Explanation Given information: The load at point C is F C = P . Load intensity at B D is w = 20 kN/m . The allowable bearing stress for the plates is σ b a l l o w = 1.8 MPa . Cross section dimension at plate A ' is 200 mm × 200 mm . Cross section dimension at plate B ' is 300 mm × 300 mm . Free body diagram of beam: For the beam to be in equilibrium, ∑ F V = 0 ∑ M A = 0 Bearing stress in plate is given by using the formula of bearing stress. σ C = F b e a r i n g A b a s e p l a t e Base plate area is given by: A b a s e p l a t e = l b a s e p l a t e × b b a s e p l a t e Calculation: For the vertical equilibrium of beam, ∑ F V = 0 R A − w × B D − F C + R B = 0 R A + R B = w × A D + F C R A + R B = 20 kN/m × 2 m + P R A + R B = 40 kN + P ............ 1 For the moment equilibrium about A . ∑ M A = 0 w × B D × A B + B D 2 + F C × A C − R B × A B = 0 20 kN/m × 2 m × 4 + 2 2 m + P × 2 m − R B × 4 m = 0 200 kN-m + 2 P m = R B × 4 m R B = 2 P m + 20 kN-m 4 m R B = 0.5 P + 5 kN

11th Edition

ISBN: 9780137605460

Author: Russell C. Hibbeler

Publisher: Pearson Education (US)

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Chapter 1.7, Problem 84P

To determine

The maximum load P .

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Chapter 1.7, Problem 83P

Chapter 1.7, Problem 85P

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The maximum load P .

Solution Summary: The author explains the maximum load P and the allowable bearing stress for the plates.

The maximum load P .

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