ALEKS 360 ACCESS CARD F/GEN. ORG.CHEM
ALEKS 360 ACCESS CARD F/GEN. ORG.CHEM
3rd Edition
ISBN: 9781264452545
Author: SMITH
Publisher: MCG
Question
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Chapter 18, Problem 18.82P
Interpretation Introduction

(a)

Interpretation:

The given amine needs to be labeled as 10, 20 or 30.

Concept introduction:

Amines are derivatives which are derived from ammonia, wherein one or more hydrogen atoms have been replaced by a substituent such as an alkyl or aryl group. They can be called as alkylamines and arylamines.

Expert Solution
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Answer to Problem 18.82P

A tertiary (3o) amine.

Explanation of Solution

Amines are derivatives which are derived from ammonia, wherein one or more hydrogen atoms have been replaced by a substituent such as an alkyl or aryl group. They can be called as alkylamines and arylamines.

Whether an amine is primary (1o), secondary (2o) or tertiary (3o) depends on the number of hydrogen atoms replaced by an alkyl or aryl group in ammonia. The amine is a primary amine if one hydrogen atom is replaced, it is a secondary amine if 2 hydrogen atoms are replaced and if three hydrogen atoms are replaced it is known as a tertiary amine.

The given compound is as follows:

  ALEKS 360 ACCESS CARD F/GEN. ORG.CHEM, Chapter 18, Problem 18.82P , additional homework tip  1

Here, only one hydrogen atom is replaced and therefore this amine called as a primary (1o) amine.

Interpretation Introduction

(b)

Interpretation:

The molecular shape around each atom of phentermine needs to be determined.

Concept introduction:

Molecular geometry is named as molecular shape and it is the three-dimensional arrangement of atoms within a molecule of the environment. Atoms arrange in space with an exact shape to minimize the repulsion. This can be determined using VSEPR theory.

Expert Solution
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Answer to Problem 18.82P

Carbons of benzene molecule;trigonal planar.

Carbon of −CH2 / -C(CH3)2NH2 CH2-/-CH3;tetrahedral.

Nitrogen of NH2;trigonal pyramidal.

Explanation of Solution

VSEPR or Valence Shell Electron Pair Repulsion theory is a model used to determine the geometry of molecules considering minimum electrostatic repulsion between the valence electrons of central atom in the molecule.

  ALEKS 360 ACCESS CARD F/GEN. ORG.CHEM, Chapter 18, Problem 18.82P , additional homework tip  2

  ALEKS 360 ACCESS CARD F/GEN. ORG.CHEM, Chapter 18, Problem 18.82P , additional homework tip  3

Carbons of benzene molecule;

Number of bonds= 3

Number of lone pairs = 0

Therefore, the shape is trigonal planar.

Carbon of −CH2/ -C(CH3)2NH2CH2-/-CH3;

Number of bonds= 4

Number of lone pairs = 0

Therefore, the shape is tetrahedral.

Nitrogen of NH2;

Number of bonds= 3

Number of lone pairs = 1

Therefore, the shape is trigonal pyramidal.

Interpretation Introduction

(c)

Interpretation:

The constitutional isomer containing a primary amine needs to be determined.

Concept introduction:

Constitutional isomers are called as compounds that have the unique molecular formula and different structural connectivity. To determine whether two molecules are constitutional isomer, the number of each atom needs to be counted in both molecules and see how the atoms are arranged.

Expert Solution
Check Mark

Answer to Problem 18.82P

  ALEKS 360 ACCESS CARD F/GEN. ORG.CHEM, Chapter 18, Problem 18.82P , additional homework tip  4

Explanation of Solution

Whether an amine is primary (1o), secondary (2o) or tertiary (3o) depends on the number of hydrogen atoms replaced by an alkyl or aryl group in ammonia. The amine is a primary amine if one hydrogen atom is replaced, it is a secondary amine if 2 hydrogen atoms are replaced and if three hydrogen atoms are replaced it is known as a tertiary amine.

  ALEKS 360 ACCESS CARD F/GEN. ORG.CHEM, Chapter 18, Problem 18.82P , additional homework tip  5

Here all one hydrogen atom is replaced and therefore this amine called a primary amine (1o).

Interpretation Introduction

(d)

Interpretation:

The constitutional isomer that contains a secondary amine needs to be determined.

Concept introduction:

Constitutional isomers are called as compounds that have the unique molecular formula and different structural connectivity. To determine whether two molecules are constitutional isomer, the number of each atom needs to be counted in both molecules and see how the atoms are arranged.

Expert Solution
Check Mark

Answer to Problem 18.82P

  ALEKS 360 ACCESS CARD F/GEN. ORG.CHEM, Chapter 18, Problem 18.82P , additional homework tip  6

Explanation of Solution

Whether an amine is primary (1o), secondary (2o) or tertiary (3o) depends on the number of hydrogen atoms replaced by an alkyl or aryl group in ammonia. The amine is a primary amine if one hydrogen atom is replaced, it is a secondary amine if 2 hydrogen atoms are replaced and if three hydrogen atoms are replaced it is known as a tertiary amine.

  ALEKS 360 ACCESS CARD F/GEN. ORG.CHEM, Chapter 18, Problem 18.82P , additional homework tip  7

Here all 3 hydrogen atoms are replaced and therefore this amine called as a secondary amine (2o).

Interpretation Introduction

(e)

Interpretation:

The structure of phentermine hydrobromide molecule needs to be drawn.

Concept introduction:

Phentermine hydrobromide can stimulate the central nervous system and increases the blood pressure and heart rate which decreases the appetite. It is taken along with diet and exercise in order to reduce obesity.

Expert Solution
Check Mark

Answer to Problem 18.82P

  ALEKS 360 ACCESS CARD F/GEN. ORG.CHEM, Chapter 18, Problem 18.82P , additional homework tip  8

Explanation of Solution

Phentermine hydrobromide can stimulate the central nervous system and increases the blood pressure and heart rate which decreases the appetite. It is taken along with the diet and exercise in order to reduce the obesity.

Its molecular formula is C17H22BrN. It has the following structure.

  ALEKS 360 ACCESS CARD F/GEN. ORG.CHEM, Chapter 18, Problem 18.82P , additional homework tip  9

Interpretation Introduction

(f)

Interpretation:

The products formed if phentermine is treated with benzoic acid needs to be determined.

Concept introduction:

Amines are derivatives which are derived from ammonia, wherein one or more hydrogen atoms have been replaced by a substituent such as an alkyl or aryl group. They can be called as alkylamines and arylamines.

Expert Solution
Check Mark

Answer to Problem 18.82P

  ALEKS 360 ACCESS CARD F/GEN. ORG.CHEM, Chapter 18, Problem 18.82P , additional homework tip  10

Explanation of Solution

Amines are derivatives which are derived from ammonia, wherein one or more hydrogen atoms have been replaced by a substituent such as an alkyl or aryl group. They can be called as alkylamines and arylamines.

Whether an amine is primary (1o), secondary (2o) or tertiary (3o) depends on the number of hydrogen atoms replaced by an alkyl or aryl group in ammonia. The amine is a primary amine if one hydrogen atom is replaced, it is a secondary amine if 2 hydrogen atoms are replaced and if three hydrogen atoms are replaced it is known as a tertiary amine.

Benzphetamine is a tertiary ammine. It has basic properties and it accepts protons from acids. Acetic acid is donated a proton to this amine and formed below the salt.

  ALEKS 360 ACCESS CARD F/GEN. ORG.CHEM, Chapter 18, Problem 18.82P , additional homework tip  11

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Synthadotin is a promising anticancer drug in clinical trials. a.Identify the functional groups. b.Classify any amine or amide as 1°, 2°, or 3°. c.At which sites can synthadotin hydrogen bond to another molecule like itself? d. Label two nucleophilic sites. e. Label two electrophilic sites. f. What product is formed when synthadotin is treated with HCl?
V. Classify each amine as 1', 2 or 3'. Give the IUPAC name for each amine. CH3 a. CH3CHCH,CH2NHCH3 b. CH3-C-CH,NH2 ČH3 ČH3
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Chapter 18 Solutions

ALEKS 360 ACCESS CARD F/GEN. ORG.CHEM

Ch. 18.5 - Prob. 18.11PCh. 18.5 - Prob. 18.12PCh. 18.5 - Prob. 18.13PCh. 18.6 - Prob. 18.14PCh. 18.6 - Prob. 18.15PCh. 18.6 - Prob. 18.16PCh. 18.6 - Name each ammonium salt. a. ( CH3 NH3)+Cl b. [( CH...Ch. 18.6 - Prob. 18.18PCh. 18.6 - Prob. 18.19PCh. 18.7 - Prob. 18.20PCh. 18.7 - Prob. 18.21PCh. 18.8 - Prob. 18.22PCh. 18.8 - Prob. 18.23PCh. 18.8 - Prob. 18.24PCh. 18.9 - Prob. 18.25PCh. 18.9 - Prob. 18.26PCh. 18.9 - Prob. 18.27PCh. 18.10 - Prob. 18.28PCh. 18 - Prob. 18.29PCh. 18 - Prob. 18.30PCh. 18 - Prob. 18.31PCh. 18 - Prob. 18.32PCh. 18 - Prob. 18.33PCh. 18 - Prob. 18.34PCh. 18 - Prob. 18.35PCh. 18 - Prob. 18.36PCh. 18 - Prob. 18.37PCh. 18 - Prob. 18.38PCh. 18 - Give an acceptable name for each amine. a. b.Ch. 18 - Give an acceptable name for each amine. a. b.Ch. 18 - Give an acceptable name for each amine. a. b. c....Ch. 18 - Give an acceptable name for each amine. a. CH3(...Ch. 18 - Prob. 18.43PCh. 18 - Prob. 18.44PCh. 18 - Prob. 18.45PCh. 18 - Prob. 18.46PCh. 18 - Prob. 18.47PCh. 18 - Prob. 18.48PCh. 18 - Prob. 18.49PCh. 18 - Prob. 18.50PCh. 18 - Which compound in each pair has the higher boiling...Ch. 18 - Which compound in each pair has the higher boiling...Ch. 18 - Draw the hydrogen-bonding interactions that occur...Ch. 18 - Prob. 18.54PCh. 18 - Prob. 18.55PCh. 18 - Which compound has the higher water solubility:...Ch. 18 - Prob. 18.57PCh. 18 - Prob. 18.58PCh. 18 - Draw the products of each acid-base reaction. a....Ch. 18 - Draw the products of each acid-base reaction. a....Ch. 18 - Prob. 18.61PCh. 18 - Prob. 18.62PCh. 18 - What type of nitrogen heterocycle occurs in both...Ch. 18 - Only one of the N atoms in nicotine has a trigonal...Ch. 18 - Prob. 18.65PCh. 18 - Prob. 18.66PCh. 18 - Why are aqueous solutions of an alkaloid slightly...Ch. 18 - Prob. 18.68PCh. 18 - Prob. 18.69PCh. 18 - Explain why patients with Parkinson’s disease...Ch. 18 - Prob. 18.71PCh. 18 - Prob. 18.72PCh. 18 - Prob. 18.73PCh. 18 - Prob. 18.74PCh. 18 - Prob. 18.75PCh. 18 - Prob. 18.76PCh. 18 - Prob. 18.77PCh. 18 - Prob. 18.78PCh. 18 - Prob. 18.79PCh. 18 - Prob. 18.80PCh. 18 - Prob. 18.81PCh. 18 - Prob. 18.82PCh. 18 - Prob. 18.83PCh. 18 - Prob. 18.84PCh. 18 - Prob. 18.85PCh. 18 - Prob. 18.86PCh. 18 - Prob. 18.87PCh. 18 - Why do some antihistamines cause drowsiness while...Ch. 18 - Prob. 18.89PCh. 18 - Prob. 18.90PCh. 18 - Compare the structures of morphine and heroin....Ch. 18 - Prob. 18.92CP
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