Physics of Everyday Phenomena
9th Edition
ISBN: 9781259894008
Author: W. Thomas Griffith, Juliet Brosing Professor
Publisher: McGraw-Hill Education
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Chapter 19, Problem 14CQ
To determine
Whether the battery in a smoke alarm creates the charge on the plates or charge on the ions.
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What electrostatic force acts between two protons in a nucleus if they are 4×10-15 m apart?
Select one:
O a. 8.8x109 (attractive)
O b. 8.8×10 (repulsive)
O c. 14N (repulsive)
O d. 14N (attractive)
What is the total charge of all protons in 7 gram of water (H2O)?
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1. Compare the electrostatic force between an electron and proton separated
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Chapter 19 Solutions
Physics of Everyday Phenomena
Ch. 19 - Prob. 1CQCh. 19 - Prob. 2CQCh. 19 - Prob. 3CQCh. 19 - Prob. 4CQCh. 19 - Prob. 5CQCh. 19 - Prob. 6CQCh. 19 - Prob. 7CQCh. 19 - Prob. 8CQCh. 19 - Prob. 9CQCh. 19 - Prob. 10CQ
Ch. 19 - Prob. 11CQCh. 19 - Prob. 12CQCh. 19 - Prob. 13CQCh. 19 - Prob. 14CQCh. 19 - Prob. 15CQCh. 19 - Prob. 16CQCh. 19 - Prob. 17CQCh. 19 - Prob. 18CQCh. 19 - Prob. 19CQCh. 19 - Prob. 20CQCh. 19 - Prob. 21CQCh. 19 - Prob. 22CQCh. 19 - Prob. 23CQCh. 19 - Prob. 24CQCh. 19 - Prob. 25CQCh. 19 - Prob. 26CQCh. 19 - Prob. 27CQCh. 19 - Prob. 28CQCh. 19 - Prob. 29CQCh. 19 - Prob. 30CQCh. 19 - Prob. 31CQCh. 19 - Prob. 32CQCh. 19 - Prob. 33CQCh. 19 - Prob. 34CQCh. 19 - Prob. 35CQCh. 19 - Prob. 36CQCh. 19 - Prob. 37CQCh. 19 - Prob. 1ECh. 19 - Prob. 2ECh. 19 - Prob. 3ECh. 19 - Prob. 4ECh. 19 - Prob. 5ECh. 19 - Prob. 6ECh. 19 - Prob. 7ECh. 19 - Prob. 8ECh. 19 - Prob. 9ECh. 19 - How many half-lives must go by tor the...Ch. 19 - Prob. 11ECh. 19 - Prob. 12ECh. 19 - Prob. 1SPCh. 19 - Prob. 2SPCh. 19 - Prob. 3SPCh. 19 - Prob. 4SP
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- 1. What is the magnitude of the repulsive electrostatic force between two protons in a nucleus? Consider the distance between the centers of the protons to be 3.5 x 10^-13 m. If these protons were released from rest, Calculate the magnitude of their initial acceleration?arrow_forward10) Now you have a nucleus with 13 protons at x = 6.2 Angstroms on the x-axis. How much work would it take to bring in ANOTHER nucleus with 7 protons from 1 m away and place it at y = 8.0 Angstroms on the y-axis? 70.0 eV 116.7 eV -12.6 eV 129.3 eVarrow_forwardTwo protons in the nucleus of a 238U atom are 6.0 fm (6.0x10-15m) apart. What is the potential energy (in joules) associated with the electric force that acts between these two particles? A.2.8x10-14 B. 3.8x1014 C. 5.0x10-9 D. 5.0x10-8arrow_forward
- Your body contains roughly 10^28 electrons. However, your body can be considered electrically neutral. Explain whyarrow_forwardThe bulk in laboratory plasmas are called quasineutral because in the lab setting they tend to have a positive charge. Why does this happen? fast electrons escape the plasma bulk and get sinked into the vacuum chamber walls there are more electrons than ions in the plasma bulk plasma is inherently postive the vacuum system takes out some electrons and leaves the plasma with a positive chargearrow_forward10. An electron has been placed at the origin. The grid spacing is 1 Angstrom per small square this time. Now you have a nucleus with 18 protons at x = 2.1 Angstroms on the x-axis. How much work would it take to bring in ANOTHER nucleus with 14 protons from 1 m away and place it at y = 8.0 Angstroms on the y-axis? 165.2 eV 413.1 eV -25.2 eV 438.2 eVarrow_forward
- A charged object has 82 protons, 82 neutrons, and 109 electrons on it. a) What is the element? b) What is its overall charge in C (be sure to include the sign!).arrow_forwardPart 1 Find the speed an alpha particle requires to come within 4 x 10-14 m of a gold nucleus. Coulomb's constant is 8.99 x 109 Nm2/C2, the charge on an electron is 1.6 × 10-19 C, and the mass of the alpha particle is 6.64 x 10-27 kg. Answer in units of m/s. Part 2 Find the energy of the alpha particle. Answer in units of MeV.arrow_forwardCoulomb's Law yields an expression for the energy of interaction for a pair of point charges. V = 2.31x10^-19 Q1Q2 r V is the energy (in J) required to bring the two charges from infinite distance separation to distance r (in nm).Q1 and Q2 are the charges in terms of electrons.(i.e. the constant in the above expression is 2.31×10-19 J nm electrons-2) For a group of "point" charges (e.g. ions) the total energy of interaction is the sum of the interaction energies for the individual pairs.Calculate the energy of interaction for the square arrangement of ions shown in the diagram below. d = 0.545 nmarrow_forward
- Now you have a nucleus with 20 protons at x = 7.9 Angstroms on the x-axis. How much work would it take to bring in ANOTHER nucleus with 4 protons from 1 m away and place it at y = 7.0 Angstroms on the y-axis? Question 10 options: A 50.4 eV B 100.8 eV C -8.2 eV D 109.0 eVarrow_forwardIf the nucleus is a few fm in diameter, the distance between the centers of two protons must be ≈2 fm.a. Calculate the repulsive electric force between two protons that are 2.0 fm apart.b. Calculate the attractive gravitational force between two protons that are 2.0 fm apart. Could gravity be the force that holds the nucleus together?arrow_forwardThe grid spacing is 1 Angstrom per small square. Now place an atomic nucleus with 4 protons on positive x-axis, at x = 5.2 Angstroms. How much work did it take you to bring this nucleus in from 1 m away? 7.8 eV 15.5 eV 9.5 eV 11.1 eVarrow_forward
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