In the following exercises, solve for the antiderivative ∫ f of with C = 0, the given interval [a, b]. Approximate a value of C, if possible, such that adding C to the antidelivative gives the same value as the definite integral F ( x ) = ∫ a x f ( t ) d t . 422. [T] ∫ sin − 1 x 1 − x 2 over [−1, 1]
In the following exercises, solve for the antiderivative ∫ f of with C = 0, the given interval [a, b]. Approximate a value of C, if possible, such that adding C to the antidelivative gives the same value as the definite integral F ( x ) = ∫ a x f ( t ) d t . 422. [T] ∫ sin − 1 x 1 − x 2 over [−1, 1]
In the following exercises, solve for the antiderivative
∫
f
of with C = 0, the given interval [a, b]. Approximate a value of C, if possible, such that adding C to the antidelivative gives the same value as the definite integral
F
(
x
)
=
∫
a
x
f
(
t
)
d
t
.
422. [T]
∫
sin
−
1
x
1
−
x
2
over [−1, 1]
With differentiation, one of the major concepts of calculus. Integration involves the calculation of an integral, which is useful to find many quantities such as areas, volumes, and displacement.
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, subject and related others by exploring similar questions and additional content below.
Fundamental Theorem of Calculus 1 | Geometric Idea + Chain Rule Example; Author: Dr. Trefor Bazett;https://www.youtube.com/watch?v=hAfpl8jLFOs;License: Standard YouTube License, CC-BY