Chapter 18, Problem 50R

To determine

Towrite: the chemical names for ${\text{Fe}}_{\text{2}}{\text{S}}_{\text{3}}$ , $\text{Cu}\left({\text{ClO}}_{\text{3}}\right)$, ${\text{Ca}}_{\text{3}}{\left({\text{PO}}_{\text{4}}\right)}_{\text{2}}$ and ${\left({\text{NH}}_{\text{4}}\right)}_{\text{2}}{\text{SO}}_{\text{4}}$.

Explanation of Solution

Introduction:

A chemical formula is a way of describing the chemical proportions of atoms that make a particular chemical compound or molecule.

The names of given compounds are written below:

  ${\text{Fe}}_{\text{2}}{\text{S}}_{\text{3}}$= Iron (III) Sulfide (sulfide is monoatomic ion).

  $\text{Cu}\left({\text{ClO}}_{\text{3}}\right)$= copper (II) chlorate ( chlorate is polyatomic ion).

  ${\text{Ca}}_{\text{3}}{\left({\text{PO}}_{\text{4}}\right)}_{\text{2}}$= Calcium (II) phosphate (phosphate is polyatomic ion).

  ${\left({\text{NH}}_{\text{4}}\right)}_{\text{2}}{\text{SO}}_{\text{4}}$= ammonium sulfate (ammonium and sulfate both are polyatomic).

Conclusion:

Hence,formula for for ${\text{Fe}}_{\text{2}}{\text{S}}_{\text{3}}$ , $\text{Cu}\left({\text{ClO}}_{\text{3}}\right)$, ${\text{Ca}}_{\text{3}}{\left({\text{PO}}_{\text{4}}\right)}_{\text{2}}$ and ${\left({\text{NH}}_{\text{4}}\right)}_{\text{2}}{\text{SO}}_{\text{4}}$ areIron (III) Sulfide, copper (II) chlorate, Calcium (II) phosphate and ammonium sulfate respectively.