Physical Chemistry
2nd Edition
ISBN: 9781133958437
Author: Ball, David W. (david Warren), BAER, Tomas
Publisher: Wadsworth Cengage Learning,
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 19, Problem 19.68E
Interpretation Introduction
Interpretation:
The average displacement of one atom of
Concept introduction:
The average displacement of the molecule in three dimensions is given by,
Where,
•
•
Displacement is a vector quantity while distance is scalar quantity. Distance can be calculated with the help of average velocity.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
Q6. (a)The vander waals equation is used to describe the behaviour
of real gases but still not so useful in many industrial
applications. Explain why?(3)
(b)In kinetic molecular theory of gases it is assumed that
The molecules of the gases occupy negligible volume as compared
to the total volume of the gas' which factor can be actually
described by this postulate?(2)
1.3 mole of helium gas at a temperature of 276 K is confined to a cubical container whose sides are 12 cm long.Find the mean summed kinetic energy of ALL the atoms in the container in [J].
why does small particles have higher Brownian diffusion rates than larger particles.
Chapter 19 Solutions
Physical Chemistry
Ch. 19 - Prob. 19.1ECh. 19 - What is the kinetic energy of a single atom of...Ch. 19 - Prob. 19.3ECh. 19 - One mole of Ne atoms confined to a volume of 10.0L...Ch. 19 - Prob. 19.5ECh. 19 - Prob. 19.6ECh. 19 - Prob. 19.7ECh. 19 - Prob. 19.8ECh. 19 - Prob. 19.9ECh. 19 - Prob. 19.10E
Ch. 19 - Prob. 19.11ECh. 19 - Interstellar space can be considered as having...Ch. 19 - Prob. 19.13ECh. 19 - SF6 is a gas at room temperature, 295K. What is...Ch. 19 - Prob. 19.15ECh. 19 - Prob. 19.16ECh. 19 - If relativistic effects were ignored, what...Ch. 19 - Prob. 19.18ECh. 19 - Prob. 19.19ECh. 19 - Prob. 19.20ECh. 19 - Prob. 19.21ECh. 19 - Prob. 19.22ECh. 19 - Prob. 19.23ECh. 19 - Prob. 19.24ECh. 19 - What is the ratio of vrms/vmostprob for any gas at...Ch. 19 - Prob. 19.26ECh. 19 - Prob. 19.27ECh. 19 - Prob. 19.28ECh. 19 - Prob. 19.29ECh. 19 - Prob. 19.30ECh. 19 - Prob. 19.31ECh. 19 - The previous exercise gives an expression for...Ch. 19 - Prob. 19.33ECh. 19 - Prob. 19.34ECh. 19 - Prob. 19.35ECh. 19 - What must the pressure be if the mean free path of...Ch. 19 - Prob. 19.37ECh. 19 - Prob. 19.38ECh. 19 - Prob. 19.39ECh. 19 - Explain why the molecular diameter for argon, at...Ch. 19 - Prob. 19.41ECh. 19 - Prob. 19.42ECh. 19 - Prob. 19.43ECh. 19 - A 1.00-mol sample of Xe gas is kept at a...Ch. 19 - Prob. 19.45ECh. 19 - Prob. 19.46ECh. 19 - Prob. 19.47ECh. 19 - Prob. 19.48ECh. 19 - Prob. 19.49ECh. 19 - Consider a gas mixture containing equal...Ch. 19 - The inverse of the collision rate, 1/z, is the...Ch. 19 - Prob. 19.52ECh. 19 - Prob. 19.53ECh. 19 - Prob. 19.54ECh. 19 - Prob. 19.55ECh. 19 - Estimate the rate at which Hg effuses out a hole...Ch. 19 - Prob. 19.57ECh. 19 - Knudsen effusion cells are used to determine vapor...Ch. 19 - Prob. 19.59ECh. 19 - Prob. 19.60ECh. 19 - Prob. 19.61ECh. 19 - Prob. 19.62ECh. 19 - Prob. 19.63ECh. 19 - Prob. 19.64ECh. 19 - Prob. 19.65ECh. 19 - Prob. 19.66ECh. 19 - Prob. 19.67ECh. 19 - Prob. 19.68ECh. 19 - Prob. 19.69ECh. 19 - Prob. 19.70ECh. 19 - Prob. 19.71ECh. 19 - Prob. 19.72ECh. 19 - Prob. 19.73E
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- During the discussion of gaseous diffusion for enriching uranium, it was claimed that 235UF6 diffuses 0.4% faster than 238UF6. Show the calculation that supports this value. The molar mass of 235UF6 = 235.043930 + 6 ×18.998403 = 349.034348 g/mol, and the molar mass of 238UF6 = 238.050788 + 6 × 18.998403 = 352.041206 g/mol.arrow_forwardthe heavy gas particles took twice as long to diffuse as the light gas particles. This means that the light as particles are moving twice as fast, VH/VL= ½. Therefore, VH2/VL2= ¼. How many times heavier is the heavy gas compared to the light gas?arrow_forwardDuring the discussion of gaseous diffusion for enriching uranium, it was claimed that 235UF6 diffuses 0.4% faster than 238UF6. Show the calculation that supports this value. The molar mass of 235UF6 = 235.043930 + 6 x 18.998403 = 349.034348 g/mol, and the molar mass of 238UF6 = 238.050788 + 6 x 18.998403 = 352.041206 g/mol.arrow_forward
- The diameter of a Ne atom is 140 pm. What is the mean free path in nm of 0.5 mol Ne confined in 5 L at 300 K and 9.87 x 104 Pa?arrow_forwardCalculate the time required for molecules to diffuse in a liquid a distance of 10^(−3) cm. Assume that the average velocity of the molecules is 10^4 cm/sec and that the mean free path is 10^(−8) cm. Repeat the calculation for the time of diffusion in a gas at 1 atm pressure, where the mean free path is 10^(−5) cm.arrow_forward70.0 cm³ of a mixture of methane and ethane were mixed with 250 cm³ of oxygen at room temperature and pressure and the mixture was exploded. On cooling back to the initial room conditions, the volume of the gases was 160 cm³, which was reduced to 50.0 cm³ on passing through aqueous sodium hydroxide. Calculate the volume of methane and ethane in the mixture.arrow_forward
- Calculate the most probable speed of oxygen (O2) molecules in a gas at T = 334 K, O2 atomic mass is 32 amu, where the atomic mass unit (amu) is 1.66 x 10-27 kg. Provide your answer in units of meters per second, but do not include the units in your answer, just the number in normal form to 3 significant digitsarrow_forwardwhere m stands for the mass of the particle, v stands for the particle speed, T stands for the Temperature of the system, and k stands for the Boltzmann constant. What would be the relative average kinetic energies for the helium, neon, and argon at 100K? (think about what this would mean for each variable) Explain how you assigned the relative positions of each gas.arrow_forward6. At 100°C and 16.0 kPa, the mass density of phosphorus vapor is 0.6388 kg/m³. What is the molecular formula of phosphorus under these conditions?arrow_forward
- dN F(V)dV = N M = 47(- `2 zRT" ,MV². 32v² exp(- 2RT AP(- Where dN, the number of particles having a velocity between v and v+dV, V velocity of molecules, M moleculer mass of gase, T temperature. = [v? fV)dV =?arrow_forwardDescribe in your own words the Kinetic Molecular Theory of gases. The Kinetic Molecular Theory of gases tells us that the energy content of any gas is related only to its temperature. It also tells us that it is possible to compute the "RMS" (root mean squared) velocity of any gas molecule if you know its formula weight and its temperature. Using this information describe how you might compute the RMS velocity of sulfur dioxide (SO2) in the atmosphere of the planet Venus (T = 820 F), the RMS velocity of oxygen (O2) in the atmosphere of Earth (T = 50 F), or the RMS velocity of carbon dioxide (CO2) in the atmosphere of Mars (T = - 80 F).arrow_forwardYou are working in an oil refinery. Where you use hydrocarbon gases like methane (CH4), ethane (C2H), and propane (C3H8) and prepared a mixture, When measured the pressure at 25°C it turns out to be 7.50 atm. This gas mixture was then also used in a mass spectrophotometer and the following data was obtained. Based on this information find the partial pressure of each gas and report respectively as their name appeared in the question 10 30 40 50 Molecular maaNs (amu) اخترأحد الخبارات a. 2.3 atm, 3.8 atm, 1.4 atmO b. 4.0 atm, 1.5 atm, 2.5 atm O 2.1 atm, 4.0 atm, 1.4 atm O d. 3.8 atm, 1.4 atm, 23 atm e. 1.4 atm, 2.3 atm, 3.8 atmO Intensity of peaksarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY
Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Chemistry
Chemistry
ISBN:9781259911156
Author:Raymond Chang Dr., Jason Overby Professor
Publisher:McGraw-Hill Education
Principles of Instrumental Analysis
Chemistry
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Cengage Learning
Organic Chemistry
Chemistry
ISBN:9780078021558
Author:Janice Gorzynski Smith Dr.
Publisher:McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning
Elementary Principles of Chemical Processes, Bind...
Chemistry
ISBN:9781118431221
Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:WILEY