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Concept explainers
(a)
Interpretation:
An aqueous NaOH is added to mixed solution of 0.50 M Fe(NO3)2 and 0.25 M Cd(NO3)2 which ion is a precipitate first, the reason has to be explained.
Concept Introduction:
- Molar solubility is defined as amount of solute that can be dissolved in one litre of solution before it attains saturation.
- Solubility of a compound is expressed as concentration of its ions in saturated solution.
- The solubility product constant (Ksp) is defined as the equilibrium between compound and its ions in an aqueous solution.
- Solubility product is the multiplication of concentration of dissolved ion, raised to the power of coefficients.
- Ionic compound A3B Ksp = [A]3[B].
Solubility product constant:
The equilibrium constant of a more soluble ionic compound in water at the higher solubility is known as solubility product constant.
The equilibrium constant of more soluble ionic compound is given by KSP and it is expressed by product of each ion present in the compounds which are raised to the power of number respective ion present in the compound to give a maximum solubility of the compound.
MmXx(s)⇌ mMn+(aq) + xXy-(aq)Ksp = [Mn+]m[Xy-]x
(b)
Interpretation:
Metal ions can be separated using NaOH solution the separation method has to be explained.
Concept Introduction:
Solubility product constant: The equilibrium constant of a more soluble ionic compound in water at the higher solubility is known as solubility product constant.
The equilibrium constant of more soluble ionic compound is given by KSP and it is expressed by product of each ion present in the compounds which are raised to the power of number respective ion present in the compound to give a maximum solubility of the compound.
MmXx(s)⇌ mMn+(aq) + xXy-(aq)Ksp = [Mn+]m[Xy-]x
(c)
Interpretation:
The concentrations of OH− when 50 mL of 0.50 M Fe(NO3)3 is dissolved in 125 mL of 0.25 M Cd(NO3)2 the separation has to be calculated.
Concept Introduction:
Solubility product constant: The equilibrium constant of a more soluble ionic compound in water at the higher solubility is known as solubility product constant.
The equilibrium constant of more soluble ionic compound is given by KSP and it is expressed by product of each ion present in the compounds which are raised to the power of number respective ion present in the compound to give a maximum solubility of the compound.
MmXx(s)⇌ mMn+(aq) + xXy-(aq)Ksp = [Mn+]m[Xy-]x
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Chapter 19 Solutions
Chemistry: The Molecular Nature of Matter and Change
- टे Predict the major products of this organic reaction. Be sure to use wedge and dash bonds when necessary, for example to distinguish between different major products. ☐ ☐ : ☐ + NaOH HO 2 Click and drag to start drawing a structure.arrow_forwardShown below are five NMR spectra for five different C6H10O2 compounds. For each spectrum, draw the structure of the compound, and assign the spectrum by labeling H's in your structure (or in a second drawing of the structure) with the chemical shifts of the corresponding signals (which can be estimated to nearest 0.1 ppm). IR information is also provided. As a reminder, a peak near 1700 cm-1 is consistent with the presence of a carbonyl (C=O), and a peak near 3300 cm-1 is consistent with the presence of an O–H. Extra information: For C6H10O2 , there must be either 2 double bonds, or 1 triple bond, or two rings to account for the unsaturation. There is no two rings for this problem. A strong band was observed in the IR at 1717 cm-1arrow_forwardPredict the major products of the organic reaction below. : ☐ + Х ك OH 1. NaH 2. CH₂Br Click and drag to start drawing a structure.arrow_forward
- NG NC 15Show all the steps you would use to synthesize the following products shown below using benzene and any organic reagent 4 carbons or less as your starting material in addition to any inorganic reagents that you have learned. NO 2 NC SO3H NO2 OHarrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forwardShow work...don't give Ai generated solutionarrow_forward
- 1 Please provide an efficient synthesis of the product below from the starting material. Use the starting material as the ONLY source of carbon atoms. Show the synthesis of each compound that would be used in the overall synthesis of the product. [This synthesis uses alkyne and alcohol chemistry.]arrow_forward10- 4000 20 20 30- %Reflectance 60 50- 09 60- 40- Date: Thu Feb 06 17:30:02 2025 (GMT-05:0(UnknownP Scans: 8 Resolution: 2.000 70 70 88 80 3500 3000 2500 90 100 00 Wavenumbers (cm-1) 2000 1500 2983.10 2359.13 1602.52 1584.22 1451.19 1391.87 1367.07 1314.37 1174.34 1070.13 1027.33 1714.16 1269.47 1000 1106.08 1001.14 937.02 873.60 850.20 780.22 686.91 674.38 643.09 617.98 02/06/25 16:38:20arrow_forwardd. Draw arrow-pushing mechanism for an enzymatic retro-aldol reaction of the following hexose. Use B: and/or HA as needed. OH OH سية HO OH OHarrow_forward
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