(a)
Interpretation:
The oxidation number has to be assigned to each atom of the given reaction. The substance that is oxidized, reduced, oxidizing agent and reducing agent have to be stated.
Concept Introduction:
(a)
Answer to Problem 7QRT
The oxidation number of
The oxidation number of
Explanation of Solution
The given reaction is shown below.
The oxidation number of any element in its native form is zero. So, the oxidation number of
In almost all compounds oxidation number of bromine is
Apply charge balance formula in
Therefore, the oxidation number of iron in
The element that gets oxidized reduces the other one and is known as reducing agent. The element that gets reduced oxidizes the other one and is known as oxidizing agent.
In the given reaction, the oxidation number of
The oxidation number of
(b)
Interpretation:
The oxidation number has to be assigned to each atom of the given reaction. The substance that is oxidized, reduced, oxidizing agent and reducing agent have to be stated.
Concept Introduction:
Refer to part (a).
(b)
Answer to Problem 7QRT
The oxidation number of
The oxidation number of
Explanation of Solution
The given reaction is shown below.
The oxidation number of any element in its native form is zero. So, the oxidation number of
In almost all compounds oxidation number of chlorine is
Apply charge balance formula in
Therefore, the oxidation number of aluminium in
The element that gets oxidized reduces the other one and is known as reducing agent. The element that gets reduced oxidizes the other one and is known as oxidizing agent.
In the given reaction, the oxidation number of
The oxidation number of
(c)
Interpretation:
The oxidation number has to be assigned to each atom of the given reaction. The substance that is oxidized, reduced, oxidizing agent and reducing agent have to be stated.
Concept Introduction:
Refer to part (a).
(c)
Answer to Problem 7QRT
The oxidation number of sulfur changes from
The oxidation number of
Explanation of Solution
The given reaction is shown below.
The oxidation number of any element in its native form is zero. So, the oxidation number of
In almost all compounds oxidation number of iodine is
Apply charge balance formula in
Therefore, the oxidation number of sulfur in
Apply charge balance formula in
Therefore, the oxidation number of sulfur in
The element that gets oxidized reduces the other one and is known as reducing agent. The element that gets reduced oxidizes the other one and is known as oxidizing agent.
In the given reaction, the oxidation number of sulfur changes from
The oxidation number of
(d)
Interpretation:
The oxidation number has to be assigned to each atom of the given reaction. The substance that is oxidized, reduced, oxidizing agent and reducing agent have to be stated.
Concept Introduction:
Refer to part (a).
(d)
Answer to Problem 7QRT
The oxidation number of
The oxidation number of
Explanation of Solution
The given reaction is shown below.
The oxidation number of any element carrying charge is equal to that charge. So, the oxidation number of
In almost all compounds oxidation number of hydrogen is
Apply charge balance formula in
Therefore, the oxidation number of oxygen in
Apply charge balance formula in
Therefore, the oxidation number of oxygen in
The element that gets oxidized reduces the other one and is known as reducing agent. The element that gets reduced oxidizes the other one and is known as oxidizing agent.
In the given reaction, the oxidation number of
The oxidation number of
(e)
Interpretation:
The oxidation number has to be assigned to each atom of the given reaction. The substance that is oxidized, reduced, oxidizing agent and reducing agent have to be stated.
Concept Introduction:
Refer to part (a).
(e)
Answer to Problem 7QRT
The oxidation number of
In the given reaction, the oxidation number of
The oxidation number of
Explanation of Solution
The given reaction is shown below.
The oxidation number of any element carrying charge is equal to that charge. So, the oxidation number of
In almost all compounds oxidation number of hydrogen is
Apply charge balance formula in
Therefore, the oxidation number of nitrogen in
Apply charge balance formula in
Therefore, the oxidation number of nitrogen in
Apply charge balance formula in
Therefore, the oxidation number of nitrogen in
Apply charge balance formula in
Therefore, the oxidation number of iron in
The element that gets oxidized reduces the other one and is known as reducing agent. The element that gets reduced oxidizes the other one and is known as oxidizing agent.
In the given reaction, the oxidation number of
In the given reaction, the oxidation number of
The oxidation number of
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Chapter 17 Solutions
OWLV2 FOR MOORE/STANITSKI'S CHEMISTRY:
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- Xenon trioxide, XeO3, reacts with aqueous base to form the xenate anion, HXeO4. This ion reacts further with OH to form the perxenate anion, XeO64, in the following reaction: 2HXeO4(aq)+2OH(aq)XeO64(aq)+Xe(g)+O2(g)+2H2O(l) Identify the elements that are oxidized and reduced in this reaction. You will note that the equation is balanced with respect to the number of atoms on either side. Verify that the redox part of this equation is also balanced, that is, that the extents of oxidation and reduction are also equal.arrow_forwardWrite the net ionic equation for the reaction, if any, that occurs on mixing (a) solutions of sodium hydroxide and magnesium chloride. (b) solutions of sodium nitrate and magnesium bromide. (c) magnesium metal and a solution of hydrochloric acid to produce magnesium chloride and hydrogen. Magnesium metal reacting with HCl.arrow_forwardBalance each of the following equations, and then write the net ionic equation. Show states for all reactants and products (s, . g, aq). (a) the reaction of sodium hydroxide and iron(II) chloride to give iron(II) hydroxide and sodium chloride (b) the reaction of barium chloride with sodium carbonate to give barium carbonate and sodium chloride (c) the reaction of ammonia with phosphoric acidarrow_forward
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