Chapter 18, Problem 18.40E

Interpretation Introduction

Interpretation:

The values of $q_{\text{rot}}$ for ${\text{NO}}_{\text{2}}$$\left(\sigma =2\right)$ at $295\text{K}$ and $400\text{K}$ are to be calculated.

Concept introduction:

The $q_{\text{rot}}$ is given by the formula,

$q_{\text{rot}}=\frac{T}{\sigma {\theta }_r}$

The $q_{\text{rot}}$ for polyatomic molecules is given by the formula,

$q_{\text{rot}}=\frac{{\pi }^{1/2}}{\sigma }{\left(\frac{T^3}{{\theta }_{\text{r, A}}\cdot {\theta }_{\text{r, B}}\cdot {\theta }_{\text{r, C}}}\right)}^{1/2}$