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To propose:
A mechanism for the inhibition of CK-B translation in the U937D cells.
Introduction:
Eukaryotic mRNAs have long 3′ UTR that often contains consensus sequences. CK-B is an important enzyme in the cellular
To explain:
The way in which introduction of short segments of RNA containing the 3’ UTR sequences that might remove that inhibition.
Introduction:
Researchers have introduced numerous short RNA segments containing 3′ UTR sequences only into U937D cells. As a result, these cells began to synthesize CK-B but this does not affect the CK-B mRNA amount. The introduction of short segments did not stimulate the CK-B synthesis, only the 3′ UTR sequences turned on the enzyme translation.
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Chapter 17 Solutions
Genetics: A Conceptual Approach
- Western blot results: what information can you get? Presence of proteins of your interest Levels of protein expression Levels of protein activation (must use activation state-specific antibody) Decreased function of the ATM kinase in aging mice. A C57BL/6 female 6 month Con IR 20 month C57BL/6 male 6 month 28 month Con IR Con IR Con IR p-ATM (S1981) ATM P-p53 (ser18) Actinarrow_forwardDoes it show the level of proteins? What about the amount? Levels of protein activation? How can you tell? Does the thickness tell you anything? What about the number of the lines?arrow_forwardWB: Protein of interest visualized by fluorescent Protein A Protein Barrow_forward
- Question #4: Assume you are able to use CRISPR to create an allele that will convert a cross-pollinated, sexually reproducing crop plant into an obligate apomict. Your edited obligate apomict plants retains all the CRISPR "machinery" necessary to convert the "sexually reproducing" allele to the "obligate apomict" allele. You plant 100 hectares of your edited obligate apomicts in order to increase seed for sale the following year. Neighboring farms and seed producers are growing many different un-edited sexually reproducing varieties of the crop. If your neighbors plant seed harvested from their crops that was pollinated by your crop, should they expect these seeds to generate apomictic or non-apomictic plants? Type your answer here:arrow_forwardcalculate the questions showing the solution including variables,unit and equations all the questiosn below using the data.show solving and answer a) B1, b) B2, c) hybrid rate constant (1) d) hybrid rate constant (2) e) t1/2,dist t1/2,absorb f) t1/2,elim k) apparent central compartment volume (V1,app) p) total AUC (using short cut method) apparent volume of distribution based on AUC (VAUC,app) apparent clearance (CLapp) absolute bioavailabilty of oral route ( AUCiv =116ml)arrow_forwardPlease help me to draw this by hand. In as much detail as possible, hand draw a schematic diagram of the hypothalamic-pituitary-gonad (HPG) axis in the human female. Be sure to include all the relevant structures and hormones. You must define all abbreviations the first time you use them. Please include (and explain) the feedback loops.arrow_forward
- "One of the symmetry breaking events in mouse gastrulation requires the amplification of Nodal on the side of the embryo opposite to the Anterior Visceral Endoderm (AVE). Describe one way by which Nodal gets amplified in this region." My understanding of this is that there are a few ways nodal is amplified though I'm not sure if this is specifically occurs on the opposite side of the AVE. 1. pronodal cleaved by protease -> active nodal 2. Nodal -> BMP4 -> Wnt-> nodal 3. Nodal-> Nodal, Fox1 binding site 4. BMP4 on outside-> nodal Are all of these occuring opposite to AVE?arrow_forwardIf four babies are born on a given day What is the chance all four will be girls? Use genetics lawsarrow_forwardExplain each punnet square results (genotypes and probabilities)arrow_forward
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