Principles of Geotechnical Engineering (MindTap Course List)
9th Edition
ISBN: 9781305970939
Author: Braja M. Das, Khaled Sobhan
Publisher: Cengage Learning
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Chapter 17, Problem 17.3P
To determine
Find the corrected standard penetration numbers
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A standard penetration test is carried out in sand where the efficiency of the hammer nH =70%. If the measured N-value at 30 ft depth is 24, find N60 and (N1)60. The unit weight of the sand is 115.0 lb/ft3. Assume nB = nS = nR =1.
=
A standard penetration test is carried out in sand where the efficiency of the hammer n
50%. If the measured N-value at 7.5 m depth is 20, find Noo and (N₁)60. The unit weight of the sand is
= 15 MR
= 1 and
18.08 kN/m³. Assume ¹
= 0.95. If you know that:
ns
Following are the results of a standard penetration test in sand. Determine the corrected
standard penetration number, (N1)60, at various depths. Note that the water table was not
observed within a depth of 10.5 m below the ground surface. Assume that the average
unit weight of sand is 17.3 kN/m3.
Depth (m) N60
1.5 8
3.0 7
4.6 12
6.0 14
7.5 13
Chapter 17 Solutions
Principles of Geotechnical Engineering (MindTap Course List)
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- b) Table Q2 provides the result of a standard penetration test in the sandy soil. The water table was not encountered during the test. Assume that the average unit weight of sand is 17.3 kN/m³ and use Skempton's relationship provided, determine the corrected standard penetration numbers, (N₁)eo at various depths given (CO1, PO2) (C3) 2 Skempton's equation: C = = 1+0.010! Table Q2 Depth (m) Noo 1.5 3.0 4.5 6.0 7.5 |4712419|arrow_forwardThe following are the results of a standard penetration test in sand. Determine the corrected standard penetration numbers, (N,), at the various depths given. Note that the water table was not observed within a depth of 12 m below the ground surface. Assume that the average unit weight of sand is 15.5 kN/m³. Depth (m) 1.5 8 3 7 4.5 12 14 7.5 13arrow_forwardThe following are the results of a standard penetration test in sand. Determine the standard penetration numbers, (N₁)60(CORR), at the various depths given. Note that the water table is at depth 5.0 m. Assume that the average unit weight of sand is 15.5 kN/m³ above the water table and the saturated unit weight of sand is 17.81 kN/m³, while the unit weight of water = 9.81 kN/m³. Depth (m) 0.0 1.5 3.0 4.5 6.0 7.5 N60 0 10 15 19 24 28arrow_forward
- In a standard penetration test in sands, the blow count measured at 14 m depth was 26. An automatic hammer released by a trip with an efficiency of 70% was used in the test. The unit weight of sand is 17.5 kN/m³. Determine: (a) N60 (N1) 60 using Peck, Hanson, and Thornburn (1974) correlation with Pa = 100 kPa. The most likely value of the friction angle (not the range). The possible range of relative density per Peck et al. (1974) The Young's Modulus. The table below presents two correlations proposed for estimating Young's Modulus. kg Leonards (1986) E .cm² E (kPa): = 8N60 = aPa (kPa)N60 Kulhawy & Mayne (1990) In the table a = 5 for fine sands, 10 for clean normally consolidated sands, and 15 for clean over consolidated sands. If a specific method is not specified, you may use any possible correlations. While doing so, you must clearly indicate which correlation was used.arrow_forward3. Following are the results of a standard penetration test in fine dry sand. N60 Depth (m) 1.5 7 13 3.0 18 4.5 22 6.0 7.5 24 For, the sand deposit, assume the mean grain size, D50, to be 0.26 mm and the unit weight of sand to be 15.5kN/m3. Estimate the variation of relative density with depth using the correlation developed by Cubrinovski and Ishihara. Assume pas100kN/m2. denined frictionarrow_forwardA standard penetration test is carried out in clay where the efficiency of the hammer n 80%. If the measured N-value at 10 m depth is 24, find the corrected value of number of blows to be used for other calculations. The unit weight of the clay is 19.5 kN/m³. Assume ng = 1 and ns = 1 R = 1.arrow_forward
- Solve only if you are 100 % sure, else allow other experts to do , otherwise i will downvote The following series of standard penetration test (SPT) results was obtained in an 18-ft thick stratum of relatively uniform silty sand:arrow_forwardFollowing is the variation of the field standard penetration number (N60) in a sand deposit: The groundwater table is located at a depth of 6 m. Given: the dry unit weight of sand from 0 to a depth of 6 m is 18 kN/m3, and the saturated unit weight of sand for depth 6 to 12 m is 20.2 kN/m3. Use the relationship given in Eq. (3.13) to calculate the corrected penetration numbers.arrow_forwardA drilled shaft constructed in medium sand is shown in the figure below. Given information is: y = 18 kN/m', '= 38°. Sand is medium-density sand, and the average standard penetration number (N60) within 2Ds below the drilled shaft is 19. Using the method proposed by Reese and O'Neill, determine the following: (a) The net allowable point resistance for a base movement of 25 mm. (b) The shaft frictional resistance for a base movement of 25 mm. (c) The total load that can be carried by the drilled shaft for a total base movement of 25 mm. 1 m 11 m 12 m - 2 marrow_forward
- The standard penetration test results of a sand deposit at a certain site are given below in tabular form. The groundwater table in located at a depth of 2 m below the ground surface. The dry and saturated unit weights of sand are 17 kN/m³ and 19.0 kN/m', respectively. For an expected 10.8 earthquake magnitude M = 6 and maximum acceleration amax = 0.1 g, will liquefaction occur? Depth (m) NF (blows/30 cm) 1.5 8 3.0 7 4.5 12 6.0 15 7.5 17 9.0 17arrow_forwardIn a deposit of normally consolidated dry sand a cone penetration test was conducted. Following are the result: Depth(m) Point resistance of cone, qc (MN/m²) 1.5 2.06 3.0 4.23 4.5 6.01 6.0 8.18 7.5 9.97 9.0 12.42 Assuming the dry unit weight of sand to be 16kN/m³, estimale the average peak friction angle, ф’, fo the sand. Use ф’=tan ¯1((0.38+0.27log(qc/ σ’o))arrow_forward(1) A well is drilling to the depth of 6000 m. Formation pore pressure can be expressed in equivalent mud weight is 1.50 g/cm' at the depth and changes in proportion to well depth. Also, overburden pressure gradient is 0.0245 MPa/m. Calculate: a. Pore pressure gradient at 6000 m, MPa/m. b.Pore pressure, psi, at 6000 m. c. Matrix stress gradient, MPa/m d.Matrix stress at 6000 m, MPaarrow_forward
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