Degarmo's Materials And Processes In Manufacturing
13th Edition
ISBN: 9781119492825
Author: Black, J. Temple, Kohser, Ronald A., Author.
Publisher: Wiley,
expand_more
expand_more
format_list_bulleted
Concept explainers
Textbook Question
Chapter 17, Problem 38RQ
Define the various regimes of cold working, warm working, and hot working in terms of the melting point of the material being formed.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
۲/۱
A pump draws water through a 300-mm diameter cast iron pipe, 15m long from a reservoir
in which the water surface is 4.5 m higher than the pump and discharges through a 250-
mm diameter cast iron, 75 m long, to an elevated tank in which the water surface is 60 m
higher than the pump. Q = 0.25 m³/s. Considering f= 0.02 and the coefficients for minor
head losses (k entrance = 0.5, k hend 0.35, and K exit -0.5), compute the power of the pump.
4.5 m
300 mm dia.
15 m Length
250 mm dia.
75 m Length
kentrance
kexit
60 m
kbend
osther
A pump draws water through a 300-mm diameter cast iron pipe, 15m long from a reservoir
in which the water surface is 4.5 m higher than the pump and discharges through a 250-
mm diameter cast iron, 75 m long, to an elevated tank in which the water surface is 60 m
higher than the pump. Q = 0.25 m³/s. Considering f= 0.02 and the coefficients for minor
head losses (k entrance = 0.5, k hend = 0.35, and K exit 0.5), compute the power of the pump.
=
4.5 m
300 mm dia.
15 m Length
250 mm dia.
75 m Length
Kentrance
kexit
60 m
kbend
A pump draws water through a 300-mm diameter cast iron pipe, 15m long from a reservoir
in which the water surface is 4.5 m higher than the pump and discharges through a 250-
mm diameter cast iron, 75 m long, to an elevated tank in which the water surface is 60 m
higher than the pump. Q = 0.25 m³/s. Considering f= 0.02 and the coefficients for minor
head losses (k entrance = 0.5, k hend = 0.35, and K exit 0.5), compute the power of the pump.
=
4.5 m
300 mm dia.
15 m Length
250 mm dia.
75 m Length
Kentrance
kexit
60 m
kbend
Chapter 17 Solutions
Degarmo's Materials And Processes In Manufacturing
Ch. 17 - What is plasticity?Ch. 17 - What are some of the general assets of the...Ch. 17 - Why might large production quantities be necessary...Ch. 17 - What types of deformation may occur in forming...Ch. 17 - What is an independent variable in a...Ch. 17 - What are some considerations regarding selection...Ch. 17 - What is the significance of tool and die geometry...Ch. 17 - Why is lubrication often a major concern in metal...Ch. 17 - What are some of the secondary effects that may...Ch. 17 - Prob. 10RQ
Ch. 17 - Why is it important to be able to predict the...Ch. 17 - Prob. 12RQCh. 17 - Prob. 13RQCh. 17 - Prob. 14RQCh. 17 - Prob. 15RQCh. 17 - Prob. 16RQCh. 17 - Prob. 17RQCh. 17 - What are some of the features that may be...Ch. 17 - What features have contributed to the expanded use...Ch. 17 - What are some of the uses or applications of...Ch. 17 - Prob. 21RQCh. 17 - Prob. 22RQCh. 17 - Prob. 23RQCh. 17 - What type of information about the material being...Ch. 17 - Prob. 25RQCh. 17 - Why is friction such an important parameter in...Ch. 17 - Why are friction effects in metalworking difficult...Ch. 17 - Prob. 28RQCh. 17 - Prob. 29RQCh. 17 - Prob. 30RQCh. 17 - Prob. 31RQCh. 17 - Discuss the significance of wear in metal forming:...Ch. 17 - Lubricants are often selected for properties in...Ch. 17 - What is tribology?Ch. 17 - What are some of the common types of metal forming...Ch. 17 - What is hydrodynamic lubrication? What are some of...Ch. 17 - If the temperature of a material is increased,...Ch. 17 - Define the various regimes of cold working, warm...Ch. 17 - What is an acceptable definition of hot working?...Ch. 17 - What are some of the attractive manufacturing and...Ch. 17 - What are some of the negative aspects of hot...Ch. 17 - Prob. 42RQCh. 17 - Prob. 43RQCh. 17 - If the deformed grains recrystallize during hot...Ch. 17 - Why might a rolled thread offer improved strength...Ch. 17 - How might the temperature of a deforming workpiece...Ch. 17 - Why are heated dies or tools often employed in...Ch. 17 - What generally restricts the upper temperature to...Ch. 17 - What is the primary cause of residual stresses in...Ch. 17 - What is cold working?Ch. 17 - Compared to hot working, what are some of the...Ch. 17 - What are some of the disadvantages of...Ch. 17 - How could cold working be used to reduce the cost...Ch. 17 - Why are cold�forming processes best suited for...Ch. 17 - How can the tensile test properties of a metal be...Ch. 17 - Why is elastic springback an important...Ch. 17 - What is pickling, and how does it remove surface...Ch. 17 - Prob. 58RQCh. 17 - What engineering properties are likely to decline...Ch. 17 - Prob. 60RQCh. 17 - Prob. 61RQCh. 17 - Prob. 62RQCh. 17 - What are some of the advantages of warm forming...Ch. 17 - Prob. 64RQCh. 17 - What material feature is considered to be the...Ch. 17 - Why is isothermal forming considerably more...Ch. 17 - Prob. 67RQCh. 17 - Prob. 1PCh. 17 - Prob. 2PCh. 17 - List and discuss the various economic factors that...Ch. 17 - Prob. 4PCh. 17 - Prob. 5PCh. 17 - Prob. 6PCh. 17 - Prob. 1.1CSCh. 17 - Prob. 1.2CSCh. 17 - Which stainless steel would you recommend? Begin...Ch. 17 - Prob. 1.4CSCh. 17 - Prob. 1.5CSCh. 17 - After drawing and perforating, the residual...Ch. 17 - One of the blades has struck a rock and is badly...Ch. 17 - A second propeller, identical to the one above,...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- 4. Give the dimensions completely of the following figure?arrow_forward2. Consider the picture shown in figure and draw the orthographic projection of the object in first angle projection (in direction of arrow X). ✗ 10 90° 60 60 10 15 40 40arrow_forward5. How are bearings classified? And draw the half sectional view of a ball bearing and indicate the various parts of it. (marks 15)arrow_forward
- 3. The Figure shows the isometric view of a machine component along with the view from above and the view from the left, draw the full sectional view from the front. 56 Draw here the full sectional view 90 40 (a) 32 56 B 32arrow_forwardHow do I solve this task?A spring scale should have a capacity for 10kg. The tension spring is mounted with a weight that is a preload in the spring. Choose a spring with a maximum load of 50mm. What distance should the kg weight be and what the preload weight should weigh.F=Fo+c·fFo= preload weight (N)F=10·9.81 → F=98.1 N Trying with a spring 3823f=F- Fo /c → 98.1-9/1.090=81.74 mmarrow_forwardA gearbox consists of four gears. Dimension the gearbox for a gear ratio of 18:1. The gear ratio should be as even as possible. In the first stage, module 4, in the second stage module 5. All shafts are in the same plane. Calculate the distance between Da. Da=45mm Db=40mmu=ωin/ ωout= nin/ nout= dout/ din= Mout/ Min= Zout/ Zind=m·z)da=m·(z+2) (top diameters)df=m·(z-2.5) (bottom diameters)tooth limits z1 z2 13 13-16 14 14-26 15 15-45 16 16-101 17 17-1314 18 18- .......arrow_forward
- Question 2 a) Construct the signal flow graph (SFG) for the block diagram shown in Fig. Q2 (a) and C($) obtain the gain using Mason's formula. R(s) 04 -R() 01 0₂ 0 Hi h Sinded States Text Predictions On Accessibility Unavailable Fig. Q2 (a) H₂ CAarrow_forwardHow do you solve for the force acting on member BC?arrow_forwardA brake jaw, A is pressed against the drum, B. Calculate the brake arm, X(m₂).F= 250NBraking torque = 30Nmµ=0.35Around point A:Fm₂-Nm₁-µm₃=0N=Fm₂/m1+ µm₃MBrake =µ·D/2= µ·D/2MBrake =Fµm₂D/2(m₁- µm₃)(X)m₂=FµD/Mbrake·2(m1- µm₃)(X)m₂=250·0.35.0.3/30·2(0.250-0.35·0.06)=?I don’t get some likely value?arrow_forward
- Q7 (12 Marks) For the system shown in Fig.3: 1- Draw the overall block diagram. 2- Determine the transfer function (Pc(s)/E(s)). Orifice→ Ps Actuating error signs) Flapper Pb+Pb. Nozzle. A X+X+ Ri A I R2 ㅍ think +y Pc+PCarrow_forwardFigures 4: show a pneumatic controller. The pneumatic relay has the characteristic that pc=K pb , where K>0. What kind of control action does this controller produce? a. Derive the mathematical model for the system b. Derive the transfer function Pc(s)/E(s) -Solve step by step Orifice F+Ph R₁ Actuating error signal Flapper Nozzle. x+x F+Pe thinkarrow_forwardThe equation of the turning moment diagram for the three crank engine and the equation of the moment required by a machine connected to this engine are given below: Engine Torque Machine Torque T=10000-500 sin (40) T=10000+2000 sin (20) N.m N.m where radians is the crank angle from inner dead center and the mean engine speed is 300 rpm. It is required to select a proper flywheel (find the moment of inertia of the flywheel in kgm2) and then calculate the power of the engine if the total percentage fluctuation of speed of the flywheel is ±1% of the mean speed. Calculate the angular acceleration of the flywheel when angle is 45°.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Welding: Principles and Applications (MindTap Cou...Mechanical EngineeringISBN:9781305494695Author:Larry JeffusPublisher:Cengage Learning
Welding: Principles and Applications (MindTap Cou...
Mechanical Engineering
ISBN:9781305494695
Author:Larry Jeffus
Publisher:Cengage Learning
Heat Transfer [Conduction, Convection, and Radiation]; Author: Mike Sammartano;https://www.youtube.com/watch?v=kNZi12OV9Xc;License: Standard youtube license