Chapter 17.2, Problem 16SSC

Interpretation Introduction

Interpretation:

The given concentrations of the reactants and the products are to be compared and the value of K at different concentrations needs to be compared with the given value of K at equilibrium.

Concept introduction:

The equilibrium constant of reaction depends on the reactants products and their coefficients.

Answer to Problem 16SSC

Yes both the mixtures are at different equilibrium positions.

Explanation of Solution

For the given equation:

$\begin{array}{l}2A\stackrel{}{\rightleftarrows }B\\ K_{eq}=\frac{[B]}{{[A]}^2}\end{array}$

In the first set of concentrations,

$\begin{array}{l}[A]=0.0100\\ [B]=0.0200\\ K_{eq}=\frac{0.02}{{0.01}^2}\\ K_{eq}=200\end{array}$

Which is equal to given value of K.

In the second set of concentrations,

$\begin{array}{l}[A]=0.0500\\ [B]=0.500\\ K_{eq}=\frac{0.5}{{0.05}^2}\\ K_{eq}=200\end{array}$

Which is equal to given value of K.

Conclusion

Both the reaction mixtures are at equilibrium as their constants match with the reaction equilibrium constant.