to the free energy difference between the reactants and products in the cell.
ΔG0= -nFE0n = Number of moles transferred per mole of reactant and productsF = Faradayconstant=96485C/mol E0= Volts = Work(J)/Charge(C)
The relation between standard cell potential and equilibrium constant is as follows.
lnK = nE00.0257 at 298K
(b)
Interpretation Introduction
Interpretation:
The equilibrium constants for the following reactions at 298 K have to be determined and also determine the equilibrium is a reactant or product favoured at equilibrium.
(b) Fe2+(aq) + Ag+(aq) →Fe3+(aq) + Ag(s)
Concept introduction:
According to the first law of thermodynamics, the change in internal energy of a system is equal ti the heat added to the sysytem minus the work done by the system.
The equation is as follows.
ΔU = Q - WΔU = Change in internal energyQ = Heat added to the systemW=Work done by the system
In voltaic cell, the maximum cell potential is directly related to the free energy difference between the reactants and products in the cell.
ΔG0= -nFE0n = Number of moles transferred per mole of reactant and productsF = Faradayconstant=96485C/mol E0= Volts = Work(J)/Charge(C)
The relation between standard cell potential and equilibrium constant is as follows.
What is the equilibrium constant expression for the following reaction?0, (aq) + Fe2+(aq) + 8H*(aq) -Mn?+(aq) + Fe3+(aq) + 4H20(l)
What is the equilibrium expression for the reaction: CuO (s) + 5 HCl(aq) ⇌ CuCl2(aq) + H2O(l)?
Use the hard/soft acid/base concept to predict whether the fol-
lowing reactions will occur.
(a) CaF(s) + CdIz (s) –→ Cal2(s) + CdF2 (s)
(b) Cr(CN)2 (s) + Cd(OH)2 (s) → Cd(CN)2 (s) + Cr(OH)2 (s)
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.