Physics of Everyday Phenomena
Physics of Everyday Phenomena
9th Edition
ISBN: 9781259894008
Author: W. Thomas Griffith, Juliet Brosing Professor
Publisher: McGraw-Hill Education
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Chapter 19, Problem 3SP

(a)

To determine

The mass difference Δm between the reactants and the products for the reaction 1H2+1H22He3+0n1.

(a)

Expert Solution
Check Mark

Answer to Problem 3SP

The mass difference Δm between the reactants and the products for the reaction 1H2+1H22He3+0n1 for the reaction is 3.51×103u

Explanation of Solution

Given info: The mass of 1H2 is 2.014102u , the mass of He3 is 3.016029u and the mass of neutron is 1.008665.

Write the expression for the mass difference for the reaction.

Δm=2(mH)(mHe+mn)

Here,

Δm is the mass difference

mHe is the mass of the 2He3

mH is the mass of the 1H2

mn is the mass of the neutron

Substitute 3.016029u for mHe,2.014102u for mH and 1.008665 for mn in the above equation to get Δm.

Δm=2(2.014102u)(3.016029u+1.008665)=3.51×103u

Therefore, the mass difference between the reactants and products for the reaction is 3.51×103u

Conclusion:

Thus, the mass difference Δm between the reactants and the products for the reaction 1H2+1H22He3+0n1 for the reaction is 3.51×103u

(b)

To determine

Energy unit corresponds to the mass difference.

(b)

Expert Solution
Check Mark

Answer to Problem 3SP

The mass difference is equal to 5.25×1013J.

Explanation of Solution

Given info: The unified mass is equal to 1.661×1027kg and velocity of light is light is equal to 3×108m/s.

Write the mass-equivalence relation for the mass Δm.

E=Δmc2

Here,

E is the energy equivalent to the mass difference between the reactants and products

Δm is the mass difference

c is the velocity of light in vacuum

Convert 3.51×103u into kilogram.

3.51×103u=3.51×103u×1.661×1027kg1u=5.83×1030kg

Substitute 5.83×1030kg for Δm , 3×108m/s for c in the above equation to get E.

E=(5.83×1030kg)(3×108m/s)2=5.25×1013J

Conclusion:

Thus, the energy equivalent to that of mass difference between the reactants and products in the reaction 1H2+1H22He3+0n1 is 5.25×1013J.

(c)

To determine

Whether energy calculated is released. Determine where it goes.

(c)

Expert Solution
Check Mark

Answer to Problem 3SP

The energy is released in the reaction and the released energy transformed in the form of kinetic energy of the products.

Explanation of Solution

Fusion reaction is the reaction in which two hydrogen atoms combined together to form heavier nucleus.

Write the fusion reaction mentioned in the text book.

1H2+1H22He3+0n1

Here, the total mass of the reactants is less than the total mass of the products. This difference in the mass converts as energy and transform in the form of kinetic energy of the Helium and neutron.

Therefore according conservation of energy, total energy should be a constant and one form of energy can be converted into any other form of energy. In order to conserve the energy the neutron particle moves with more kinetic energy.

Conclusion:

Thus, energy is released in the reaction and it is in the form of kinetic energy of the products.

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