Chemistry: Matter and Change
Chemistry: Matter and Change
1st Edition
ISBN: 9780078746376
Author: Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher: Glencoe/McGraw-Hill School Pub Co
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Chapter 19, Problem 15STP
Interpretation Introduction

Interpretation:

The chemical which will dissociate into greatest number of particles out of given five is to be calculated.

Concept introduction:

Molarity of the substance helps to calculate the number of moles of that substance. Then number of moles helps to calculate number of particles in aqueous solution.

Molarity=numberofmolesofsolutevolumeofsolutioninliters

numberofparticles=numberofmoles×6.023×1023

Expert Solution & Answer
Check Mark

Answer to Problem 15STP

Chemical C will dissociate into greatest particles in aqueous solution.

Explanation of Solution

Given data:

V=500mL=5001000LMolarity=0.25M

KCl dissociates into K+andCl in aqueous solution.

Therefore number of particles of KCl=2×6.023×1023×0.250×0.5=1.51×1023

Number of moles of CH3OH=6.023×1023×0.250×0.5=0.75×1023

Ba(OH)2 dissociates into three ions.

Therefore, number of moles of Ba(OH)2=3×6.023×1023×0.250×0.5=2.26×1023

Number of moles of CH3COOH=6.023×1023×0.250×0.5=0.75×1023

NaOH dissociate into two ions.

Therefore number of moles of NaOH=2×6.023×1023×0.250×0.5=1.51×1023

Ba(OH)2 has greatest number of particles in aqueous solution.

Conclusion

Because Ba(OH)2 dissociates into maximum ions in aqueous solution, it has greatest number of particles.

Chapter 19 Solutions

Chemistry: Matter and Change

Ch. 19.1 - Prob. 11SSCCh. 19.1 - Prob. 12SSCCh. 19.1 - Prob. 13SSCCh. 19.1 - Prob. 14SSCCh. 19.2 - Prob. 15PPCh. 19.2 - Prob. 16PPCh. 19.2 - Prob. 17PPCh. 19.2 - Prob. 18PPCh. 19.2 - Prob. 19PPCh. 19.2 - Prob. 20PPCh. 19.2 - Prob. 21PPCh. 19.2 - Prob. 22PPCh. 19.2 - Prob. 23PPCh. 19.2 - Prob. 24PPCh. 19.2 - Prob. 25PPCh. 19.2 - Prob. 26SSCCh. 19.2 - Prob. 27SSCCh. 19.2 - Prob. 28SSCCh. 19.2 - Prob. 29SSCCh. 19.2 - Prob. 30SSCCh. 19.2 - Prob. 31SSCCh. 19.2 - Prob. 32SSCCh. 19 - Prob. 33ACh. 19 - Prob. 34ACh. 19 - Prob. 35ACh. 19 - Prob. 36ACh. 19 - Prob. 37ACh. 19 - Prob. 38ACh. 19 - Prob. 39ACh. 19 - Prob. 40ACh. 19 - Prob. 41ACh. 19 - Prob. 42ACh. 19 - Prob. 43ACh. 19 - Prob. 44ACh. 19 - Prob. 45ACh. 19 - Prob. 46ACh. 19 - Prob. 47ACh. 19 - Prob. 48ACh. 19 - Prob. 49ACh. 19 - Prob. 50ACh. 19 - Prob. 51ACh. 19 - Prob. 52ACh. 19 - Prob. 53ACh. 19 - Prob. 54ACh. 19 - Prob. 55ACh. 19 - Prob. 56ACh. 19 - Prob. 57ACh. 19 - Prob. 58ACh. 19 - Prob. 59ACh. 19 - Prob. 60ACh. 19 - Prob. 61ACh. 19 - Prob. 62ACh. 19 - Prob. 63ACh. 19 - Prob. 64ACh. 19 - Prob. 65ACh. 19 - Prob. 66ACh. 19 - Prob. 67ACh. 19 - Prob. 68ACh. 19 - Prob. 69ACh. 19 - Prob. 70ACh. 19 - Prob. 71ACh. 19 - Prob. 72ACh. 19 - Prob. 73ACh. 19 - Prob. 74ACh. 19 - Prob. 75ACh. 19 - Prob. 76ACh. 19 - Prob. 77ACh. 19 - Prob. 78ACh. 19 - Prob. 79ACh. 19 - Prob. 80ACh. 19 - Prob. 81ACh. 19 - Prob. 82ACh. 19 - Prob. 83ACh. 19 - Prob. 84ACh. 19 - Prob. 85ACh. 19 - Prob. 86ACh. 19 - Prob. 87ACh. 19 - Prob. 88ACh. 19 - Prob. 89ACh. 19 - Prob. 90ACh. 19 - Prob. 91ACh. 19 - Prob. 92ACh. 19 - Prob. 93ACh. 19 - Prob. 94ACh. 19 - Prob. 95ACh. 19 - Prob. 96ACh. 19 - Prob. 1STPCh. 19 - Prob. 2STPCh. 19 - Prob. 3STPCh. 19 - Prob. 4STPCh. 19 - Prob. 5STPCh. 19 - Prob. 6STPCh. 19 - Prob. 7STPCh. 19 - Prob. 8STPCh. 19 - Prob. 9STPCh. 19 - Prob. 10STPCh. 19 - Prob. 11STPCh. 19 - Prob. 12STPCh. 19 - Prob. 13STPCh. 19 - Prob. 14STPCh. 19 - Prob. 15STPCh. 19 - Prob. 16STPCh. 19 - Prob. 17STPCh. 19 - Prob. 18STP
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