Atkins' Physical Chemistry
Atkins' Physical Chemistry
11th Edition
ISBN: 9780198769866
Author: ATKINS, P. W. (peter William), De Paula, Julio, Keeler, JAMES
Publisher: Oxford University Press
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Chapter 19, Problem 19.5IA

(a)

Interpretation Introduction

Interpretation:

The thermodynamic limit to the zero-current potential of fuel cells operating on hydrogen and oxygen has to be calculated.

(a)

Expert Solution
Check Mark

Explanation of Solution

The zero-current potential of fuel cell operating on hydrogen and oxygen is calculated as,

    E0=rG0νFH2+12O2CO2+2H2O rG0=-237KJ/molν=2E0=rG0νF=-(-237kJ/mol)2×96.48kC/mol=+1.23V.

(b)

Interpretation Introduction

Interpretation:

The thermodynamic limit to the zero-current potential of fuel cells operating on methane and air has to be calculated.

(b)

Expert Solution
Check Mark

Explanation of Solution

The zero-current potential of fuel cell operating on methane and air is calculated as,

    E0=rG0νFCH4+2O2CO2+2H2O ΔrG0=2ΔfG0(H2O)+ΔfG0(CO2)-ΔfG0(CH4) =[(2)×(-237.1)+ (-394.4)-(-50.7)]KJ/mol=817.9KJ/molν=8E0=rG0νF=-(817.9KJ/mol)8×96.48kC/mol=+1.06V

(c)

Interpretation Introduction

Interpretation:

The thermodynamic limit to the zero-current potential of fuel cells operating on propane and air has to be calculated.

(c)

Expert Solution
Check Mark

Explanation of Solution

The zero-current potential of fuel cell operating on propane and air is calculated as,

    E0=rG0νFC3H8+5O23CO2+4H2O ΔrG0=4ΔfG0(H2O)+fG0(CO2)-ΔfG0(C3H8) =[(4)(-237.1)+ 3(-394.4)-(-23.4)]KJ/mol=-2108.2KJ/molν=16E0=rG0νF=-(-2108.2KJ/mol)16×96.48kC/mol=+1.36V.

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